Gear Ratio Calculator
Calculate gear ratio accurately for your build. Get material quantities, waste allowances, and project cost breakdowns.
Gear Ratio Calculator
Calculator
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Formula: Gear Ratio = Driven Teeth / Driving Teeth | Output RPM = Input RPM / Ratio | Output Torque = Input Torque ร Ratio ร ฮท
Worked example โ Ratio = 5:1 | Output = 350 RPM | Torque = 47.5 Nยทm | 2.46HP
Formula
Gear Ratio = Driven Teeth / Driving Teeth | Output RPM = Input RPM / Ratio | Output Torque = Input Torque ร Ratio ร ฮท
The gear ratio equals the number of teeth on the driven gear divided by the driving gear teeth. Output RPM is inversely proportional to the ratio, while output torque is directly proportional (multiplied by the efficiency factor ฮท). Power is conserved minus friction losses.
Worked Examples
Example 1: Motor Speed Reduction
Problem:A 1750 RPM motor with a 15-tooth pinion drives a 75-tooth gear. The motor produces 10 Nยทm of torque. Calculate outputs at 95% efficiency.
Solution:Gear Ratio = 75/15 = 5:1 Output RPM = 1750 / 5 = 350 RPM Output Torque = 10 ร 5 ร 0.95 = 47.5 Nยทm Input Power = 10 ร 1750 ร 2ฯ/60 = 1,832.6W = 2.46HP Output Power = 1,832.6 ร 0.95 = 1,740.9W
Result:Ratio = 5:1 | Output = 350 RPM | Torque = 47.5 Nยทm | 2.46HP
Example 2: Bicycle Gear Analysis
Problem:A bicycle has a 44-tooth chainring driving a 16-tooth rear sprocket. The cyclist pedals at 80 RPM with 40 Nยทm of torque.
Solution:Gear Ratio = 16/44 = 0.364 (speed increase) Output RPM = 80 / 0.364 = 220 RPM (wheel turns faster) Output Torque = 40 ร 0.364 ร 0.97 = 14.1 Nยทm This is a speed-increasing setup (ratio < 1) Wheel turns 2.75ร faster than pedals
Result:Ratio = 0.364:1 | Wheel = 220 RPM | Torque = 14.1 Nยทm
Frequently Asked Questions
What is a gear ratio?
A gear ratio is the relationship between the number of teeth on two meshing gears, expressed as the ratio of driven gear teeth to driving gear teeth. It determines how speed and torque are transferred between gears. A gear ratio greater than 1 means speed reduction and torque multiplication (the output shaft turns slower but with more force). A gear ratio less than 1 means speed increase and torque reduction. For example, a 60-tooth driven gear meshing with a 20-tooth driving gear gives a 3:1 ratio, meaning the output turns 3 times slower but with 3 times the torque.
How does gear ratio affect torque and speed?
Gear ratio creates an inverse relationship between speed and torque: Speed reduction = torque multiplication, and speed increase = torque reduction. Output RPM = Input RPM / Gear Ratio. Output Torque = Input Torque x Gear Ratio x Efficiency. In an ideal (100% efficient) system, power is conserved: P = Torque x RPM. In reality, friction losses reduce efficiency to typically 95-98% per gear stage. This trade-off is fundamental to mechanical design, allowing engineers to match motor characteristics to load requirements.
What is mechanical advantage in gears?
Mechanical advantage (MA) in gears equals the gear ratio for a simple gear pair. It represents the factor by which the input force (torque) is multiplied. An MA of 3 means the output torque is 3 times the input torque (minus friction losses). In compound gear trains (multiple stages), the overall MA is the product of individual stage ratios. For example, two stages of 3:1 each give an overall MA of 9:1. Mechanical advantage always comes at the cost of speed, as power (P = T x omega) must be conserved.
What is the difference between gear ratio and speed ratio?
Gear ratio and speed ratio are reciprocals of each other. Gear ratio = Driven teeth / Driving teeth = Input speed / Output speed. Speed ratio = Driving teeth / Driven teeth = Output speed / Input speed. For example, if a 20-tooth gear drives a 60-tooth gear: Gear ratio = 60/20 = 3:1 (output is 3x slower), Speed ratio = 20/60 = 1:3 (output is 1/3 the speed). Engineers typically use gear ratio when discussing torque multiplication and speed ratio when discussing velocity changes.
How do I calculate compound gear train ratios?
For a compound gear train (multiple gear pairs on shared shafts), the overall gear ratio is the product of individual pair ratios. For a two-stage train: Total Ratio = (Driven1/Driving1) x (Driven2/Driving2). For example: Stage 1: 20-tooth drives 60-tooth (3:1), Stage 2: 15-tooth drives 45-tooth (3:1). Total ratio = 3 x 3 = 9:1. The output turns 9 times slower with 9 times the torque. Compound trains allow high ratios in compact space. Each stage adds friction losses (typically 2-5% per mesh), so a 3-stage train at 97% per stage has 91.3% overall efficiency.
How does an idler gear change the ratio and the direction of rotation?
An idler sits between driver and driven and meshes with both. Its tooth count appears in the numerator of one mesh and the denominator of the next, so it cancels out and changes neither the overall ratio nor the torque. What it changes is direction and layout: every external mesh reverses rotation, so a single idler makes input and output shafts turn the same way, and it bridges a long centre distance without needing one oversized gear.
What are module and diametral pitch, and why must meshing gears share them?
Module m is the pitch diameter divided by the number of teeth, quoted in millimetres; diametral pitch is the inch-system counterpart, teeth per inch of pitch diameter. Two gears mesh correctly only if they share the same module (or diametral pitch) and the same pressure angle, commonly 20 degrees, since those two values define tooth size and the involute flank profile. Module also fixes the layout, because standard centre distance for an external pair is m x (N1 + N2) / 2.
Why do designers favour a hunting tooth ratio over a round one?
A hunting ratio is one whose tooth counts share no common factor, so their greatest common divisor is 1. When the counts do share a factor, the same tooth pairs re-meet every few revolutions and a burr or hard spot repeatedly attacks the same partner teeth. With a hunting ratio each tooth eventually meets every tooth on the mating gear, spreading run-in and wear evenly. That is why 21 and 61 teeth are often chosen instead of a tidy 20 and 60.
How does an epicyclic (planetary) gear set differ from a simple external pair?
An epicyclic set has a central sun gear, planet gears carried on a rotating carrier, and an outer ring or annulus. Any of the three members can be input, output or held stationary, so one set of tooth counts yields several ratios. With the ring held and the sun driving the carrier, the reduction is 1 + Nring/Nsun. Torque splits across several planet meshes, giving more capacity in a given diameter while keeping input and output shafts coaxial.
Which gear type should I choose, and how does that change the efficiency figure?
Gear type largely sets the efficiency you enter here. A well-lubricated spur or helical mesh usually runs in the high nineties per stage, so even a multi-stage train keeps most of its input power. Helical teeth engage gradually and run quieter but push axial thrust into the bearings. Bevel gears turn the drive through an angle. Worm drives reach very high single-stage ratios but slide rather than roll, so their efficiency falls sharply at low lead angles and the set can become self-locking.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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