Transformer Calculator
Calculate transformer turns ratio, voltage, current, and efficiency. Determine secondary turns, power losses, and impedance ratio for step-up.
Transformer Calculator
Calculator
Adjust values & calculateEnter your values below. Every result is computed in your browser โ no data is sent to any server.
Formula: Vp/Vs = Np/Ns = Is/Ip
Worked example โ Turns: 2:1 (500:250) | Primary: 4.386A | Secondary: 8.333A | Loss: 52.63W
Formula
Vp/Vs = Np/Ns = Is/Ip
Where Vp and Vs are primary and secondary voltages, Np and Ns are primary and secondary turns, and Ip and Is are primary and secondary currents. For an ideal transformer, power in equals power out: Vp x Ip = Vs x Is.
Worked Examples
Example 1: Residential Step-Down Transformer
Problem:A transformer has 500 primary turns at 240V and needs to output 120V with a 1000W load at 95% efficiency. Calculate secondary turns, currents, and losses.
Solution:Turns Ratio = 240 / 120 = 2:1 Secondary Turns = 500 / 2 = 250 turns Secondary Current = 1000 / 120 = 8.333A Ideal Primary Current = 1000 / 240 = 4.167A Input Power = 1000 / 0.95 = 1052.63W Actual Primary Current = 1052.63 / 240 = 4.386A Power Loss = 1052.63 - 1000 = 52.63W
Result:Turns: 2:1 (500:250) | Primary: 4.386A | Secondary: 8.333A | Loss: 52.63W
Example 2: Industrial Step-Up Transformer
Problem:A step-up transformer converts 120V to 480V with 200 primary turns and a 5000W load at 97% efficiency.
Solution:Turns Ratio = 120 / 480 = 0.25:1 (step-up) Secondary Turns = 200 / 0.25 = 800 turns Secondary Current = 5000 / 480 = 10.417A Input Power = 5000 / 0.97 = 5154.64W Actual Primary Current = 5154.64 / 120 = 42.955A Power Loss = 5154.64 - 5000 = 154.64W Impedance Ratio = 0.25^2 = 0.0625
Result:Turns: 0.25:1 (200:800) | Primary: 42.96A | Secondary: 10.42A | Loss: 154.64W
Frequently Asked Questions
How does a transformer work and what is the turns ratio?
A transformer works on the principle of electromagnetic induction, transferring electrical energy between two or more windings through a shared magnetic core. The turns ratio is the ratio of the number of turns in the primary winding to the number of turns in the secondary winding, expressed as Np divided by Ns. This ratio directly determines the voltage transformation relationship, where Vp divided by Vs equals Np divided by Ns. A transformer with 1000 primary turns and 500 secondary turns has a turns ratio of 2 to 1, meaning it steps down the voltage by half. The turns ratio is the most fundamental parameter in transformer design and determines whether the transformer steps voltage up or down.
What is the difference between step-up and step-down transformers?
A step-down transformer has more turns on the primary winding than the secondary winding, resulting in a turns ratio greater than one. It reduces voltage from the primary to the secondary side. Common applications include power distribution transformers that step 11kV down to 240V or 120V for household use. A step-up transformer has fewer primary turns than secondary turns, with a turns ratio less than one, increasing voltage at the secondary. Power plants use step-up transformers to raise generator output voltage to hundreds of thousands of volts for efficient long-distance transmission. In both cases, the power relationship is conserved, so when voltage goes up, current proportionally goes down and vice versa.
How do you calculate transformer efficiency and power losses?
Transformer efficiency is calculated as the ratio of output power to input power, expressed as a percentage using the formula Efficiency equals output power divided by input power times 100. Power losses in transformers come from two main sources: copper losses and core losses. Copper losses, also called I-squared-R losses, occur due to the resistance of the winding conductors and increase with the square of the current. Core losses include hysteresis losses from the continuous magnetization and demagnetization of the core material and eddy current losses from circulating currents induced in the core. Modern power transformers typically achieve efficiencies of 95 to 99 percent. Distribution transformers are usually rated at 97 to 99 percent efficiency at full load.
What is impedance ratio and why is it important in transformer design?
The impedance ratio of a transformer equals the square of the turns ratio, expressed as the quantity Np divided by Ns, all squared. This relationship is crucial for impedance matching in electronic circuits, particularly in audio equipment and RF applications. For example, a transformer with a 10 to 1 turns ratio has an impedance ratio of 100 to 1, meaning a 100 ohm load on the secondary appears as a 10,000 ohm impedance on the primary side. Maximum power transfer occurs when the source impedance matches the load impedance. Audio output transformers use this principle to match the high impedance of vacuum tube amplifiers to the low impedance of speakers, ensuring efficient power delivery.
How do you size a transformer for a specific application?
Sizing a transformer requires determining the VA (volt-ampere) rating, which is calculated by multiplying the secondary voltage by the maximum secondary current. For resistive loads, VA equals watts, but for inductive or capacitive loads you must account for the power factor. A motor drawing 10 amps at 120 volts with a power factor of 0.8 requires 1200 VA but only consumes 960 watts. Always add a safety margin of 20 to 25 percent above the calculated VA rating to prevent overheating and ensure reliable operation. Consider ambient temperature conditions since transformers derate at higher temperatures. For applications with significant inrush current like motors, size the transformer to handle the starting current, which can be 5 to 8 times the running current.
Why does supply frequency change what a transformer can do?
The winding voltage follows the EMF equation, in which the RMS voltage equals 4.44 times frequency times turns times peak flux density times core cross-sectional area. For a fixed voltage and fixed turns, peak flux density is therefore inversely proportional to frequency. Running a transformer designed for 60 Hz on a 50 Hz supply at the same voltage raises the working flux density by 20 percent, which can push the core into saturation, causing a large distorted magnetising current, extra heating and audible buzz. The reverse case, a 50 Hz unit on 60 Hz, is generally safe.
What is an isolation transformer used for if the turns ratio is 1:1?
A one-to-one transformer changes no voltage, but it breaks the galvanic connection between source and load, so the secondary has no fixed reference to the supply neutral or earth. That means touching one secondary conductor and ground does not complete a circuit, which is why isolation transformers are used on test benches, in medical equipment and around sensitive instrumentation. They also interrupt ground loops that cause hum, and an electrostatic screen between the windings attenuates common-mode noise coupled from the mains.
Why does a transformer draw a large inrush current when it is first energised?
At the instant of switching the core may already hold residual flux from the previous shutdown, and if the supply is closed at an unfavourable point on the voltage wave the flux demanded adds to that remanence and drives the core deep into saturation. Saturated iron behaves almost like air, so the magnetising current briefly rises to many times the rated current before decaying over several cycles as losses damp it out. Protection must therefore use time-delayed or magnetising-inrush-restrained characteristics rather than instantaneous overcurrent trips.
At what load does a transformer reach its highest efficiency?
Core loss from hysteresis and eddy currents is essentially fixed once the transformer is energised, whereas copper loss rises with the square of the load current. Efficiency peaks at the load fraction where copper loss becomes equal to core loss, which is the square root of core loss divided by full-load copper loss. Distribution transformers are deliberately designed so that this point falls somewhere near 40 to 70 percent of rating, because they spend most of their life at partial load rather than at nameplate.
Why is the measured secondary voltage lower than the ideal turns-ratio value?
The turns ratio gives the induced voltage, but the winding resistance and leakage reactance drop part of it once current flows, so the terminal voltage falls as the load increases. Voltage regulation expresses this as no-load voltage minus full-load voltage, divided by full-load voltage, as a percentage. Lagging power-factor loads make the drop worse because the load current is more nearly in phase with the leakage reactance drop. Transformer Calculator assumes the ideal relationship, so expect a few percent of droop in a real unit at full load.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
Related Calculators
๐งฎTransformer Turns Ratio Calculator
Calculate transformer turns ratio with inputs, formulas, and instant results.
๐งฎCantilever Retaining Wall Calculator
Calculate cantilever retaining wall with inputs, formulas, and instant results.
๐งฎOpen Channel Manning Calculator
Calculate open channel manning with inputs, formulas, and instant results.
๐งฎPipe Flow Darcy Weisbach Calculator
Calculate pipe flow darcy weisbach with inputs, formulas, and instant results.
๐งฎRoad Superelevation Calculator
Calculate road superelevation with inputs, formulas, and instant results.
๐งฎRlccircuit Impedance Calculator
Calculate rlccircuit impedance with inputs, formulas, and instant results.
๐งฎThree Phase Power Calculator
Calculate three phase power with inputs, formulas, and instant results.
๐งฎVoltage Divider Calculator
Calculate voltage divider with inputs, formulas, and instant results.