Three Phase Power Calculator
Calculate three-phase real power (kW), apparent power (kVA), and reactive power (kVAR) for star and delta connections.
Three Phase Power Calculator
Calculator
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Formula: P = โ3 ร VL ร IL ร PF | S = โ3 ร VL ร IL | Q = โ3 ร VL ร IL ร sin(ฯ)
Worked example โ P = 37.6kW | S = 43.2kVA | Q = 21.3kVAR | 50.4HP
Formula
P = โ3 ร VL ร IL ร PF | S = โ3 ร VL ร IL | Q = โ3 ร VL ร IL ร sin(ฯ)
Three-phase power calculations use the square root of 3 (โ1.732) multiplied by line voltage and line current. Real power (P) includes the power factor, apparent power (S) is the total VA, and reactive power (Q) accounts for the phase angle. These formulas apply to both star (Y) and delta (ฮ) connections when using line values.
Worked Examples
Example 1: Industrial Motor Load
Problem:A 480V three-phase motor draws 52A at a power factor of 0.87 in star connection. Calculate all power values.
Solution:VL = 480V, IL = 52A, PF = 0.87 Real Power: P = โ3 ร 480 ร 52 ร 0.87 = 37,598W = 37.6kW Apparent Power: S = โ3 ร 480 ร 52 = 43,217VA = 43.2kVA Reactive Power: Q = โ3 ร 480 ร 52 ร sin(29.5ยฐ) = 21,297VAR = 21.3kVAR Phase Voltage: 480/โ3 = 277.1V Equivalent HP: 37,598 / 745.7 = 50.4HP
Result:P = 37.6kW | S = 43.2kVA | Q = 21.3kVAR | 50.4HP
Example 2: Commercial Building Supply
Problem:A building has a 400V three-phase supply (star) drawing 200A with PF = 0.92. What is the total power consumption?
Solution:VL = 400V, IL = 200A, PF = 0.92 Real Power: P = โ3 ร 400 ร 200 ร 0.92 = 127,435W = 127.4kW Apparent Power: S = โ3 ร 400 ร 200 = 138,564VA = 138.6kVA Reactive Power: Q = โ3 ร 400 ร 200 ร sin(23.1ยฐ) = 54,316VAR = 54.3kVAR Phase Voltage: 400/โ3 = 230.9V
Result:P = 127.4kW | S = 138.6kVA | Q = 54.3kVAR
Frequently Asked Questions
What is three-phase power?
Three-phase power is an electrical power distribution method that uses three alternating currents, each offset by 120 degrees from each other. It is the standard for industrial and commercial power distribution worldwide because it delivers more power than single-phase with the same amount of wire, provides constant power delivery (no zero-crossing dips), is more efficient for motors and large loads, and enables smaller, lighter electrical equipment. Three-phase power is used in factories, data centers, commercial buildings, and for powering motors above about 5 HP.
What is the difference between star (Y) and delta connection?
Star (Y) connection ties one end of each winding to a common neutral point, forming a Y shape. Line voltage = phase voltage x sqrt(3), and line current = phase current. It provides a neutral wire for single-phase loads and is common in distribution systems. Delta connection connects windings end-to-end in a triangle. Line voltage = phase voltage, and line current = phase current x sqrt(3). It has no neutral, provides higher starting torque for motors, and is common in industrial motor connections. Both deliver the same total power when properly designed.
What is power factor and why does it matter?
Power factor (PF) is the ratio of real power (kW) to apparent power (kVA), ranging from 0 to 1. It indicates how effectively electrical power is being used. A power factor of 1.0 (unity) means all power is doing useful work. Low power factor (below 0.85) means more current is needed for the same real power, leading to larger cables, higher losses, utility penalties, and reduced transformer capacity. Common causes of low PF include induction motors (0.7-0.85), fluorescent lighting, and welding equipment. Power factor correction capacitors can improve PF.
How do you calculate three-phase power?
Three-phase power formulas: Real Power (P) = sqrt(3) x VL x IL x PF (in watts). Apparent Power (S) = sqrt(3) x VL x IL (in volt-amps). Reactive Power (Q) = sqrt(3) x VL x IL x sin(phi) (in VAR). Where VL = line-to-line voltage, IL = line current, PF = power factor, and phi = phase angle (arccos of PF). These formulas work for both star and delta connections when using line values. The sqrt(3) factor (approximately 1.732) accounts for the 120-degree phase relationship.
What are common three-phase voltages?
Common three-phase voltages vary by region: In North America: 208V (120V phase), 480V (277V phase), and 600V are standard. In Europe/Asia: 400V (230V phase) is most common, with 690V for larger industrial systems. Medium voltage systems use 4.16kV, 13.8kV, or 34.5kV. The relationship between line and phase voltage depends on the connection type. For star (Y) connections, VL = Vphase x sqrt(3). For delta connections, VL = Vphase.
How are kW, kVA and kVAR related in the power triangle?
Real power P, reactive power Q and apparent power S form a right triangle in which S squared equals P squared plus Q squared, and the angle phi between S and P satisfies cos(phi) equals the power factor. Apparent power is the vector sum, so a 37.6 kW load at 0.87 power factor draws 43.2 kVA and 21.3 kVAR. Transformers, generators and cables are rated in kVA rather than kW because their heating and voltage drop depend on total current, not just the useful component.
How much capacitor kVAR is needed to correct power factor?
The capacitor bank must supply the difference between the existing and target reactive power at constant real power: Qc equals P times the quantity tan(phi1) minus tan(phi2). For a 100 kW load moving from 0.80 to 0.95 power factor, tan(phi1) is 0.750 and tan(phi2) is 0.329, so Qc equals 100 times 0.421, about 42 kVAR. Correcting reduces line current and losses, but over-correction into a leading power factor can cause voltage rise and resonance with system inductance.
What happens to the neutral current when a three-phase load is unbalanced?
In a balanced star-connected load the three line currents are equal and 120 degrees apart, so their phasor sum at the neutral point is zero and the neutral carries nothing. Any imbalance between phases leaves a residual that returns through the neutral conductor. Nonlinear single-phase loads such as switch-mode power supplies make this worse, because third-harmonic currents are in phase in all three legs and add arithmetically in the neutral rather than cancelling. The square-root-of-three formulas assume balance and do not predict this current.
What is the difference between a motor's kW rating and the kVA it draws from the supply?
A motor nameplate states mechanical shaft output, while the supply must furnish that output plus winding, iron and friction losses, and it must also carry magnetising current. Input apparent power equals output kW divided by the product of efficiency and power factor. A 37.3 kW (50 HP) motor at 92 percent efficiency and 0.87 power factor therefore draws about 46.6 kVA, not 37.3. Sizing a transformer or generator from the shaft rating alone consistently undersizes the supply.
How do you find line current when only the load in kW is known?
Rearranging the real power expression gives line current equals P divided by the product of sqrt(3), line voltage and power factor, with P in watts. A 37.6 kW load on a 480 V system at 0.87 power factor draws 37,600 divided by (1.732 times 480 times 0.87), which is about 52 A. This is the figure that sets conductor size, breaker rating and voltage drop, and it rises as power factor falls, which is why a poor power factor forces larger cable for the same useful output.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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