Terrestrial Radiation Budget Calculator
Calculate a planet's radiative equilibrium temperature from the solar constant, albedo, and emissivity using the Stefan-Boltzmann energy balance.
Terrestrial Radiation Budget Calculator
Calculator
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Formula: T = [(S(1-α)) / (4εσ)]^(1/4)
Worked example — Absorbed: 238.2 W/m2 | T: 287.83 K (14.68 C) | Emitted: 238.2 W/m2
Formula
T = [(S(1-α)) / (4εσ)]^(1/4)
Single-layer Stefan-Boltzmann balance for the whole planet: absorbed shortwave equals emitted longwave. Sunlight is intercepted across Earth's circular cross-section but re-radiated from the full sphere, which is where the factor of 4 comes from, so the absorbed flux is S(1−α)/4. With S = 1361 W/m² and α = 0.30 that is 238 W/m². σ = 5.670374×10⁻⁸ W/m²K⁴. The effective emissivity ε is a lumped index of atmospheric infrared opacity, not a surface material property: ε = 1 gives the bare-rock 254.6 K, while ε ≈ 0.612 reproduces the observed 288 K.
Worked Examples
Example 1: Present-Day Earth
Problem:Solar constant S = 1361 W/m2, planetary albedo 0.30, effective emissivity 0.612. Find the absorbed shortwave flux, the equilibrium temperature and the outgoing longwave flux.
Solution:Absorbed = S (1 - a) / 4 = 1361 x 0.70 / 4 = 952.7 / 4 = 238.2 W/m2 T = [S(1 - a) / (4 eps sigma)]^(1/4) = [238.2 / (0.612 x 5.6704e-8)]^(1/4) 0.612 x 5.6704e-8 = 3.4703e-8, and 238.2 / 3.4703e-8 = 6.8633e9 T = (6.8633e9)^(1/4) = 287.83 K, i.e. 14.68 C Outgoing longwave = eps sigma T^4 = 3.4703e-8 x 287.83^4 = 238.2 W/m2, equal to the absorbed flux as the balance requires.
Result:Absorbed: 238.2 W/m2 | T: 287.83 K (14.68 C) | Emitted: 238.2 W/m2
Example 2: Bare-Rock Earth With No Greenhouse Effect
Problem:Set the effective emissivity to 1.0, removing the atmosphere's infrared opacity while keeping S = 1361 W/m2 and albedo 0.30. How cold would Earth be?
Solution:Absorbed is unchanged at 238.2 W/m2 T = (238.2 / 5.6704e-8)^(1/4) = (4.2003e9)^(1/4) = 254.58 K, i.e. -18.57 C Greenhouse warming = 287.83 - 254.58 = 33.25 K This is the origin of the widely quoted 33 K figure: it is the gap between the observed mean surface temperature and the temperature a body with the same albedo and no infrared-opaque atmosphere would hold.
Result:T: 254.58 K (-18.57 C) | Greenhouse warming accounts for 33.25 K
Example 3: Ice-Free Earth: Albedo Falls to 0.25
Problem:Keep S = 1361 W/m2 and emissivity 0.612 but lower the albedo from 0.30 to 0.25, as would follow from a large loss of snow and sea ice. How much does the surface warm?
Solution:New absorbed flux = 1361 x 0.75 / 4 = 255.2 W/m2, an extra 17.0 W/m2 T = (255.2 / 3.4703e-8)^(1/4) = (7.3533e9)^(1/4) = 292.84 K Warming = 292.84 - 287.83 = 5.01 K That is a very large response for a 0.05 change in albedo, and it is why the ice-albedo feedback is treated as one of the strongest amplifiers in the climate system. Note that the model holds emissivity fixed, so it captures none of the water-vapour or cloud feedbacks that would accompany such a change.
Result:Absorbed rises to 255.2 W/m2 | T: 292.84 K | Warming: 5.01 K
Frequently Asked Questions
What is the Earth's radiation budget?
Earth absorbs ~240 W/m² of solar radiation and emits ~240 W/m² of longwave radiation. The greenhouse effect warms the surface by ~33°C above the bare-rock equilibrium of 255 K.
Why is Earth's albedo approximately 0.30?
Earth's planetary albedo of about 0.30 (30% reflectivity) results from contributions of clouds (~20%), ice and snow surfaces (~4%), and land and ocean surfaces (~6%). Clouds are the dominant factor and their behavior under climate change is a major source of uncertainty in climate projections. Changing any of these components shifts Earth's energy balance and equilibrium temperature.
What is the greenhouse effect and how does emissivity capture it?
The greenhouse effect occurs because atmospheric gases (water vapor, CO₂, methane, ozone) absorb outgoing infrared radiation and re-emit it in all directions, warming the surface. The effective emissivity parameter in Terrestrial Radiation Budget Calculator (default 0.612) is lower than the blackbody value of 1.0, reflecting the atmosphere's partial trapping of outgoing radiation. Without this greenhouse warming, Earth's surface would be approximately -18°C instead of the observed +15°C.
How does increasing CO₂ affect this radiation budget calculation?
Higher CO₂ concentrations reduce the effective emissivity of Earth's atmosphere because more outgoing infrared radiation is absorbed and re-emitted rather than escaping to space. In this simplified model, lowering emissivity from 0.612 to 0.60 raises the equilibrium temperature by about 1.4°C, since T scales as emissivity to the power minus one quarter and (0.612/0.60)^0.25 is about 1.005 applied to 288 K. Real climate sensitivity involves complex feedbacks from water vapor, clouds, ice-albedo, and lapse rate changes that amplify the direct CO₂ forcing.
Why is the solar constant divided by four in this formula?
The planet intercepts sunlight across a disc of area pi R squared, but it radiates infrared from its entire surface, 4 pi R squared. The ratio of those two areas is exactly four, so the globally and diurnally averaged absorbed flux is S(1 - albedo)/4 rather than S(1 - albedo). With S = 1361 W/m2 and an albedo of 0.30 that gives about 238 W/m2. The factor is a geometric consequence of a sphere lit from one side, and it is what makes a global mean energy balance possible in one equation.
How constant is the solar constant?
Total solar irradiance at one astronomical unit averages close to 1361 W/m2, and it varies by only about 0.1 percent across the roughly 11-year sunspot cycle, brighter at solar maximum. The far larger swing is orbital: an eccentricity near 0.0167 moves Earth about plus or minus 1.7 percent about its mean distance, so perihelion in early January and aphelion in early July differ by roughly 3.3 percent. Because flux falls as the inverse square of distance, incident irradiance spans about 7 percent, near 1408 W/m2 at perihelion against 1317 W/m2 at aphelion. That seasonal variation is spread over the whole globe and is not the cause of the seasons.
Where in the atmosphere does the 255 K effective temperature actually apply?
It is the temperature of the level from which infrared radiation escapes to space, not of the ground. Because the troposphere cools upward at a lapse rate of roughly 6.5 K per kilometre, a surface at 288 K reaches 255 K about five kilometres up, which is where the effective emission level sits on average. Adding greenhouse gases raises that level into colder air, so the planet initially emits less than it absorbs and must warm until balance is restored. The effective emissivity term is a compact stand-in for this mechanism.
How do the answers change for Venus, Mars and the Moon?
Only the solar constant and albedo change, and both scale predictably. Venus at 0.723 AU receives about 2600 W/m2 but reflects roughly 77 percent of it, so its effective temperature is near 227 K even though its surface sits close to 737 K, the largest greenhouse effect in the solar system. Mars at 1.524 AU receives about 590 W/m2, and its thin atmosphere adds only a few kelvin above an effective temperature near 210 K. The airless Moon has essentially no greenhouse term at all.
Why does a large change in absorbed energy produce only a small temperature change?
Because emission scales as the fourth power of temperature, the inverse relation is a fourth root, and the fractional temperature response is one quarter of the fractional flux change. A 1 percent increase in absorbed flux therefore raises equilibrium temperature by about 0.25 percent, roughly 0.7 K at 288 K. This strong damping is the Planck response, the fundamental stabilising negative feedback of any planetary climate, and it is the baseline against which amplifying feedbacks such as water vapour and ice-albedo are measured.
Why does this model assume balance when Earth is currently gaining energy?
The equation sets outgoing longwave emission equal to absorbed shortwave by definition, so it can only describe a planet already in equilibrium. In reality the top-of-atmosphere fluxes do not balance: satellite radiometers measure a small persistent surplus, and the excess is stored overwhelmingly in the ocean, whose enormous heat capacity delays surface warming by decades. Any zero-dimensional balance therefore gives the temperature the planet is heading toward under fixed conditions, not the temperature it has now.
References
- NASA CERES - Clouds and the Earth's Radiant Energy System (top-of-atmosphere fluxes)
- NASA Earth Observatory - Climate and Earth's Energy Budget
- IPCC AR6 WG1 Chapter 7 - Earth's Energy Budget, Climate Feedbacks and Climate Sensitivity
- NASA NSSDCA - Planetary Fact Sheets (solar irradiance, albedo, blackbody temperature)
Background & Theory
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Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer · Editorial policy
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