Moles to Grams Converter
Convert moles grams between units instantly. Includes conversion tables, common equivalents, and calculation formulas.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
Grams = Moles x Molar Mass (g/mol)
Multiply the number of moles by the molar mass of the substance (sum of atomic masses in the molecular formula). The result is the mass in grams. To find particles, multiply moles by Avogadro number (6.022e23).
Worked Examples
Example 1: Moles of NaCl to Grams
Problem:How many grams are in 2.5 moles of NaCl (molar mass 58.44 g/mol)?
Solution:Grams = moles x molar mass\nGrams = 2.5 x 58.44 = 146.10 g\nKilograms = 146.10 / 1000 = 0.14610 kg\nParticles = 2.5 x 6.022e23 = 1.506e24
Result:2.5 mol NaCl = 146.10 grams
Example 2: Moles of Glucose to Grams
Problem:Convert 0.5 moles of glucose (C6H12O6, molar mass 180.16 g/mol) to grams.
Solution:Grams = moles x molar mass\nGrams = 0.5 x 180.16 = 90.08 g\nMilligrams = 90.08 x 1000 = 90080 mg\nParticles = 0.5 x 6.022e23 = 3.011e23
Result:0.5 mol glucose = 90.08 grams
Frequently Asked Questions
What is the relationship between moles and grams?
The mole is a counting unit in chemistry representing 6.02214076 times 10 to the 23rd particles (Avogadro number). To convert moles to grams, multiply the number of moles by the molar mass (molecular weight) of the substance in grams per mole. For example, 1 mole of water (H2O) has a molar mass of 18.015 g/mol, so 1 mole weighs 18.015 grams. This relationship is the foundation of stoichiometry in chemistry.
Can you convert grams to moles using Moles to Grams Converter?
Moles to Grams Converter is designed for moles-to-grams conversion, but the reverse calculation is straightforward: divide the mass in grams by the molar mass to get moles. For example, if you have 100 grams of NaCl with a molar mass of 58.44 g/mol, the number of moles is 100 / 58.44 = 1.711 moles. You can verify your reverse calculation by entering 1.711 moles of NaCl into Moles to Grams Converter to confirm you get approximately 100 grams.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy