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Terminal Velocity Calculator

Free Terminal velocity Calculator for mechanics. Enter variables to compute results with formulas and detailed steps. Get results you can export or share.

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Physics

Terminal Velocity Calculator

Calculate terminal velocity for any falling object. Input mass, drag coefficient, cross-sectional area, and air density to find maximum fall speed, time to reach terminal velocity, and drag force.

Last updated: December 2025

Calculator

Adjust values & calculate
80 kg
0.7
0.7 m2
1.225 kg/m3
Terminal Velocity
51.13 m/s
184.1 km/h | 114.4 mph | Mach 0.149
km/h
184.1
mph
114.4
ft/s
167.7
knots
99.4
Weight (N)
784.5
Drag Force at Vt (N)
784.5
Time to 95% Vt
9.6s
Distance to 95% Vt
310 m

Velocity Build-Up

25% Vt (12.8 m/s)
1.33s(9 m)
50% Vt (25.6 m/s)
2.86s(38 m)
75% Vt (38.3 m/s)
5.07s(110 m)
90% Vt (46.0 m/s)
7.68s(221 m)
95% Vt (48.6 m/s)
9.55s(310 m)
99% Vt (50.6 m/s)
13.80s(522 m)
With Parachute (30 m2, Cd=1.5)
Landing speed:5.3 m/s (11.9 mph)
Your Result
Terminal Velocity: 51.13 m/s (184.1 km/h / 114.4 mph) | Mach: 0.149 | Subsonic
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Formula

Vt = sqrt(2mg / (rho x Cd x A))

Terminal velocity equals the square root of (2 times mass times gravitational acceleration) divided by (air density times drag coefficient times cross-sectional area). This is derived by setting gravitational force (mg) equal to drag force (0.5 x rho x Cd x A x V^2) and solving for velocity.

Last reviewed: December 2025

Worked Examples

Example 1: Skydiver in Belly-Down Position

An 80 kg skydiver falls in belly-down position with Cd = 0.7 and cross-sectional area = 0.7 m2 at sea level (air density = 1.225 kg/m3).
Solution:
Vt = sqrt(2 x 80 x 9.81 / (1.225 x 0.7 x 0.7)) Vt = sqrt(1569.6 / 0.60025) Vt = sqrt(2615.1) Vt = 51.14 m/s = 184 km/h = 114 mph Weight = 80 x 9.81 = 784.8 N Drag force at terminal velocity = 784.8 N Time to 95% = (51.14/9.81) x 3.0 = 15.6 seconds Distance to 95% = approx 540 m
Result: Terminal Velocity: 51.14 m/s (184 km/h / 114 mph) | Time to 95%: ~15.6s | Distance: ~540m

Example 2: Golf Ball Free Fall

A golf ball (mass = 0.046 kg, diameter = 42.67mm, Cd = 0.25) falls from a tall building. Calculate terminal velocity at sea level.
Solution:
Area = pi x (0.02134)^2 = 0.001431 m2 Vt = sqrt(2 x 0.046 x 9.81 / (1.225 x 0.25 x 0.001431)) Vt = sqrt(0.9025 / 0.000438) Vt = sqrt(2060.5) Vt = 45.39 m/s = 163 km/h = 101 mph Weight = 0.046 x 9.81 = 0.451 N Mach = 45.39 / 343 = 0.132
Result: Terminal Velocity: 45.39 m/s (163 km/h / 101 mph) | Mach: 0.132 | Subsonic
Expert Insights

Background & Theory

The Terminal Velocity Calculator applies the following established principles and formulas. Physics is the fundamental natural science concerned with matter, energy, and the interactions between them. Classical mechanics, founded on Newton's three laws of motion, provides the framework for analyzing the motion of objects. The first law states that an object remains at rest or in uniform motion unless acted upon by a net external force. The second law quantifies this relationship: F = ma, where force equals mass times acceleration in SI units of newtons (N = kgยทm/sยฒ). The third law establishes that every action produces an equal and opposite reaction. Kinematics describes motion without reference to its causes. The four fundamental equations relate displacement s, initial velocity u, final velocity v, acceleration a, and time t: v = u + at, s = ut + ยฝatยฒ, vยฒ = uยฒ + 2as, and s = ยฝ(u + v)t. These assume constant acceleration and are foundational for solving projectile motion, free fall, and linear dynamics problems. Energy conservation underpins much of physics. Kinetic energy is KE = ยฝmvยฒ, where m is mass in kilograms and v is speed in meters per second. Gravitational potential energy is PE = mgh, where g โ‰ˆ 9.81 m/sยฒ near Earth's surface and h is height in meters. The work-energy theorem states that the net work done on an object equals its change in kinetic energy: W = ฮ”KE. Electricity and circuits rely on Ohm's law: V = IR, where voltage V is in volts, current I in amperes, and resistance R in ohms. Electrical power is P = IV = IยฒR = Vยฒ/R, measured in watts. Wave mechanics connects frequency f, wave speed v, and wavelength ฮป through f = v/ฮป, with frequency in hertz (Hz). Pressure is defined as force per unit area, P = F/A, in pascals (Pa = N/mยฒ). The ideal gas law PV = nRT links pressure, volume, moles n, the gas constant R = 8.314 J/(molยทK), and absolute temperature in kelvin. Gravitational force between two masses follows Newton's law of universal gravitation: F = Gmโ‚mโ‚‚/rยฒ, where G = 6.674ร—10โปยนยน Nยทmยฒ/kgยฒ is the gravitational constant.

History

The history behind the Terminal Velocity Calculator traces back through the following developments. The history of physics spans over two millennia, beginning with the natural philosophy of ancient Greece. Aristotle (384โ€“322 BCE) proposed that all matter consisted of four elements and that objects moved toward their natural place, with heavier objects falling faster than lighter ones. While largely incorrect, his systematic approach to explaining nature dominated Western thought for nearly 2,000 years. The Scientific Revolution overturned Aristotelian physics. Galileo Galilei (1564โ€“1642) performed groundbreaking experiments on inclined planes and falling bodies, demonstrating that all objects fall with the same acceleration regardless of mass, and established the principle of inertia. His use of mathematics to describe motion was revolutionary. Isaac Newton synthesized these developments in his landmark Principia Mathematica (1687), laying out the three laws of motion and the law of universal gravitation. Newton's framework unified terrestrial and celestial mechanics, explaining planetary orbits with the same equations governing a falling apple. His calculus provided the mathematical language for expressing rates of change. The 19th century brought two major theoretical achievements. James Clerk Maxwell formulated his equations of electromagnetism between 1861 and 1862, unifying electricity, magnetism, and optics, and predicting the existence of electromagnetic waves traveling at the speed of light. Thermodynamics was developed by Carnot, Clausius, and Kelvin, establishing the laws governing heat, work, and entropy. The 20th century produced two revolutions that fundamentally altered the classical picture. Albert Einstein published the special theory of relativity in 1905, showing that space and time are not absolute but relative to the observer, and that mass and energy are equivalent via E = mcยฒ. His general theory of relativity in 1915 reinterpreted gravity as the curvature of spacetime. Simultaneously, quantum mechanics emerged from the work of Planck, Bohr, Heisenberg, and Schrรถdinger, revealing that at atomic scales energy is quantized and particles exhibit wave-particle duality. These developments culminated in the Standard Model of particle physics, which describes all known fundamental particles and three of the four fundamental forces.

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Frequently Asked Questions

Terminal velocity is the maximum speed an object reaches when falling through a fluid (like air) when the drag force equals the gravitational force, resulting in zero net acceleration. When you first release an object, gravity accelerates it downward at 9.8 m/s per second. As speed increases, air resistance (drag force) grows proportionally to the square of velocity. At some point, drag exactly balances gravity and the object stops accelerating, falling at a constant speed. This speed is terminal velocity. A skydiver in a belly-down position reaches about 120 mph (195 km/h) after approximately 12 seconds and 450 meters of free fall. The formula is Vt = sqrt(2mg / (rho x Cd x A)), derived from setting the gravitational force equal to the drag force equation.
Four primary factors determine terminal velocity. Mass (or weight) is directly proportional to terminal velocity: heavier objects fall faster because they need more drag force to balance gravity. The drag coefficient depends on the object shape: streamlined shapes like teardrops (Cd = 0.04) have much lower drag than flat plates (Cd = 1.28). Cross-sectional area is the projected area perpendicular to the direction of motion. A skydiver belly-down presents about 0.7 square meters, while head-down presents only 0.3 square meters, dramatically increasing speed. Air density decreases with altitude: at 30,000 feet, air density is roughly 40% of sea level, so terminal velocity is much higher at altitude. This is why Felix Baumgartner exceeded the speed of sound during his stratospheric jump, where air density was extremely low.
A human skydiver has different terminal velocities depending on body position and equipment. In the standard belly-to-earth spread position, terminal velocity is approximately 120 mph (195 km/h or 54 m/s) for an average 80 kg person with a drag coefficient of about 0.7 and cross-sectional area of 0.7 square meters. In a head-down dive position, the reduced area (about 0.3 square meters) and lower drag coefficient (about 0.4) increase terminal velocity to approximately 200 mph (320 km/h). Competitive speed skydivers wearing tight suits in a head-down position can exceed 300 mph (480 km/h). With a deployed parachute (area approximately 30 square meters, Cd approximately 1.5), terminal velocity drops to about 12-18 mph (5-8 m/s), allowing safe landing. Body weight significantly affects speed, with heavier skydivers falling faster.
Air density decreases exponentially with altitude, and since terminal velocity is inversely proportional to the square root of density, objects fall faster at higher altitudes. At sea level, air density is 1.225 kg/m3. At 5,000 meters (16,400 feet), it drops to about 0.736 kg/m3, increasing terminal velocity by roughly 29%. At 10,000 meters (32,800 feet, typical cruising altitude), density is about 0.414 kg/m3, increasing terminal velocity by about 72%. At 39,000 meters (Felix Baumgartner jump altitude), air density is only about 0.004 kg/m3, making terminal velocity roughly 17 times higher than at sea level. This is how Baumgartner reached 833 mph (Mach 1.25) during his fall. As he descended into denser air, drag increased and he naturally decelerated without any action needed. Temperature also affects density: hot air is less dense, slightly increasing terminal velocity on warm days.
The approach to terminal velocity follows a hyperbolic tangent function. The exact equation for velocity as a function of time is v(t) = Vt x tanh(g x t / Vt), where Vt is terminal velocity, g is gravitational acceleration, and t is time. Initially (small t), tanh approximates its argument, so v approximately equals g x t, showing free-fall acceleration as if no drag existed. As t grows large, tanh approaches 1, and velocity asymptotically approaches Vt. The object reaches 50% of terminal velocity in about 0.55 x Vt/g seconds, 90% in about 1.47 x Vt/g seconds, and 95% in about 1.83 x Vt/g seconds. Theoretically, terminal velocity is never exactly reached, only approached asymptotically. For a skydiver with Vt = 54 m/s, reaching 95% (51 m/s) takes about 10 seconds and roughly 350 meters of fall distance. The distance equation involves the natural log of cosh, making analytical solutions possible.
Parachutes reduce terminal velocity by dramatically increasing both the cross-sectional area and drag coefficient. A typical sport parachute has a canopy area of 20-30 square meters (compared to a skydiver body of 0.7 square meters) and a drag coefficient of 1.3-1.5 (compared to 0.7 for a body). Plugging these into the terminal velocity formula, the speed drops from about 54 m/s (120 mph) to about 5-7 m/s (11-16 mph), which is a survivable landing speed. Round parachutes (military style) have higher drag but no forward glide capability. Ram-air rectangular parachutes (sport skydiving) generate lift as well as drag, allowing forward flight at 20-40 mph with controlled descent rates. Drogue chutes (small stabilizing parachutes) are used to reduce speed partially from very high velocities. Parachute deployment timing is critical because opening at too high a speed can damage the canopy or cause injury from the sudden deceleration forces.
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Formula

Vt = sqrt(2mg / (rho x Cd x A))

Terminal velocity equals the square root of (2 times mass times gravitational acceleration) divided by (air density times drag coefficient times cross-sectional area). This is derived by setting gravitational force (mg) equal to drag force (0.5 x rho x Cd x A x V^2) and solving for velocity.

Worked Examples

Example 1: Skydiver in Belly-Down Position

Problem: An 80 kg skydiver falls in belly-down position with Cd = 0.7 and cross-sectional area = 0.7 m2 at sea level (air density = 1.225 kg/m3).

Solution: Vt = sqrt(2 x 80 x 9.81 / (1.225 x 0.7 x 0.7))\nVt = sqrt(1569.6 / 0.60025)\nVt = sqrt(2615.1)\nVt = 51.14 m/s = 184 km/h = 114 mph\nWeight = 80 x 9.81 = 784.8 N\nDrag force at terminal velocity = 784.8 N\nTime to 95% = (51.14/9.81) x 3.0 = 15.6 seconds\nDistance to 95% = approx 540 m

Result: Terminal Velocity: 51.14 m/s (184 km/h / 114 mph) | Time to 95%: ~15.6s | Distance: ~540m

Example 2: Golf Ball Free Fall

Problem: A golf ball (mass = 0.046 kg, diameter = 42.67mm, Cd = 0.25) falls from a tall building. Calculate terminal velocity at sea level.

Solution: Area = pi x (0.02134)^2 = 0.001431 m2\nVt = sqrt(2 x 0.046 x 9.81 / (1.225 x 0.25 x 0.001431))\nVt = sqrt(0.9025 / 0.000438)\nVt = sqrt(2060.5)\nVt = 45.39 m/s = 163 km/h = 101 mph\nWeight = 0.046 x 9.81 = 0.451 N\nMach = 45.39 / 343 = 0.132

Result: Terminal Velocity: 45.39 m/s (163 km/h / 101 mph) | Mach: 0.132 | Subsonic

Frequently Asked Questions

What is terminal velocity and how is it reached?

Terminal velocity is the maximum speed an object reaches when falling through a fluid (like air) when the drag force equals the gravitational force, resulting in zero net acceleration. When you first release an object, gravity accelerates it downward at 9.8 m/s per second. As speed increases, air resistance (drag force) grows proportionally to the square of velocity. At some point, drag exactly balances gravity and the object stops accelerating, falling at a constant speed. This speed is terminal velocity. A skydiver in a belly-down position reaches about 120 mph (195 km/h) after approximately 12 seconds and 450 meters of free fall. The formula is Vt = sqrt(2mg / (rho x Cd x A)), derived from setting the gravitational force equal to the drag force equation.

What factors affect terminal velocity?

Four primary factors determine terminal velocity. Mass (or weight) is directly proportional to terminal velocity: heavier objects fall faster because they need more drag force to balance gravity. The drag coefficient depends on the object shape: streamlined shapes like teardrops (Cd = 0.04) have much lower drag than flat plates (Cd = 1.28). Cross-sectional area is the projected area perpendicular to the direction of motion. A skydiver belly-down presents about 0.7 square meters, while head-down presents only 0.3 square meters, dramatically increasing speed. Air density decreases with altitude: at 30,000 feet, air density is roughly 40% of sea level, so terminal velocity is much higher at altitude. This is why Felix Baumgartner exceeded the speed of sound during his stratospheric jump, where air density was extremely low.

What is the terminal velocity of a human body?

A human skydiver has different terminal velocities depending on body position and equipment. In the standard belly-to-earth spread position, terminal velocity is approximately 120 mph (195 km/h or 54 m/s) for an average 80 kg person with a drag coefficient of about 0.7 and cross-sectional area of 0.7 square meters. In a head-down dive position, the reduced area (about 0.3 square meters) and lower drag coefficient (about 0.4) increase terminal velocity to approximately 200 mph (320 km/h). Competitive speed skydivers wearing tight suits in a head-down position can exceed 300 mph (480 km/h). With a deployed parachute (area approximately 30 square meters, Cd approximately 1.5), terminal velocity drops to about 12-18 mph (5-8 m/s), allowing safe landing. Body weight significantly affects speed, with heavier skydivers falling faster.

How does altitude and air density affect terminal velocity?

Air density decreases exponentially with altitude, and since terminal velocity is inversely proportional to the square root of density, objects fall faster at higher altitudes. At sea level, air density is 1.225 kg/m3. At 5,000 meters (16,400 feet), it drops to about 0.736 kg/m3, increasing terminal velocity by roughly 29%. At 10,000 meters (32,800 feet, typical cruising altitude), density is about 0.414 kg/m3, increasing terminal velocity by about 72%. At 39,000 meters (Felix Baumgartner jump altitude), air density is only about 0.004 kg/m3, making terminal velocity roughly 17 times higher than at sea level. This is how Baumgartner reached 833 mph (Mach 1.25) during his fall. As he descended into denser air, drag increased and he naturally decelerated without any action needed. Temperature also affects density: hot air is less dense, slightly increasing terminal velocity on warm days.

What is the physics behind reaching terminal velocity?

The approach to terminal velocity follows a hyperbolic tangent function. The exact equation for velocity as a function of time is v(t) = Vt x tanh(g x t / Vt), where Vt is terminal velocity, g is gravitational acceleration, and t is time. Initially (small t), tanh approximates its argument, so v approximately equals g x t, showing free-fall acceleration as if no drag existed. As t grows large, tanh approaches 1, and velocity asymptotically approaches Vt. The object reaches 50% of terminal velocity in about 0.55 x Vt/g seconds, 90% in about 1.47 x Vt/g seconds, and 95% in about 1.83 x Vt/g seconds. Theoretically, terminal velocity is never exactly reached, only approached asymptotically. For a skydiver with Vt = 54 m/s, reaching 95% (51 m/s) takes about 10 seconds and roughly 350 meters of fall distance. The distance equation involves the natural log of cosh, making analytical solutions possible.

How do parachutes work to reduce terminal velocity?

Parachutes reduce terminal velocity by dramatically increasing both the cross-sectional area and drag coefficient. A typical sport parachute has a canopy area of 20-30 square meters (compared to a skydiver body of 0.7 square meters) and a drag coefficient of 1.3-1.5 (compared to 0.7 for a body). Plugging these into the terminal velocity formula, the speed drops from about 54 m/s (120 mph) to about 5-7 m/s (11-16 mph), which is a survivable landing speed. Round parachutes (military style) have higher drag but no forward glide capability. Ram-air rectangular parachutes (sport skydiving) generate lift as well as drag, allowing forward flight at 20-40 mph with controlled descent rates. Drogue chutes (small stabilizing parachutes) are used to reduce speed partially from very high velocities. Parachute deployment timing is critical because opening at too high a speed can damage the canopy or cause injury from the sudden deceleration forces.

References

Reviewed by Manoj Kumar, Mathematics Educator ยท Editorial policy