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Half Angle Calculator

Calculate half angle instantly with our math tool. Shows detailed work, formulas used, and multiple solution methods. Get results you can export or share.

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Mathematics

Half Angle Calculator

Calculate half angle values using trigonometric half angle formulas. Compute sin(A/2), cos(A/2), and tan(A/2) from any angle with automatic sign determination and verification.

Last updated: December 2025Reviewed by NovaCalculator Mathematics Team

Calculator

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Half Angle: 60.0000 / 2 = 30.0000 degrees
30.0000 degrees
Quadrant 1 | 0.523599 radians

Half Angle Results

sin(30.0000)
sqrt((1 - cos(60.0000))/2)
0.50000000
Verified
cos(30.0000)
sqrt((1 + cos(60.0000))/2)
0.86602540
Verified
tan(30.0000)
sin(A)/(1 + cos(A))
0.57735027
Verified
sec(A/2)
1.15470054
csc(A/2)
2.00000000
cot(A/2)
1.73205081

Tangent Half Angle Formulas Comparison

sin(A) / (1 + cos(A))0.57735027
(1 - cos(A)) / sin(A)0.57735027
Direct: tan(30.0000)0.57735027
Your Result
sin(30.0000) = 0.50000000 | cos(30.0000) = 0.86602540 | tan(30.0000) = 0.57735027
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Formula

sin(A/2) = +/-sqrt((1-cosA)/2), cos(A/2) = +/-sqrt((1+cosA)/2), tan(A/2) = sinA/(1+cosA)

The half angle formulas express trig functions of A/2 in terms of cos(A). The sign depends on which quadrant A/2 falls in. The tangent formula avoids square roots and determines sign automatically.

Last reviewed: December 2025

Worked Examples

Example 1: Half Angle of 60 Degrees

Calculate sin(30), cos(30), and tan(30) using half angle formulas with A = 60 degrees.
Solution:
cos(60) = 0.5 sin(30) = sqrt((1 - cos(60))/2) = sqrt((1 - 0.5)/2) = sqrt(0.25) = 0.5 cos(30) = sqrt((1 + cos(60))/2) = sqrt((1 + 0.5)/2) = sqrt(0.75) = 0.86602540 tan(30) = sin(60)/(1 + cos(60)) = 0.86602540/1.5 = 0.57735027 All positive since 30 degrees is in Q1. Verification: sin(30) = 0.5, cos(30) = 0.86602540, tan(30) = 0.57735027 (all confirmed)
Result: sin(30) = 0.5 | cos(30) = 0.86602540 | tan(30) = 0.57735027

Example 2: Half Angle of 270 Degrees

Find sin(135), cos(135), tan(135) using half angle formulas with A = 270 degrees.
Solution:
cos(270) = 0 A/2 = 135 degrees (Quadrant II: sin positive, cos negative) sin(135) = +sqrt((1 - 0)/2) = +sqrt(0.5) = 0.70710678 cos(135) = -sqrt((1 + 0)/2) = -sqrt(0.5) = -0.70710678 tan(135) = sin(270)/(1 + cos(270)) = -1/1 = -1.0 Verification: sin(135) = 0.70710678, cos(135) = -0.70710678, tan(135) = -1.0 (confirmed)
Result: sin(135) = 0.70710678 | cos(135) = -0.70710678 | tan(135) = -1.0
Expert Insights

Background & Theory

The Half Angle Calculator applies the following established principles and formulas. Mathematics rests on a hierarchy of number systems, each extending the previous. The natural numbers (1, 2, 3, ...) support counting and ordering. The integers add negative values and zero, enabling subtraction without restriction. The rational numbers, expressible as p/q where p and q are integers and q is nonzero, close the system under division. The real numbers fill the gaps left by irrationals such as the square root of 2 or pi, forming a complete ordered field. The complex numbers, written as a + bi where i is the square root of negative one, complete the algebraic closure of the reals and allow every polynomial to have a root. Prime factorization states that every integer greater than one is uniquely expressible as a product of primes, a result known as the Fundamental Theorem of Arithmetic. Computing the greatest common divisor (GCD) of two integers relies most efficiently on the Euclidean algorithm: repeatedly replace the larger number with the remainder when it is divided by the smaller, until the remainder is zero. The last nonzero remainder is the GCD. The least common multiple (LCM) follows from the identity LCM(a, b) = |a * b| / GCD(a, b). Modular arithmetic defines equivalence classes of integers that share the same remainder under division by a modulus n. Fermat's Little Theorem and Euler's Theorem arise from this structure and underpin modern cryptography. Logarithms are the inverses of exponential functions. If b raised to the power x equals y, then the logarithm base b of y equals x. The natural logarithm uses base e, approximately 2.71828. Combinatorics counts arrangements and selections. The number of ordered arrangements (permutations) of r objects from n distinct objects is nPr = n! / (n - r)!. The number of unordered selections (combinations) is nCr = n! / (r! * (n - r)!). Pascal's triangle arranges these binomial coefficients so that each entry equals the sum of the two entries directly above it. The Fibonacci sequence, defined by F(1) = 1, F(2) = 1, and F(n) = F(n-1) + F(n-2), appears throughout nature and connects deeply to the golden ratio via Binet's formula.

History

The history behind the Half Angle Calculator traces back through the following developments. Mathematics as a systematic discipline traces to ancient Mesopotamia. Babylonian clay tablets dating to around 1800 BCE demonstrate knowledge of quadratic equations, Pythagorean triples, and base-60 arithmetic, suggesting a practical mathematical tradition far preceding Greek formalism. Euclid of Alexandria compiled the Elements around 300 BCE, establishing the axiomatic method that would define rigorous mathematics for over two thousand years. His work organized plane geometry, number theory, and proportion into logically chained propositions derived from a small set of postulates. The algorithm bearing his name for computing GCDs appears in Book VII and remains in use today. In the 9th century, the Persian scholar Muhammad ibn Musa Al-Khwarizmi wrote Al-Kitab al-mukhtasar fi hisab al-jabr wal-muqabala, the treatise whose title gave algebra its name. He systematized the solution of linear and quadratic equations and described procedures that operated on unknowns as objects, a conceptual leap away from purely numerical calculation. Rene Descartes introduced coordinate geometry in 1637 by uniting algebra and Euclidean geometry, allowing curves to be studied through equations. This synthesis set the stage for calculus. Isaac Newton and Gottfried Wilhelm Leibniz independently developed calculus during the 1660s and 1670s, triggering a priority dispute that lasted decades and divided British and Continental mathematicians. Carl Friedrich Gauss proved the Fundamental Theorem of Algebra in 1799, showing that every nonconstant polynomial has at least one complex root. His Disquisitiones Arithmeticae of 1801 established modern number theory. David Hilbert's formalist program at the turn of the 20th century sought to place all of mathematics on an explicit axiomatic foundation, a project that Kurt Godel's incompleteness theorems of 1931 showed to be fundamentally limited. Alan Turing's work in the 1930s on computability introduced the theoretical model of the stored-program computer and linked mathematical logic directly to the limits of algorithmic calculation. His proof that no algorithm can decide in general whether an arbitrary program will halt or run forever placed fundamental boundaries on what mathematics can mechanically determine, and it opened the discipline now known as theoretical computer science.

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Frequently Asked Questions

The half angle formulas express trigonometric functions of half an angle in terms of the cosine of the full angle. The three primary formulas are: sin(A/2) = plus or minus sqrt((1 - cos(A))/2), cos(A/2) = plus or minus sqrt((1 + cos(A))/2), and tan(A/2) = sin(A)/(1 + cos(A)) = (1 - cos(A))/sin(A). The plus or minus sign for sine and cosine depends on the quadrant in which A/2 falls. These formulas are derived from the double angle formulas by solving for the half-angle function. They are particularly useful in calculus for evaluating integrals involving square roots of trigonometric expressions and in deriving the Weierstrass substitution.
The half angle formulas are derived by rearranging the double angle cosine formulas. Starting with cos(2B) = 1 - 2sin2(B), solve for sin(B): sin2(B) = (1 - cos(2B))/2, so sin(B) = plus or minus sqrt((1 - cos(2B))/2). Now substitute B = A/2: sin(A/2) = plus or minus sqrt((1 - cos(A))/2). Similarly, from cos(2B) = 2cos2(B) - 1, solve for cos(B): cos2(B) = (1 + cos(2B))/2, giving cos(A/2) = plus or minus sqrt((1 + cos(A))/2). The tangent half angle formula tan(A/2) = sin(A)/(1 + cos(A)) avoids the square root by using the identity tan(A/2) = sin(A/2)/cos(A/2) and algebraic manipulation.
The sign (positive or negative) in the half angle formulas for sine and cosine depends on the quadrant in which the half angle A/2 falls, not the quadrant of A itself. If A/2 is in the first or second quadrant (0 to 180 degrees), sin(A/2) is positive. If A/2 is in the first or fourth quadrant (0 to 90 or 270 to 360 degrees), cos(A/2) is positive. For example, if A = 300 degrees, then A/2 = 150 degrees which is in the second quadrant. Therefore sin(150) is positive and cos(150) is negative. The tangent half angle formulas using sin(A)/(1+cos(A)) or (1-cos(A))/sin(A) automatically give the correct sign without needing to determine the quadrant separately.
The Weierstrass substitution (also called the tangent half-angle substitution) is a powerful calculus technique that converts trigonometric integrals into rational function integrals. You set t = tan(x/2), then use the half angle identities to express: sin(x) = 2t/(1+t2), cos(x) = (1-t2)/(1+t2), and dx = 2/(1+t2) dt. This transforms any rational function of sin(x) and cos(x) into a rational function of t, which can be integrated using partial fractions. While not always the most efficient method, the Weierstrass substitution is universal and guaranteed to work for any rational trigonometric integral. It was developed by Karl Weierstrass in the 19th century and remains a standard technique in calculus courses.
Half angle formulas have important applications across mathematics and engineering. In calculus, they enable the power reduction technique: sin2(x) = (1 - cos(2x))/2 and cos2(x) = (1 + cos(2x))/2, which are essential for integrating even powers of sine and cosine. In physics, half angle formulas appear in the analysis of optical systems, specifically in calculations involving prism refraction and thin film interference patterns. In electrical engineering, they help simplify AC circuit analysis when dealing with rectified waveforms. In computer graphics, half angle vectors are used in specular reflection calculations (Blinn-Phong shading model). In surveying and navigation, half angle formulas appear in the haversine formula for calculating great circle distances.
Half angle formulas allow you to find exact values of trigonometric functions for angles that are half of known standard angles. For example, to find the exact value of sin(15 degrees), use sin(30/2) = sqrt((1 - cos(30))/2) = sqrt((1 - sqrt(3)/2)/2) = sqrt((2 - sqrt(3))/4). This gives an exact radical expression rather than a decimal approximation. Similarly, cos(22.5 degrees) = sqrt((1 + cos(45))/2) = sqrt((1 + sqrt(2)/2)/2) = sqrt((2 + sqrt(2))/4). By repeatedly applying half angle formulas, you can find exact values for angles like 7.5 degrees, 3.75 degrees, and so on. This technique is valuable in pure mathematics where exact symbolic expressions are preferred over numerical approximations.
Educational Note: This calculator is provided for educational and informational purposes. Results are based on the formulas and inputs provided. Always verify important calculations independently. NovaCalculator processes calculator inputs client-side; optional analytics follow visitor consent settings.Reviewed by: NovaCalculator Mathematics Team โ€” Verified against standard mathematical and scientific references. Last reviewed: December 2025. ยฉ 2024โ€“2026 NovaCalculator.

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Formula

sin(A/2) = +/-sqrt((1-cosA)/2), cos(A/2) = +/-sqrt((1+cosA)/2), tan(A/2) = sinA/(1+cosA)

The half angle formulas express trig functions of A/2 in terms of cos(A). The sign depends on which quadrant A/2 falls in. The tangent formula avoids square roots and determines sign automatically.

Worked Examples

Example 1: Half Angle of 60 Degrees

Problem: Calculate sin(30), cos(30), and tan(30) using half angle formulas with A = 60 degrees.

Solution: cos(60) = 0.5\nsin(30) = sqrt((1 - cos(60))/2) = sqrt((1 - 0.5)/2) = sqrt(0.25) = 0.5\ncos(30) = sqrt((1 + cos(60))/2) = sqrt((1 + 0.5)/2) = sqrt(0.75) = 0.86602540\ntan(30) = sin(60)/(1 + cos(60)) = 0.86602540/1.5 = 0.57735027\nAll positive since 30 degrees is in Q1.\nVerification: sin(30) = 0.5, cos(30) = 0.86602540, tan(30) = 0.57735027 (all confirmed)

Result: sin(30) = 0.5 | cos(30) = 0.86602540 | tan(30) = 0.57735027

Example 2: Half Angle of 270 Degrees

Problem: Find sin(135), cos(135), tan(135) using half angle formulas with A = 270 degrees.

Solution: cos(270) = 0\nA/2 = 135 degrees (Quadrant II: sin positive, cos negative)\nsin(135) = +sqrt((1 - 0)/2) = +sqrt(0.5) = 0.70710678\ncos(135) = -sqrt((1 + 0)/2) = -sqrt(0.5) = -0.70710678\ntan(135) = sin(270)/(1 + cos(270)) = -1/1 = -1.0\nVerification: sin(135) = 0.70710678, cos(135) = -0.70710678, tan(135) = -1.0 (confirmed)

Result: sin(135) = 0.70710678 | cos(135) = -0.70710678 | tan(135) = -1.0

Frequently Asked Questions

What are the half angle formulas?

The half angle formulas express trigonometric functions of half an angle in terms of the cosine of the full angle. The three primary formulas are: sin(A/2) = plus or minus sqrt((1 - cos(A))/2), cos(A/2) = plus or minus sqrt((1 + cos(A))/2), and tan(A/2) = sin(A)/(1 + cos(A)) = (1 - cos(A))/sin(A). The plus or minus sign for sine and cosine depends on the quadrant in which A/2 falls. These formulas are derived from the double angle formulas by solving for the half-angle function. They are particularly useful in calculus for evaluating integrals involving square roots of trigonometric expressions and in deriving the Weierstrass substitution.

How are half angle formulas derived from double angle formulas?

The half angle formulas are derived by rearranging the double angle cosine formulas. Starting with cos(2B) = 1 - 2sin2(B), solve for sin(B): sin2(B) = (1 - cos(2B))/2, so sin(B) = plus or minus sqrt((1 - cos(2B))/2). Now substitute B = A/2: sin(A/2) = plus or minus sqrt((1 - cos(A))/2). Similarly, from cos(2B) = 2cos2(B) - 1, solve for cos(B): cos2(B) = (1 + cos(2B))/2, giving cos(A/2) = plus or minus sqrt((1 + cos(A))/2). The tangent half angle formula tan(A/2) = sin(A)/(1 + cos(A)) avoids the square root by using the identity tan(A/2) = sin(A/2)/cos(A/2) and algebraic manipulation.

How do you determine the sign in half angle formulas?

The sign (positive or negative) in the half angle formulas for sine and cosine depends on the quadrant in which the half angle A/2 falls, not the quadrant of A itself. If A/2 is in the first or second quadrant (0 to 180 degrees), sin(A/2) is positive. If A/2 is in the first or fourth quadrant (0 to 90 or 270 to 360 degrees), cos(A/2) is positive. For example, if A = 300 degrees, then A/2 = 150 degrees which is in the second quadrant. Therefore sin(150) is positive and cos(150) is negative. The tangent half angle formulas using sin(A)/(1+cos(A)) or (1-cos(A))/sin(A) automatically give the correct sign without needing to determine the quadrant separately.

What is the Weierstrass substitution and how does it use half angle formulas?

The Weierstrass substitution (also called the tangent half-angle substitution) is a powerful calculus technique that converts trigonometric integrals into rational function integrals. You set t = tan(x/2), then use the half angle identities to express: sin(x) = 2t/(1+t2), cos(x) = (1-t2)/(1+t2), and dx = 2/(1+t2) dt. This transforms any rational function of sin(x) and cos(x) into a rational function of t, which can be integrated using partial fractions. While not always the most efficient method, the Weierstrass substitution is universal and guaranteed to work for any rational trigonometric integral. It was developed by Karl Weierstrass in the 19th century and remains a standard technique in calculus courses.

What are common applications of half angle formulas?

Half angle formulas have important applications across mathematics and engineering. In calculus, they enable the power reduction technique: sin2(x) = (1 - cos(2x))/2 and cos2(x) = (1 + cos(2x))/2, which are essential for integrating even powers of sine and cosine. In physics, half angle formulas appear in the analysis of optical systems, specifically in calculations involving prism refraction and thin film interference patterns. In electrical engineering, they help simplify AC circuit analysis when dealing with rectified waveforms. In computer graphics, half angle vectors are used in specular reflection calculations (Blinn-Phong shading model). In surveying and navigation, half angle formulas appear in the haversine formula for calculating great circle distances.

How do half angle formulas help find exact trigonometric values?

Half angle formulas allow you to find exact values of trigonometric functions for angles that are half of known standard angles. For example, to find the exact value of sin(15 degrees), use sin(30/2) = sqrt((1 - cos(30))/2) = sqrt((1 - sqrt(3)/2)/2) = sqrt((2 - sqrt(3))/4). This gives an exact radical expression rather than a decimal approximation. Similarly, cos(22.5 degrees) = sqrt((1 + cos(45))/2) = sqrt((1 + sqrt(2)/2)/2) = sqrt((2 + sqrt(2))/4). By repeatedly applying half angle formulas, you can find exact values for angles like 7.5 degrees, 3.75 degrees, and so on. This technique is valuable in pure mathematics where exact symbolic expressions are preferred over numerical approximations.

References

Reviewed by Manoj Kumar, Mathematics Educator ยท Editorial policy