Gradient Field Plotter Calculator
Solve gradient field plotter problems step-by-step with our free calculator. See formulas, worked examples, and clear explanations.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
grad(f) = (df/dx, df/dy)
The gradient of a scalar function f(x,y) is the vector of partial derivatives. It points in the direction of steepest ascent with magnitude equal to the maximum rate of change. The gradient is perpendicular to level curves.
Worked Examples
Example 1: Gradient of f(x,y) = x^2 + y^2 at (3, 4)
Problem:Compute the gradient vector, magnitude, direction, and directional derivative at the point (3, 4) for f(x,y) = x^2 + y^2.
Solution:f(3,4) = 9 + 16 = 25\ndf/dx = 2x = 2(3) = 6\ndf/dy = 2y = 2(4) = 8\nGradient = (6, 8)\nMagnitude = sqrt(36 + 64) = sqrt(100) = 10\nDirection = arctan(8/6) = 53.13 degrees\nUnit gradient = (0.6, 0.8)\nMax directional derivative = 10 (in gradient direction)
Result:Gradient = (6, 8) | Magnitude = 10 | Direction = 53.13 deg | f(3,4) = 25
Example 2: Critical Point Analysis of f(x,y) = x^2 - y^2
Problem:Evaluate the gradient at the origin (0, 0) for the saddle surface f(x,y) = x^2 - y^2.
Solution:f(0,0) = 0\ndf/dx = 2x = 0\ndf/dy = -2y = 0\nGradient = (0, 0) - this is a critical point\nf_xx = 2, f_yy = -2, f_xy = 0\nHessian determinant = (2)(-2) - 0^2 = -4 < 0\nClassification: Saddle Point\nLaplacian = f_xx + f_yy = 2 + (-2) = 0
Result:Gradient = (0, 0) | Critical Point | Classification: Saddle Point
Frequently Asked Questions
What is a gradient field in mathematics?
A gradient field (also called a gradient vector field) is a vector field derived from a scalar function f(x,y) by computing its partial derivatives. At every point (x,y) in the domain, the gradient vector is formed by the partial derivative with respect to x and the partial derivative with respect to y, written as grad(f) = (df/dx, df/dy). The gradient vector at any point indicates the direction of steepest ascent of the function and its magnitude gives the rate of that steepest ascent. Gradient fields are fundamental in multivariable calculus, physics, optimization, and machine learning.
What does the gradient vector represent geometrically?
Geometrically, the gradient vector at a point has two key properties. First, it points in the direction of the steepest increase of the function at that point. If you imagine the function as a topographic surface, the gradient points uphill in the steepest direction. Second, the magnitude of the gradient equals the rate of change in that steepest direction. The gradient is always perpendicular (orthogonal) to the level curves (contour lines) of the function. Where the gradient is zero, you have a critical point which could be a local minimum, maximum, or saddle point.
How do you compute the gradient of a function?
To compute the gradient of a scalar function f(x,y), take the partial derivative with respect to each variable independently. For f(x,y) = x^2 + y^2, the partial derivative with respect to x is 2x (treating y as constant), and the partial derivative with respect to y is 2y (treating x as constant). So grad(f) = (2x, 2y). For three variables, the gradient has three components: grad(f) = (df/dx, df/dy, df/dz). The gradient operator is denoted by the nabla symbol. Each component tells you how fast the function changes in that coordinate direction.
What is the relationship between gradient and level curves?
The gradient vector at any point is always perpendicular (orthogonal) to the level curve passing through that point. A level curve is a set of points where the function has a constant value, like contour lines on a topographic map. Since the function value does not change along a level curve, there is zero rate of change in the tangential direction. The gradient, pointing in the direction of maximum change, must therefore be perpendicular to the level curve. The spacing of level curves indicates the gradient magnitude: closely spaced contours mean a large gradient, widely spaced contours mean a small gradient.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy