Skip to main content

Binomial Probability Calculator

Solve binomial probability problems step-by-step with our free calculator. See formulas, worked examples, and clear explanations.

Skip to calculator
Mathematics

Binomial Probability Calculator

Calculate exact and cumulative binomial probabilities. Find P(X=k), P(X<=k), P(X>=k) with distribution visualization, mean, variance, and standard deviation.

Last updated: December 2025Reviewed by NovaCalculator Mathematics Team

Calculator

Adjust values & calculate
10
50.0%
6
P(X = 6)
20.5078%
C(10,6) = 210
P(X โ‰ค 6)
82.8125%
P(X โ‰ฅ 6)
37.6953%
P(X < 6)
62.3047%
P(X > 6)
17.1875%
Mean (Expected Value)
5.00
Standard Deviation
1.5811
Variance
2.5000
Mode
5

Probability Distribution

0
0.10%
1
0.98%
2
4.39%
3
11.72%
4
20.51%
5
24.61%
6
20.51%
7
11.72%
8
4.39%
9
0.98%
10
0.10%
Your Result
P(X=6) = 20.5078% | P(X<=6) = 82.8125% | Mean = 5.00
Share Your Result
Understand the Math

Formula

P(X=k) = C(n,k) * p^k * (1-p)^(n-k)

Where n is the number of independent trials, k is the number of successes, p is the probability of success on each trial, and C(n,k) is the binomial coefficient (n choose k). The formula multiplies the number of ways to arrange k successes among n trials by the probability of any specific arrangement.

Last reviewed: December 2025

Worked Examples

Example 1: Coin Flip Probability

What is the probability of getting exactly 6 heads in 10 fair coin flips?
Solution:
n = 10 trials, k = 6 successes, p = 0.5 P(X = 6) = C(10,6) x 0.5^6 x 0.5^4 C(10,6) = 10! / (6! x 4!) = 210 P(X = 6) = 210 x 0.015625 x 0.0625 P(X = 6) = 210 x 0.000977 P(X = 6) = 0.2051 or 20.51% Cumulative P(X <= 6) = 0.8281 or 82.81%
Result: P(exactly 6 heads) = 20.51%, P(6 or fewer heads) = 82.81%

Example 2: Quality Control Defect Analysis

A factory has a 3% defect rate. In a sample of 50 items, what is the probability of finding exactly 2 defective items?
Solution:
n = 50 trials, k = 2 successes (defects), p = 0.03 P(X = 2) = C(50,2) x 0.03^2 x 0.97^48 C(50,2) = 1225 0.03^2 = 0.0009 0.97^48 = 0.2281 P(X = 2) = 1225 x 0.0009 x 0.2281 P(X = 2) = 0.2515 or 25.15% Mean defects expected: 50 x 0.03 = 1.5
Result: P(exactly 2 defects) = 25.15%, Expected defects = 1.5
Expert Insights

Background & Theory

The Binomial Probability Calculator applies the following established principles and formulas. Probability theory provides the mathematical foundation for analysing all games of chance. The fundamental measure assigns a probability between 0 and 1 to each outcome by dividing the count of favourable outcomes by the count of equally likely total outcomes. Rolling a standard six-sided die produces a 1/6 probability for each face; the probability that a fair coin lands heads exactly three times in five tosses follows the binomial distribution with parameters n=5 and p=0.5. Expected value (EV) is the probability-weighted average outcome of a random variable: EV equals the sum of each outcome multiplied by its probability. A fair coin flip paying $1 for heads and costing $1 for tails has EV of zero. Casino games are designed with negative expected value for the player; the house edge is the casino's average percentage profit per bet. European roulette with a single zero has a house edge of 2.7 percent, while American roulette's double zero raises it to 5.26 percent. Poker hand probabilities derive from combinatorics. From a 52-card deck, the number of distinct 5-card hands is C(52,5) = 2,598,960. A royal flush can occur in only 4 ways, giving it a probability of approximately 0.000154 percent. Blackjack basic strategy tables, derived from computer simulation of millions of hands, reduce the house edge from roughly 2 percent to below 0.5 percent by specifying the optimal hit, stand, double, or split decision for every player hand against every dealer up-card. Sports betting implied probability converts decimal odds to a probability estimate: implied probability equals 1 divided by decimal odds. Odds of 2.5 imply a 40 percent probability. The Kelly Criterion provides the theoretically optimal bet fraction: f equals (bp minus q) divided by b, where b is the net odds received, p is the probability of winning, and q is the probability of losing. This formula maximises the long-run geometric growth rate of a bankroll.

History

The history behind the Binomial Probability Calculator traces back through the following developments. Physical evidence of dice play dates to around 2500 BCE at the Indus Valley city of Mohenjo-daro, where excavators found carved cubic astragali remarkably similar to modern dice. Ancient Egyptian, Greek, and Roman cultures all incorporated dice games into both leisure and religious ritual, suggesting gambling emerged independently across early civilisations as a universal human impulse. The first systematic attempt to mathematically analyse games of chance came from Gerolamo Cardano, the Italian polymath who wrote "Liber de Ludo Aleae" (Book on Games of Chance) around 1564. Cardano derived correct probabilities for dice combinations and introduced the concept of sample space, though his work remained unpublished until 1663. The field transformed into a rigorous discipline through correspondence in 1654 between Blaise Pascal and Pierre de Fermat prompted by a gambling problem posed by the Chevalier de Mere. Their exchange established the rules of probability, including the concept of expected value. Jacob Bernoulli's "Ars Conjectandi" (1713) formalised the law of large numbers, proving that sample frequencies converge to true probabilities as trials increase. The 20th century brought two pivotal developments. Stanislaw Ulam and John von Neumann devised Monte Carlo simulation methods in 1947 while working at Los Alamos, showing that complex probabilistic systems could be analysed by random sampling. Game theory and poker strategy developed in parallel, with John von Neumann's minimax theorem providing early foundations and later work by game theorists formalisingrational play under incomplete information. Online gambling launched in the mid-1990s following the passage of the Free Trade and Processing Act in Antigua in 1994, which issued the first online casino licences. The Unlawful Internet Gambling Enforcement Act of 2006 disrupted US online gambling markets. Esports betting and video game loot box mechanics brought probability and expected value calculations to younger audiences in the 2010s, prompting regulatory scrutiny of randomised virtual reward systems across multiple jurisdictions.

Share this calculator

Explore More

Frequently Asked Questions

The binomial probability distribution models the number of successes in a fixed number of independent trials, where each trial has exactly two possible outcomes (success or failure) with a constant probability of success. It is one of the most fundamental discrete probability distributions in statistics. For example, flipping a fair coin 10 times and counting heads follows a binomial distribution with n equals 10 and p equals 0.5. The distribution requires three conditions: a fixed number of trials, independent trials, and a constant probability of success. The shape of the distribution depends on both n and p, ranging from right-skewed when p is small to left-skewed when p is large to symmetric when p equals 0.5.
The binomial probability formula calculates the exact probability of getting exactly k successes in n trials: P(X equals k) equals C(n,k) times p raised to the k times (1 minus p) raised to the (n minus k). Here, C(n,k) is the binomial coefficient representing the number of ways to choose k items from n items, calculated as n factorial divided by k factorial times (n minus k) factorial. The term p to the k represents the probability of k successes occurring, and (1 minus p) to the (n minus k) represents the probability of the remaining trials being failures. The binomial coefficient accounts for all possible orderings of successes and failures within the n trials.
The Probability Mass Function (PMF) gives the probability of getting exactly a specific number of successes, while the Cumulative Distribution Function (CDF) gives the probability of getting at most that number of successes. The PMF answers questions like 'what is the probability of exactly 3 heads in 10 flips' while the CDF answers 'what is the probability of 3 or fewer heads in 10 flips.' The CDF is calculated by summing all PMF values from 0 up to and including the target value. The complement of the CDF (1 minus CDF) gives the probability of getting more than that number of successes. Both functions are essential for hypothesis testing, quality control, and risk assessment in statistics.
Four conditions must be satisfied for the binomial distribution to apply. First, there must be a fixed number of trials (n) determined before the experiment begins. Second, each trial must have exactly two possible outcomes, conventionally called success and failure. Third, the probability of success (p) must remain constant from trial to trial. Fourth, the trials must be independent, meaning the outcome of one trial does not affect any other trial. If these conditions are violated, other distributions may be more appropriate: the hypergeometric distribution for sampling without replacement, the negative binomial for variable trial counts, or the multinomial distribution for more than two outcomes per trial.
The mean (expected value) of a binomial distribution equals n times p, representing the average number of successes you would expect over many repetitions of the experiment. For 100 coin flips with a fair coin, the expected number of heads is 50. The standard deviation equals the square root of n times p times (1 minus p), measuring the typical spread of results around the mean. For those 100 coin flips, the standard deviation is about 5, meaning most outcomes will fall between 45 and 55 heads. Together, the mean and standard deviation define the center and spread of the distribution. As n increases, the distribution becomes more bell-shaped and can be approximated by a normal distribution.
Quality control extensively uses the binomial distribution to make accept or reject decisions about product batches. In acceptance sampling, inspectors test a random sample of n items from a batch and count the number of defective items. If the defect count exceeds a predetermined threshold (the acceptance number), the entire batch is rejected. The binomial distribution calculates the probability of finding a certain number of defects given the true defect rate. Operating Characteristic curves, which plot the probability of accepting a batch versus the true defect rate, are based on binomial probabilities. Control charts for attribute data (p-charts and np-charts) use binomial distribution properties to set control limits and detect process shifts.
Educational Note: This calculator is provided for educational and informational purposes. Results are based on the formulas and inputs provided. Always verify important calculations independently. NovaCalculator processes calculator inputs client-side; optional analytics follow visitor consent settings.Reviewed by: NovaCalculator Mathematics Team โ€” Verified against standard mathematical and scientific references. Last reviewed: December 2025. ยฉ 2024โ€“2026 NovaCalculator.

Share this calculator

Formula

P(X=k) = C(n,k) * p^k * (1-p)^(n-k)

Where n is the number of independent trials, k is the number of successes, p is the probability of success on each trial, and C(n,k) is the binomial coefficient (n choose k). The formula multiplies the number of ways to arrange k successes among n trials by the probability of any specific arrangement.

Worked Examples

Example 1: Coin Flip Probability

Problem: What is the probability of getting exactly 6 heads in 10 fair coin flips?

Solution: n = 10 trials, k = 6 successes, p = 0.5\n\nP(X = 6) = C(10,6) x 0.5^6 x 0.5^4\nC(10,6) = 10! / (6! x 4!) = 210\nP(X = 6) = 210 x 0.015625 x 0.0625\nP(X = 6) = 210 x 0.000977\nP(X = 6) = 0.2051 or 20.51%\n\nCumulative P(X <= 6) = 0.8281 or 82.81%

Result: P(exactly 6 heads) = 20.51%, P(6 or fewer heads) = 82.81%

Example 2: Quality Control Defect Analysis

Problem: A factory has a 3% defect rate. In a sample of 50 items, what is the probability of finding exactly 2 defective items?

Solution: n = 50 trials, k = 2 successes (defects), p = 0.03\n\nP(X = 2) = C(50,2) x 0.03^2 x 0.97^48\nC(50,2) = 1225\n0.03^2 = 0.0009\n0.97^48 = 0.2281\n\nP(X = 2) = 1225 x 0.0009 x 0.2281\nP(X = 2) = 0.2515 or 25.15%\n\nMean defects expected: 50 x 0.03 = 1.5

Result: P(exactly 2 defects) = 25.15%, Expected defects = 1.5

Frequently Asked Questions

What is the binomial probability distribution?

The binomial probability distribution models the number of successes in a fixed number of independent trials, where each trial has exactly two possible outcomes (success or failure) with a constant probability of success. It is one of the most fundamental discrete probability distributions in statistics. For example, flipping a fair coin 10 times and counting heads follows a binomial distribution with n equals 10 and p equals 0.5. The distribution requires three conditions: a fixed number of trials, independent trials, and a constant probability of success. The shape of the distribution depends on both n and p, ranging from right-skewed when p is small to left-skewed when p is large to symmetric when p equals 0.5.

How is the binomial probability formula calculated?

The binomial probability formula calculates the exact probability of getting exactly k successes in n trials: P(X equals k) equals C(n,k) times p raised to the k times (1 minus p) raised to the (n minus k). Here, C(n,k) is the binomial coefficient representing the number of ways to choose k items from n items, calculated as n factorial divided by k factorial times (n minus k) factorial. The term p to the k represents the probability of k successes occurring, and (1 minus p) to the (n minus k) represents the probability of the remaining trials being failures. The binomial coefficient accounts for all possible orderings of successes and failures within the n trials.

What is the difference between PMF and CDF in binomial distribution?

The Probability Mass Function (PMF) gives the probability of getting exactly a specific number of successes, while the Cumulative Distribution Function (CDF) gives the probability of getting at most that number of successes. The PMF answers questions like 'what is the probability of exactly 3 heads in 10 flips' while the CDF answers 'what is the probability of 3 or fewer heads in 10 flips.' The CDF is calculated by summing all PMF values from 0 up to and including the target value. The complement of the CDF (1 minus CDF) gives the probability of getting more than that number of successes. Both functions are essential for hypothesis testing, quality control, and risk assessment in statistics.

What are the conditions for using the binomial distribution?

Four conditions must be satisfied for the binomial distribution to apply. First, there must be a fixed number of trials (n) determined before the experiment begins. Second, each trial must have exactly two possible outcomes, conventionally called success and failure. Third, the probability of success (p) must remain constant from trial to trial. Fourth, the trials must be independent, meaning the outcome of one trial does not affect any other trial. If these conditions are violated, other distributions may be more appropriate: the hypergeometric distribution for sampling without replacement, the negative binomial for variable trial counts, or the multinomial distribution for more than two outcomes per trial.

What do the mean and standard deviation of a binomial distribution tell us?

The mean (expected value) of a binomial distribution equals n times p, representing the average number of successes you would expect over many repetitions of the experiment. For 100 coin flips with a fair coin, the expected number of heads is 50. The standard deviation equals the square root of n times p times (1 minus p), measuring the typical spread of results around the mean. For those 100 coin flips, the standard deviation is about 5, meaning most outcomes will fall between 45 and 55 heads. Together, the mean and standard deviation define the center and spread of the distribution. As n increases, the distribution becomes more bell-shaped and can be approximated by a normal distribution.

How is the binomial distribution used in quality control?

Quality control extensively uses the binomial distribution to make accept or reject decisions about product batches. In acceptance sampling, inspectors test a random sample of n items from a batch and count the number of defective items. If the defect count exceeds a predetermined threshold (the acceptance number), the entire batch is rejected. The binomial distribution calculates the probability of finding a certain number of defects given the true defect rate. Operating Characteristic curves, which plot the probability of accepting a batch versus the true defect rate, are based on binomial probabilities. Control charts for attribute data (p-charts and np-charts) use binomial distribution properties to set control limits and detect process shifts.

References

Reviewed by Manoj Kumar, Mathematics Educator ยท Editorial policy