Collatz Conjecture Calculator
Free Collatz conjecture Calculator for sequences. Enter values to get step-by-step solutions with formulas and graphs. Get results you can export or share.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
If n is even: n -> n/2 | If n is odd: n -> 3n + 1
Starting from any positive integer, repeatedly apply these two rules. The Collatz conjecture states that this process will always eventually reach 1, regardless of the starting number. The sequence of values is also called hailstone numbers because they rise and fall like hailstones in a cloud.
Worked Examples
Example 1: Classic Example: Starting at 27
Problem:Compute the Collatz sequence starting at 27. How many steps does it take to reach 1, and what is the maximum value?
Solution:Starting at 27:\n27 -> 82 -> 41 -> 124 -> 62 -> 31 -> 94 -> 47 -> 142 -> 71 -> ...\nThe sequence climbs to a peak of 9,232 at step 77\nAfter the peak, it descends through powers of 2\nThe sequence finally reaches 1 after 111 steps\nTotal odd steps: 41 | Total even steps: 70
Result:Stopping time: 111 steps | Peak value: 9,232 | Peak/Start ratio: 341.93x
Example 2: Power of 2: Starting at 64
Problem:Compute the Collatz sequence starting at 64 (which is 2^6).
Solution:Starting at 64:\n64 -> 32 -> 16 -> 8 -> 4 -> 2 -> 1\nSince 64 = 2^6, the sequence simply halves 6 times\nAll steps are even-number divisions\nNo odd steps occur, so the value never increases\nThis is the shortest possible sequence for a number of this magnitude
Result:Stopping time: 6 steps | Peak value: 64 | All 6 steps are even divisions
Frequently Asked Questions
What is the Collatz conjecture and why is it famous?
The Collatz conjecture, also known as the 3n+1 problem, is one of the most famous unsolved problems in mathematics. The rule is simple: start with any positive integer, if it is even divide by 2, if it is odd multiply by 3 and add 1. The conjecture states that no matter what starting number you choose, the sequence will always eventually reach 1. Despite its simple formulation, no one has been able to prove this is true for all numbers, even after decades of effort by brilliant mathematicians. Paul Erdos famously said that mathematics is not yet ready for such problems.
How does the Collatz sequence work step by step?
Starting with any positive integer n, apply two rules repeatedly. Rule 1: if n is even, divide it by 2 (n becomes n/2). Rule 2: if n is odd, multiply by 3 and add 1 (n becomes 3n+1). Continue until you reach 1. For example, starting with 6: 6 is even, so 6/2=3. Then 3 is odd, so 3x3+1=10. Then 10/2=5, 5x3+1=16, 16/2=8, 8/2=4, 4/2=2, 2/2=1. The sequence is 6, 3, 10, 5, 16, 8, 4, 2, 1, taking 8 steps. The path can be surprisingly long and unpredictable even for small starting numbers.
What is the stopping time in the Collatz sequence?
The stopping time (also called total stopping time) is the number of steps required for the sequence to reach 1 from the starting number. Different starting values produce vastly different stopping times. The number 1 has a stopping time of 0. The number 2 takes 1 step. The number 27 is famous because despite being relatively small, it takes 111 steps and reaches a maximum value of 9,232 before finally descending to 1. There is no known formula to predict the stopping time without actually computing the sequence. This unpredictability is part of what makes the conjecture so challenging to prove.
What are some notable numbers in Collatz sequences?
The number 27 is perhaps the most famous example because it takes 111 steps and climbs to 9,232 before reaching 1, demonstrating how a small starting number can produce a long, wild trajectory. Powers of 2 have the shortest sequences since they simply halve down to 1 (for example, 64 takes only 6 steps). The number 9,663 takes 184 steps. Among the first million numbers, 837,799 has the longest sequence at 524 steps. The number 77,031 reaches a peak value over 21 million. These examples illustrate the chaotic and unpredictable nature of the sequences generated by this deceptively simple rule.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy