Null Space Calculator
Free Null space Calculator for fractions. Enter values to get step-by-step solutions with formulas and graphs. Free to use with no signup required.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
Null(A) = {x | Ax = 0}The null space of matrix A is the set of all vectors x that satisfy the homogeneous equation Ax = 0. It is found by row reducing A to RREF and identifying free variables.
Worked Examples
Example 1: Singular 3x3 Matrix Null Space
Problem:Find the null space of the matrix [[1,2,3],[4,5,6],[7,8,9]].
Solution:RREF: [[1,0,-1],[0,1,2],[0,0,0]]\nRank = 2, Nullity = 1\nFree variable: x3 = t\nFrom row 2: x2 = -2t\nFrom row 1: x1 = t\nNull space basis: [1, -2, 1]\nVerify: [1,2,3] dot [1,-2,1] = 1-4+3 = 0
Result:Null space = span{[1, -2, 1]}, dimension = 1
Example 2: Full Rank Matrix (Trivial Null Space)
Problem:Find the null space of the identity matrix [[1,0,0],[0,1,0],[0,0,1]].
Solution:RREF: [[1,0,0],[0,1,0],[0,0,1]]\nRank = 3, Nullity = 0\nNo free variables\nThe only solution to Ix = 0 is x = [0,0,0]\nDeterminant = 1 (nonzero, confirming invertibility)
Result:Null space = {[0,0,0]} (trivial), dimension = 0
Frequently Asked Questions
What is the null space of a matrix and why is it important?
The null space (also called the kernel) of a matrix A is the set of all vectors x such that Ax equals the zero vector. In other words, it contains every vector that the matrix maps to zero when used as a linear transformation. The null space is a subspace of the domain, meaning it is closed under addition and scalar multiplication. It is important because it tells us about the redundancy in a system of linear equations. If the null space contains only the zero vector, the system has a unique solution. If the null space is nontrivial, the system has infinitely many solutions, and the null space vectors describe the directions of freedom in the solution set.
How do you calculate the null space of a matrix step by step?
To find the null space, first set up the homogeneous equation Ax = 0 and form the augmented matrix with a zero column. Then perform Gaussian elimination (row reduction) to bring the matrix to reduced row echelon form (RREF). Identify the pivot columns (which correspond to basic variables) and the non-pivot columns (which correspond to free variables). Set each free variable equal to a parameter (like t or s) and solve for the basic variables in terms of these parameters. Each parameter generates one basis vector for the null space. The collection of these basis vectors spans the entire null space, and the number of basis vectors equals the nullity of the matrix.
What is the rank-nullity theorem and how does it relate to null space?
The rank-nullity theorem states that for any m-by-n matrix A, the rank of A plus the nullity of A equals n (the number of columns). The rank is the number of pivot columns in the RREF, representing the dimension of the column space. The nullity is the dimension of the null space, representing the number of free variables. This theorem is fundamental because it creates a direct relationship between the column space and the null space. For example, a 3-by-3 matrix with rank 2 must have nullity 1, meaning its null space is a line through the origin. A 3-by-3 matrix with rank 1 has nullity 2, meaning its null space is a plane through the origin.
What does it mean when the null space is trivial versus nontrivial?
A trivial null space contains only the zero vector, which means the matrix has full column rank and the equation Ax = 0 has only the solution x = 0. This indicates that the columns of the matrix are linearly independent and the associated linear transformation is one-to-one (injective). A nontrivial null space contains nonzero vectors, meaning there exist nonzero solutions to Ax = 0. This tells us the columns are linearly dependent and the transformation is not injective. For square matrices, a trivial null space also means the matrix is invertible and its determinant is nonzero. The distinction between trivial and nontrivial null spaces has critical implications in solving systems of equations.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy