Spherical Coordinates Calculator
Solve spherical coordinates problems step-by-step with our free calculator. See formulas, worked examples, and clear explanations.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
r = sqrt(x^2+y^2+z^2), theta = atan2(y,x), phi = acos(z/r)
Where r is the radial distance from the origin, theta is the azimuthal angle in the xy-plane from the positive x-axis, and phi is the polar angle from the positive z-axis.
Worked Examples
Example 1: Cartesian to Spherical Conversion
Problem:Convert the Cartesian point (3, 4, 5) to spherical coordinates.
Solution:r = sqrt(3^2 + 4^2 + 5^2) = sqrt(9 + 16 + 25) = sqrt(50) = 7.0711\ntheta = atan2(4, 3) = 53.1301 degrees (0.9273 radians)\nphi = acos(5 / 7.0711) = acos(0.7071) = 45.0000 degrees (0.7854 radians)\nJacobian = r^2 * sin(phi) = 50 * 0.7071 = 35.3553
Result:(r, theta, phi) = (7.0711, 53.13 deg, 45.00 deg)
Example 2: Spherical to Cartesian Conversion
Problem:Convert spherical coordinates (10, 30 deg, 60 deg) to Cartesian.
Solution:x = 10 * sin(60 deg) * cos(30 deg) = 10 * 0.8660 * 0.8660 = 7.5000\ny = 10 * sin(60 deg) * sin(30 deg) = 10 * 0.8660 * 0.5000 = 4.3301\nz = 10 * cos(60 deg) = 10 * 0.5000 = 5.0000\nVerification: sqrt(7.5^2 + 4.33^2 + 5^2) = sqrt(56.25 + 18.75 + 25) = 10
Result:(x, y, z) = (7.5000, 4.3301, 5.0000)
Frequently Asked Questions
What are spherical coordinates and when are they used?
Spherical coordinates describe a point in three-dimensional space using three values: the radial distance (rho or r) from the origin, the polar angle (phi) measured from the positive z-axis, and the azimuthal angle (theta) measured from the positive x-axis in the xy-plane. This system is particularly useful when dealing with problems that have spherical symmetry, such as gravitational fields around planets, electromagnetic radiation patterns from antennas, and quantum mechanical wavefunctions of atoms. Spherical coordinates simplify many integrals and differential equations that would be much more complex in Cartesian coordinates.
How do you convert from Cartesian to spherical coordinates?
Converting from Cartesian coordinates (x, y, z) to spherical coordinates (r, theta, phi) uses three formulas. The radial distance r equals the square root of x-squared plus y-squared plus z-squared. The azimuthal angle theta equals arctan(y/x), which gives the angle in the xy-plane measured from the positive x-axis. The polar angle phi equals arccos(z/r), which gives the angle measured down from the positive z-axis. When implementing these formulas, it is important to use the two-argument arctangent function (atan2) to get the correct quadrant for theta, as the standard arctangent function only returns values between -90 and 90 degrees.
What is the difference between spherical and cylindrical coordinates?
Both spherical and cylindrical coordinates are alternatives to Cartesian coordinates for describing points in 3D space, but they are suited for different symmetries. Cylindrical coordinates (r, theta, z) extend polar coordinates by adding a height component z, making them ideal for problems with circular or cylindrical symmetry like pipes, towers, and rotating shafts. Spherical coordinates (rho, theta, phi) use two angles and a radial distance, making them ideal for problems with spherical symmetry like planets, atoms, and radiation patterns. The cylindrical radial distance r is the distance from the z-axis, while the spherical radial distance rho is the distance from the origin.
What is the Jacobian determinant in spherical coordinates?
The Jacobian determinant for the transformation from Cartesian to spherical coordinates equals r-squared times sin(phi), written as J = r^2 sin(phi). This factor appears whenever you perform integration in spherical coordinates, converting the volume element from dx dy dz to r^2 sin(phi) dr d_theta d_phi. The Jacobian accounts for the fact that coordinate cells in spherical coordinates are not uniform cubes but rather wedge-shaped volumes that get larger as r increases and vary in shape with phi. Without including the Jacobian, integrals in spherical coordinates would give incorrect results. This is crucial in physics for calculating gravitational potentials, electric fields, and probability densities.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy