Synthetic Division Calculator
Calculate synthetic division instantly with our math tool. Shows detailed work, formulas used, and multiple solution methods.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
P(x) / (x - c): bring down a_n, then multiply by c and add to next coefficient
Synthetic division works by repeatedly multiplying the current result by the divisor value c and adding to the next coefficient. The last number in the bottom row is the remainder, and all preceding numbers are the quotient coefficients. If the remainder is zero, then (x - c) is a factor of P(x).
Worked Examples
Example 1: Dividing a Cubic Polynomial
Problem:Divide P(x) = x^3 - 6x^2 + 11x - 6 by (x - 2) using synthetic division.
Solution:Coefficients: 1, -6, 11, -6 and divisor c = 2\nBring down 1\n1 * 2 = 2, add to -6: -4\n-4 * 2 = -8, add to 11: 3\n3 * 2 = 6, add to -6: 0\nBottom row: 1, -4, 3, 0
Result:Quotient: x^2 - 4x + 3, Remainder: 0. Since remainder is 0, x = 2 is a root and (x - 2) is a factor.
Example 2: Testing a Potential Root
Problem:Use synthetic division to test whether x = 3 is a root of P(x) = 2x^3 - 5x^2 - 4x + 3.
Solution:Coefficients: 2, -5, -4, 3 and divisor c = 3\nBring down 2\n2 * 3 = 6, add to -5: 1\n1 * 3 = 3, add to -4: -1\n-1 * 3 = -3, add to 3: 0\nBottom row: 2, 1, -1, 0
Result:Quotient: 2x^2 + x - 1, Remainder: 0. x = 3 IS a root. Factor further: (x - 3)(2x - 1)(x + 1).
Frequently Asked Questions
What is synthetic division and when should I use it?
Synthetic division is a shorthand method for dividing a polynomial by a linear factor of the form (x - c). It dramatically simplifies the traditional long division process by working only with the coefficients of the polynomial rather than writing out full variable expressions. This method is particularly useful when you need to test potential roots of a polynomial using the Rational Root Theorem, or when factoring higher-degree polynomials step by step. Synthetic division reduces errors and saves significant time compared to polynomial long division, making it the preferred approach in most algebra courses.
How do I set up synthetic division correctly?
To set up synthetic division, first write down all coefficients of the polynomial in descending order of degree, including zeros for any missing terms. For example, x^3 + 2x - 5 has coefficients 1, 0, 2, -5 because the x^2 term is missing and needs a zero placeholder. Then write the value c from the divisor (x - c) to the left side. If you are dividing by (x + 3), use c = -3 since (x + 3) = (x - (-3)). Getting the sign correct on the divisor value is the most common source of errors in synthetic division problems.
What does the remainder in synthetic division tell me?
The remainder in synthetic division has a direct connection to the Remainder Theorem, which states that when polynomial P(x) is divided by (x - c), the remainder equals P(c). This means you can evaluate any polynomial at a specific value simply by performing synthetic division. If the remainder is zero, then c is a root of the polynomial and (x - c) is a factor. This connection between division and evaluation makes synthetic division an incredibly efficient tool for finding polynomial roots, testing potential rational roots, and completely factoring polynomials into linear factors.
Can synthetic division be used with any divisor?
Standard synthetic division only works when dividing by a linear expression of the form (x - c). You cannot directly use synthetic division to divide by quadratic or higher-degree polynomials like (x^2 + 1) or (x^2 - 3x + 2). For those cases, you must use polynomial long division instead. However, there is an extended version of synthetic division that can handle divisors of the form (ax - c) where a is not equal to 1, though it requires an additional step of dividing all quotient coefficients by a at the end. Most textbooks stick to the standard form where the leading coefficient of the divisor is one.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy