Completing the Square Calculator
Our free algebra calculator solves completing square problems. Get worked examples, visual aids, and downloadable results.
Reviewed by Manoj Kumar, Mathematics Educator
Formula
ax^2 + bx + c = a(x - h)^2 + k
Where h = -b/(2a) is the x-coordinate of the vertex, and k = c - b^2/(4a) is the y-coordinate. The vertex form reveals the parabola opens upward when a > 0 (minimum at k) and downward when a < 0 (maximum at k). The axis of symmetry is the vertical line x = h.
Worked Examples
Example 1: Completing the Square for x^2 - 6x + 5
Problem:Convert x^2 - 6x + 5 to vertex form by completing the square.
Solution:Step 1: Take half of -6: (-6)/2 = -3\nStep 2: Square it: (-3)^2 = 9\nStep 3: Add and subtract 9:\n x^2 - 6x + 9 - 9 + 5\n = (x - 3)^2 - 4\nVertex: (3, -4)\nRoots: x - 3 = +/-2 => x = 1, x = 5
Result:(x - 3)^2 - 4 | Vertex: (3, -4)
Example 2: Completing the Square for 2x^2 + 8x + 3
Problem:Convert 2x^2 + 8x + 3 to vertex form.
Solution:Step 1: Factor out 2: 2(x^2 + 4x) + 3\nStep 2: Half of 4 is 2, squared is 4\nStep 3: 2(x^2 + 4x + 4 - 4) + 3\n = 2(x + 2)^2 - 8 + 3\n = 2(x + 2)^2 - 5\nVertex: (-2, -5)
Result:2(x + 2)^2 - 5 | Vertex: (-2, -5)
Frequently Asked Questions
What does completing the square mean and why is it useful?
Completing the square is an algebraic technique that transforms a quadratic expression ax^2 + bx + c into vertex form a(x - h)^2 + k. This transformation reveals the vertex of the parabola at point (h, k), making it easy to identify the minimum or maximum value and the axis of symmetry. The technique works by adding and subtracting a specific constant to create a perfect square trinomial within the expression. It is one of the most versatile methods in algebra because it not only solves quadratic equations but also helps derive the quadratic formula, analyze conic sections, and simplify certain integral calculations in calculus.
What are the step-by-step instructions for completing the square?
To complete the square for ax^2 + bx + c, first factor out the leading coefficient a from the x terms if a is not 1. Then take half the coefficient of x (which is b/(2a)), square it to get b^2/(4a^2), and both add and subtract this value inside the expression. This creates a perfect square trinomial that factors as (x + b/(2a))^2. After simplifying, you get a(x - h)^2 + k where h = -b/(2a) and k = c - b^2/(4a). For example, x^2 + 6x + 2 becomes (x^2 + 6x + 9) - 9 + 2 = (x + 3)^2 - 7. Always verify by expanding the result back to standard form.
How is completing the square related to the quadratic formula?
The quadratic formula x = (-b plus/minus sqrt(b^2 - 4ac)) / (2a) is actually derived by completing the square on the general quadratic equation ax^2 + bx + c = 0. Starting with the general form, dividing by a, moving c/a to the other side, adding (b/(2a))^2 to both sides, factoring the left side as a perfect square, and then solving for x produces the quadratic formula. Understanding this derivation provides deeper insight into why the formula works and reveals the geometric meaning of its components: -b/(2a) is the x-coordinate of the vertex, and the discriminant b^2 - 4ac determines whether and where the parabola crosses the x-axis.
When should you use completing the square instead of factoring or the quadratic formula?
Completing the square is the best choice when you need the vertex form of a quadratic function, when solving optimization problems, or when working with circles and other conic sections. Factoring is faster when the quadratic has nice integer roots, and the quadratic formula is more direct when you only need the roots. However, completing the square is essential when the quadratic cannot be easily factored and you need more than just the roots. In calculus, completing the square is frequently used to evaluate integrals involving quadratic expressions in the denominator. It is also the standard approach for converting general conic section equations to standard form.
References
Reviewed by Manoj Kumar, Mathematics Educator · Editorial policy