BOD Calculator
Calculate Biochemical Oxygen Demand (BOD5) from dissolved oxygen readings and dilution factor, plus ultimate BOD via first-order kinetics for wastewater
BOD Calculator
Calculator
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Formula: BOD=(D1-D2)xDF; BODu=BODt/(1-e^(-kt))
Worked example โ BOD5=159 mg/L
Formula
BOD=(D1-D2)xDF; BODu=BODt/(1-e^(-kt))
DO depletion times dilution factor. Ultimate BOD via first-order kinetics.
Worked Examples
Example 1: Wastewater
Problem:D1=8.5,D2=3.2,DF=30,5d,k=0.23
Solution:BOD=(8.5-3.2)x30=159 mg/L BODu=159/0.683=232.7 mg/L
Result:BOD5=159 mg/L
Example 2: River
Problem:D1=8,D2=5.5,DF=1,5d,k=0.23
Solution:BOD=2.5 mg/L BODu=3.66 mg/L
Result:BOD5=2.5 mg/L
Frequently Asked Questions
Why must a wastewater sample be diluted before the BOD test?
Dissolved oxygen saturation in water at 20 degrees C is only about 9.1 mg/L, so a strong sample would exhaust the bottle long before five days elapse and the result would be a floor rather than a measurement. Diluting with aerated, nutrient-buffered dilution water keeps the depletion inside the measurable range, and the dilution factor multiplies the observed drop back up to the original strength. Raw sewage often needs a factor of 30 to 50.
What makes a BOD bottle valid under Standard Methods 5210B?
A dilution is only usable if oxygen depletion over the incubation reaches at least 2.0 mg/L and at least 1.0 mg/L of dissolved oxygen still remains at the end. Too little depletion means the reading is dominated by measurement noise, while too little residual means the microbes ran out of oxygen and the demand was truncated. Laboratories therefore set up several dilutions in parallel and report only those satisfying both limits.
What is the difference between BOD5 and ultimate BOD?
BOD5 is the oxygen consumed during the first five days, while ultimate BOD is the total carbonaceous demand the sample would eventually exert. They are linked by first-order kinetics, BODt = BODu x (1 - e^(-kt)). At the conventional k of 0.23 per day the bracket evaluates to about 0.683, so five days recovers only around 68 percent of ultimate demand. Oxygen sag modelling and waste load allocation use ultimate BOD, whereas discharge permits are usually written on BOD5.
What does the deoxygenation constant k represent and how do I choose it?
k is the first-order rate at which degradable organic matter is oxidised, in reciprocal days on a natural log basis, and it sets the shape of the BOD curve rather than its height. The customary default of 0.23 per day for domestic wastewater corresponds to a half-life of about three days, since ln 2 divided by 0.23 is close to 3.0. Readily degradable wastes have a larger k, while treated effluent and industrial wastes containing resistant compounds have smaller values.
How does nitrification distort a five-day result?
After roughly five to eight days nitrifying bacteria begin oxidising ammonia to nitrate, exerting a nitrogenous oxygen demand on top of the carbonaceous one. In nitrified effluent from a well-run plant that seed population is already present and the second demand can start much earlier, inflating apparent BOD. Adding an inhibitor such as allylthiourea or 2-chloro-6-trichloromethylpyridine suppresses it, and the result is then reported as carbonaceous BOD, or CBOD.
When should I use COD instead of BOD?
Chemical oxygen demand oxidises the sample with dichromate in a couple of hours and captures both degradable and non-degradable organics, so it is the practical choice for process control where a five-day wait is useless. BOD measures only what microorganisms will actually degrade, which is closer to what a receiving stream experiences. Many plants establish a site-specific BOD to COD ratio, run COD daily, and re-check the ratio with periodic BOD tests.
Why does the method specify incubation in the dark at 20 degrees C?
Darkness stops algae in the sample from photosynthesising and releasing oxygen, which would offset microbial consumption and understate demand. The fixed temperature matters because microbial rate constants rise with temperature, so a warmer bottle exerts more demand over the same five days and would report a higher BOD for identical water. Without both controls, results from different laboratories or different seasons would not be comparable.
What can make a BOD result come back falsely low?
Toxicity is the classic cause: chlorine residual, heavy metals, cyanide or extremes of pH inhibit the microbial population, so little oxygen is consumed even when organic load is high. Samples lacking a suitable microbial community, such as some industrial wastes, must be seeded before incubation. Holding a sample too long before setup also depresses the reading. A parallel COD result far above the BOD is a useful warning that something suppressed the biology.
How does temperature change the deoxygenation constant k?
The bottle is incubated at 20 degrees C, but a receiving stream rarely sits there, and rate constants rise with temperature. The usual correction is k at temperature T equals k at 20 degrees C multiplied by theta raised to the power (T - 20), with theta near 1.047 for carbonaceous deoxygenation. That value implies roughly a 4.7 percent change per degree, so a summer stream at 25 degrees C oxidises organics appreciably faster than the same water in winter, drawing the oxygen sag down sooner and closer to the outfall.
When does a BOD sample need to be seeded, and what is a seed correction?
Seeding supplies the microbial population that will do the oxidising. It is needed when the sample lacks one, for example chlorinated effluent, acidic or alkaline waste that has been neutralised, or industrial streams with unusual substrates. A settled domestic sewage supernatant or a commercial seed culture is added to the dilution water, and blank bottles containing seed alone are incubated in parallel so their own oxygen uptake can be subtracted from the sample depletion before the dilution factor is applied.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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