Slope Stability Factor Calculator - Geotechnical
Calculate geotechnical slope stability factor of safety using the infinite slope method. Includes stability number, critical height, and Taylor chart
Slope Stability Factor Calculator - Geotechnical
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Formula: FS = c/(gamma*H*sin(beta)*cos(beta)) + tan(phi)/tan(beta)
Worked example โ FS = 1.242, marginally stable
Formula
FS = c/(gamma*H*sin(beta)*cos(beta)) + tan(phi)/tan(beta)
The infinite slope factor of safety has two components: a cohesion term that depends on slope geometry and soil weight, and a friction term that is simply the ratio of tangent of friction angle to tangent of slope angle. The stability number Ns = gamma*H/c is a dimensionless group used with Taylor charts. The critical height Hc is the maximum height at which the slope can stand without failure.
Worked Examples
Example 1: Natural Hillside Slope Assessment
Problem:Analyze a 30-degree slope with H = 8 m, c = 20 kPa, phi = 28 degrees, gamma = 18 kN/m3.
Solution:Infinite slope FS = c/(gamma*H*sin(beta)*cos(beta)) + tan(phi)/tan(beta) = 20/(18*8*sin30*cos30) + tan28/tan30 = 20/62.35 + 0.5317/0.5774 = 0.321 + 0.921 = 1.242
Result:FS = 1.242, marginally stable
Example 2: Cohesionless Sand Slope
Problem:Check stability of a 35-degree dry sand slope with phi = 33 degrees, no cohesion.
Solution:FS (friction only) = tan(33)/tan(35) = 0.6494/0.7002 = 0.927 Slope angle exceeds friction angle, so the slope is unstable.
Result:FS = 0.927, unstable
Frequently Asked Questions
What is the infinite slope method and when is it appropriate?
The infinite slope method analyzes slope stability by assuming the slope extends infinitely in all directions with a uniform thickness of potentially unstable soil. It is most appropriate for shallow planar failures where the depth of the failure surface is small compared to the slope length, such as soil slips on natural hillsides, colluvial deposits, and residual soils. The method is not suitable for deep-seated rotational failures, which require circular arc methods like Bishop or Spencer. It provides a quick, conservative estimate for preliminary slope assessments.
What is the stability number and how is it used in slope design?
The stability number (Ns = gamma * H / c) is a dimensionless parameter introduced by Taylor in 1937 for analyzing homogeneous slopes. It relates the unit weight, slope height, and cohesion into a single value that can be looked up on Taylor stability charts. For a given slope angle and friction angle, these charts provide the critical stability number at which failure occurs. If the actual stability number exceeds the critical value, the slope is expected to fail. This approach allows engineers to quickly determine the maximum safe height for a given slope angle and soil strength.
How does cohesion affect slope stability differently from friction angle?
Cohesion provides a constant shear resistance that is independent of the normal stress, making it most important for steep slopes and near the crest where normal stresses are low. The friction angle provides resistance proportional to the normal stress, so it becomes more significant at greater depths and for gentler slopes. A purely cohesive slope (phi = 0, like soft clay) has a critical height beyond which it cannot stand, while a purely frictional slope (c = 0, like dry sand) is stable at any height as long as the slope angle is less than the friction angle. Most real soils have both components.
What are common causes of slope failure in geotechnical practice?
Water infiltration is the most frequent trigger, raising pore pressures and reducing effective stress along potential failure surfaces. Erosion at the toe of the slope removes support, decreasing the factor of safety. Surcharge loading from construction, stockpiles, or buildings adds driving forces. Earthquake shaking induces additional inertial forces and can trigger liquefaction in saturated loose soils. Weathering gradually degrades the shear strength of exposed materials. Poor drainage design, rapid drawdown of reservoirs, and cutting into natural slopes without adequate retention are common engineering causes.
What does the critical height Hc represent and where does it come from?
Hc is the height at which a cohesive slope of angle beta reaches limiting equilibrium, so a cut taller than Hc cannot stand unsupported. The value shown here follows Culmann's plane-wedge solution, Hc = 4 c sin(beta) cos(phi) / (gamma x (1 - cos(beta - phi))). It assumes a single planar rupture surface through the toe in a homogeneous, drained soil with no tension crack and no water pressure. Because a real slip surface curves, Culmann overestimates Hc for gentle slopes and is best reserved for steep cuts and quick screening.
How does groundwater seepage parallel to the slope change the factor of safety?
With the water table at the ground surface and flow parallel to the slope, the friction term is multiplied by the ratio of buoyant to saturated unit weight, becoming (gamma-prime / gamma-sat) x tan(phi) / tan(beta). Since gamma-prime is gamma-sat minus the 9.81 kN/m3 unit weight of water, a soil at 20 kN/m3 keeps only about half its frictional resistance. That single factor explains why so many shallow hillside slips occur during prolonged rain, and why subsurface drains and cut-off trenches are such effective remedial measures.
Which unit weight should I enter: moist, saturated or buoyant?
Use the unit weight of the material actually present above the assumed slip plane under the condition being checked. A moist bulk unit weight, commonly 16 to 20 kN/m3 for soils, suits a dry or partly saturated hillside. Use the saturated unit weight, often 18 to 22 kN/m3, when the failure mass lies below the phreatic surface, and pair it with pore pressures rather than substituting the buoyant weight into the driving term as well. Mixing conventions is a frequent source of a factor of safety that looks unaccountably high.
What effect does a tension crack at the crest have on stability?
Cohesive soils cannot sustain the tensile stress that the analysis implies near the crest, so a vertical crack opens there. The crack shortens the length of slip surface over which cohesion can act, removing resistance, and if it fills with rainwater the hydrostatic thrust adds a driving force pushing the block downslope. Both effects reduce the factor of safety, and neither appears in the simple infinite slope expression. Sealing or draining crest cracks is a standard first response when tension cracking is observed on a moving slope.
Which stabilisation measure gives the largest gain in factor of safety?
It depends on which term is deficient. If the friction term is small because pore pressures are high, drainage is usually the cheapest and most effective option, since it restores effective stress along the whole slip surface. If the geometry is the problem, unloading the crest and building a toe buttress attacks the driving and resisting moments simultaneously. Where geometry cannot change, reinforcement such as soil nails, anchors or piles adds resistance directly. Toe erosion protection is essential whenever a stream or wave action is undercutting the slope.
When does a slope fail on a base circle rather than a toe circle?
Circular failures are classified by where the arc exits: a slope circle daylights on the face, a toe circle passes through the toe, and a base circle swings below the toe into the foundation soil. The controlling variables are the friction angle and the depth factor, the depth from the crest to a firm stratum divided by the slope height. In soft, near-frictionless clay on flatter slopes the critical arc tends to dig deep and becomes a base circle; steep slopes and appreciable friction pull it back to a toe circle. Borehole depth must reach below the suspected arc or the analysis misses the governing mechanism.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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