Shear Strength of Soil Calculator
Compute shear strength soil using validated scientific equations. See step-by-step derivations, unit analysis, and reference values.
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer
Shear Strength of Soil Calculator
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Formula: tau = c + (sigma - u) * tan(phi)
Worked example โ Effective shear strength = 56.19 kPa
Formula
tau = c + (sigma - u) * tan(phi)
Shear strength tau equals the cohesion c plus the effective normal stress (total normal stress sigma minus pore water pressure u) multiplied by the tangent of the friction angle phi. This is the Mohr-Coulomb criterion in effective stress form. When excess pore pressure is present, the effective stress is reduced, lowering the available shear strength.
Worked Examples
Example 1: Sandy Soil with Low Cohesion
Problem:Calculate shear strength of soil with c = 10 kPa, phi = 30 degrees, normal stress = 100 kPa, and pore pressure = 20 kPa.
Solution:Effective normal stress = 100 - 20 = 80 kPa tan(30) = 0.5774 Effective shear strength = 10 + 80 * 0.5774 = 56.19 kPa Total shear strength = 10 + 100 * 0.5774 = 67.74 kPa
Result:Effective shear strength = 56.19 kPa
Example 2: Undrained Clay Analysis
Problem:A saturated clay has undrained cohesion cu = 50 kPa and phi-u = 0 degrees under undrained conditions.
Solution:Shear strength = cu + sigma * tan(0) = 50 + 0 = 50 kPa Undrained strength is constant regardless of normal stress. This is the total stress approach for short-term loading.
Result:Undrained shear strength = 50 kPa (constant)
Frequently Asked Questions
What is the Mohr-Coulomb failure criterion?
The Mohr-Coulomb criterion is the most widely used model for predicting shear failure in soil. It states that shear strength on any plane equals the cohesion intercept plus the effective normal stress on that plane multiplied by the tangent of the internal friction angle. The two parameters, cohesion c and friction angle phi, can be determined from direct shear tests or triaxial compression tests. The failure envelope is a straight line on a Mohr diagram, and failure occurs when the Mohr circle of stress touches this line.
What is the difference between drained and undrained shear strength?
Drained shear strength applies when pore water can freely drain during loading, so no excess pore pressure builds up. This condition uses effective stress parameters c-prime and phi-prime and governs long-term stability. Undrained shear strength (Su or cu) applies when loading is too fast for drainage, common in saturated clays under rapid loading. In undrained conditions, the friction angle is effectively zero, and all resistance comes from cohesion. The choice between drained and undrained analysis depends on the loading rate relative to the permeability of the soil.
How are cohesion and friction angle determined from laboratory tests?
The most common methods are the direct shear test and the triaxial compression test. In a direct shear test, a soil sample is sheared along a predetermined plane at different normal stresses, and the peak shear stress is recorded for each. Plotting shear stress versus normal stress gives a straight line whose y-intercept is the cohesion and whose slope is tan(phi). Triaxial tests apply confining pressure and then increase the axial load until failure, producing Mohr circles at different confining pressures. The failure envelope tangent to these circles defines c and phi.
What are typical friction angle values for different soil types?
Loose sand typically has a friction angle of 28 to 32 degrees, medium dense sand ranges from 32 to 36 degrees, and dense sand can reach 36 to 42 degrees. Gravel usually has higher values, from 34 to 48 degrees. Normally consolidated clay has effective friction angles of 20 to 28 degrees, while overconsolidated clay ranges from 25 to 35 degrees. Silt falls between sand and clay at about 26 to 34 degrees. These values depend on grain shape, size distribution, mineralogy, and the density of the deposit.
What is soil composition and how is it measured?
Soil is composed of minerals (45%), organic matter (5%), water (25%), and air (25%). Texture is classified by percentages of sand (0.05-2mm), silt (0.002-0.05mm), and clay (less than 0.002mm) using the USDA soil texture triangle. Loam, an ideal garden soil, has roughly equal parts of each.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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