Liquefaction Potential Index Calculator
Calculate the Liquefaction Potential Index (LPI) from SPT data, earthquake magnitude, and site conditions.
Liquefaction Potential Index Calculator
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Formula: LPI = F(z) * w(z), where F = 1 - FS (if FS < 1), w = 10 - 0.5z
Worked example โ Factor of Safety and LPI computed with risk assessment
Formula
LPI = F(z) * w(z), where F = 1 - FS (if FS < 1), w = 10 - 0.5z
The Liquefaction Potential Index integrates the liquefaction severity function F over the top 20 meters of soil. F equals 1 minus the factor of safety when FS is below 1.0 (zero otherwise). The weighting function w decreases linearly with depth, reflecting that shallow liquefaction causes more surface damage. The factor of safety is the ratio of Cyclic Resistance Ratio (CRR) to Cyclic Stress Ratio (CSR).
Worked Examples
Example 1: Moderate Earthquake on Sandy Soil
Problem:Evaluate liquefaction potential for Mw = 7.5, PGA = 0.25g, SPT N = 12, depth = 5 m, water table at 2 m.
Solution:Calculate rd = 1 - 0.00765(5) = 0.962 Total stress = 5 * 18 = 90 kPa Effective stress = 2*18 + 3*(18-9.81) = 60.57 kPa CSR = 0.65 * (90/60.57) * 0.25 * 0.962 = 0.231 Correct N to N1-60, compute CRR, then FS and LPI.
Result:Factor of Safety and LPI computed with risk assessment
Example 2: Deep Soil Layer Assessment
Problem:Check liquefaction at 15 m depth with N = 25, Mw = 6.5, PGA = 0.15g, water table at 3 m.
Solution:At 15 m, rd = 1.174 - 0.0267(15) = 0.774 Higher N value yields higher CRR Smaller magnitude gives higher MSF (fewer cycles) Result: FS likely > 1.0, LPI contribution near zero.
Result:Low liquefaction risk at this depth
Frequently Asked Questions
What is the Liquefaction Potential Index and why does it matter?
The Liquefaction Potential Index (LPI) is a numerical measure that quantifies the overall severity of liquefaction at a site by integrating the factor of safety against liquefaction over the top 20 meters of soil. An LPI of zero means no liquefaction risk, while values above 15 indicate very high risk of ground failure. Engineers use LPI to assess earthquake hazards for building sites, bridge foundations, and critical infrastructure. It was developed by Iwasaki et al. in 1978 and has since become a standard tool in seismic hazard evaluation worldwide.
What soil conditions make liquefaction more likely?
Liquefaction is most likely in loose, saturated, cohesionless soils such as fine to medium sand, silty sand, and non-plastic silt. The water table must be close to the surface, typically within the top few meters. Young geological deposits like recently filled land, river deltas, and coastal sediments are particularly vulnerable. Denser soils with higher SPT blow counts (N values above 30) are generally resistant to liquefaction because the particles are tightly packed and less prone to rearranging under shaking.
How does earthquake magnitude affect the liquefaction calculation?
Earthquake magnitude influences the number of significant stress cycles applied to the soil. The Magnitude Scaling Factor (MSF) corrects the cyclic stress ratio to an equivalent earthquake magnitude of 7.5, which is the reference standard. Larger magnitude earthquakes produce more loading cycles, increasing the demand on the soil. For example, a magnitude 8.0 event produces roughly 20 equivalent cycles compared to about 10 cycles for a magnitude 6.5 event, making liquefaction significantly more likely at longer durations of shaking.
What is the SPT blow count and how is it used for liquefaction analysis?
The Standard Penetration Test (SPT) blow count N is the number of hammer blows needed to drive a split-spoon sampler 300 mm into the ground. It provides a direct measure of soil density and strength. For liquefaction analysis, the raw N value is corrected for overburden pressure, hammer energy, borehole diameter, and rod length to produce the normalized value N1-60. Soils with corrected blow counts below 15 are considered highly susceptible to liquefaction, while values above 30 generally indicate a non-liquefiable material.
What is the cyclic stress ratio, and why does the formula include a factor of 0.65?
The cyclic stress ratio expresses seismic demand as the average earthquake-induced shear stress divided by the vertical effective stress at that depth. A real acceleration record is irregular, with one dominant peak and many smaller cycles, so the simplified procedure replaces it with an equivalent series of uniform cycles at 65 percent of the peak shear stress. That convention, adopted with the Seed and Idriss method, is what allows a single scalar demand to be compared with laboratory cyclic resistance curves derived from constant-amplitude testing.
What does the stress reduction coefficient rd represent?
If the soil column were perfectly rigid, the shear stress at depth would equal the surface acceleration times the overlying mass. Soil is deformable, so the column does not move in phase from top to bottom and the induced shear stress is smaller than the rigid-body value. The coefficient rd captures that reduction and falls from 1.0 at the ground surface to well below 1 at depth. It is an average across many site profiles, so real scatter around it widens considerably below about 10 metres.
How does the depth of the water table change the computed demand?
Only saturated cohesionless soil can liquefy, because the mechanism requires pore water pressure to rise until it cancels the effective stress. Below the water table the soil contributes only its buoyant unit weight to effective stress, so the ratio of total to vertical effective stress climbs and the cyclic stress ratio rises with it. Lowering the water table raises effective stress, cuts the demand ratio and increases penetration resistance, which is why dewatering is sometimes used as a mitigation measure.
Why does the depth weighting function fall to zero at 20 metres?
The index is meant to predict damage visible at the ground surface, not liquefaction as such. A deep liquefied layer is separated from the surface by a thick non-liquefied crust that spreads and resists the upward escape of water and sand, so sand boils, settlement and bearing failure become progressively less likely as the source depth increases. The linear weight of 10 minus half the depth encodes that observation and vanishes at 20 metres, the depth beyond which case histories rarely show surface manifestation.
How do fines content and plasticity affect liquefaction resistance?
Non-plastic fines make penetration resistance read low for a given density, so corrected blow counts are shifted upward by a fines-content adjustment before the resistance curve is entered. Plasticity is a different matter: once the plasticity index rises above roughly the boundary of clay-like behaviour, the soil no longer liquefies in the classical sense but can still lose stiffness through cyclic softening, which is assessed against undrained shear strength rather than against a penetration-based resistance ratio.
What is the difference between liquefaction and lateral spreading?
Liquefaction is the loss of effective stress within a saturated granular layer during shaking. Lateral spreading is one of its consequences: the intact crust above a liquefied layer slides downslope or toward a free face such as a river bank or quay wall, often on gradients of only a few percent, and can travel metres while remaining broadly intact. The index quantifies triggering severity, not displacement, so a spreading assessment needs a separate empirical or numerical displacement model.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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