Planetary Density From Mass Radius Calculator
Free Planetary density mass radius Calculator for planetary & earth system science. Enter variables to compute results with formulas and detailed steps.
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer
Planetary Density From Mass Radius Calculator
Calculator
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Formula: rho = M / V = 3M / (4 * pi * R^3); g = GM / R^2; v_esc = sqrt(2GM / R)
Worked example โ Density 5513.4 kg/m3 (5.513 g/cm3) | 1.000x Earth | g = 9.82 m/s2 | v_esc = 11.19 km/s | Iron-rich rocky body. This is within about 0.01 percent of the 5514 kg/โฆ
Formula
rho = M / V = 3M / (4 * pi * R^3); g = GM / R^2; v_esc = sqrt(2GM / R)
M is the planet mass in kilograms, R its volumetric mean radius in metres, V = (4/3)*pi*R^3 the volume of the equivalent sphere, and rho the bulk (mean) density in kg/m3. G = 6.67430e-11 m3 kg-1 s-2 (CODATA 2018). In Earth-relative form the constants cancel: rho/rho_E = (M/M_E) / (R/R_E)^3, g/g_E = (M/M_E) / (R/R_E)^2, and v_esc/v_esc_E = sqrt((M/M_E) / (R/R_E)), with M_E = 5.9722e24 kg, R_E = 6371.0 km, rho_E = 5513 kg/m3, g_E = 9.82 m/s2 and v_esc_E = 11.19 km/s.
Worked Examples
Example 1: Earth, from SI inputs
Problem:Compute the bulk density, surface gravity, and escape velocity of Earth from its mass of 5.9722e24 kg and volumetric mean radius of 6371 km. Use G = 6.67430e-11 m3 kg-1 s-2.
Solution:R = 6371 km = 6.371e6 m R^3 = (6.371e6)^3 = 2.58597e20 m3 V = (4/3) * pi * 2.58597e20 = 1.08321e21 m3 rho = 5.9722e24 / 1.08321e21 = 5513.4 kg/m3 = 5.513 g/cm3 GM = 6.67430e-11 * 5.9722e24 = 3.98603e14 m3/s2 g = GM / R^2 = 3.98603e14 / 4.05896e13 = 9.82 m/s2 v_esc = sqrt(2GM / R) = sqrt(7.97205e14 / 6.371e6) = sqrt(1.25130e8) = 11186 m/s
Result:Density 5513.4 kg/m3 (5.513 g/cm3) | 1.000x Earth | g = 9.82 m/s2 | v_esc = 11.19 km/s | Iron-rich rocky body. This is within about 0.01 percent of the 5514 kg/m3 published in the NASA Earth Fact Sheet.
Example 2: Mars, from Earth-relative inputs
Problem:Mars has 0.1074 Earth masses and 0.5320 Earth radii. Find its bulk density, surface gravity, and escape velocity without converting to SI by hand.
Solution:Density ratio = (M/M_E) / (R/R_E)^3 = 0.1074 / 0.5320^3 = 0.1074 / 0.150569 = 0.7133 rho = 0.7133 * 5513.4 = 3932.7 kg/m3 = 3.933 g/cm3 Gravity ratio = (M/M_E) / (R/R_E)^2 = 0.1074 / 0.283024 = 0.37947 g = 0.37947 * 9.8203 = 3.73 m/s2 Escape ratio = sqrt((M/M_E) / (R/R_E)) = sqrt(0.1074 / 0.5320) = sqrt(0.20188) = 0.44931 v_esc = 0.44931 * 11.186 = 5.03 km/s Check in SI: M = 6.4141e23 kg, R = 3389.4 km, V = 1.63097e20 m3, rho = 6.4141e23 / 1.63097e20 = 3932.7 kg/m3
Result:Density 3932.7 kg/m3 (3.933 g/cm3) | 0.713x Earth | g = 3.73 m/s2 | v_esc = 5.03 km/s | Silicate rock dominated. The NASA Mars Fact Sheet lists 3933 kg/m3 and 5.03 km/s; its quoted surface gravity of 3.71 m/s2 is slightly lower because it includes rotation and oblateness.
Example 3: A 5 Earth-mass super-Earth
Problem:A transiting exoplanet is measured at 5.00 Earth masses and 1.60 Earth radii. Is it plausibly rocky?
Solution:Density ratio = 5.00 / 1.60^3 = 5.00 / 4.096 = 1.2207 rho = 1.2207 * 5513.4 = 6730.3 kg/m3 = 6.730 g/cm3 Gravity ratio = 5.00 / 1.60^2 = 5.00 / 2.56 = 1.9531 g = 1.9531 * 9.8203 = 19.18 m/s2 = 1.956 standard gravities Escape ratio = sqrt(5.00 / 1.60) = sqrt(3.125) = 1.76777 v_esc = 1.76777 * 11.186 = 19.77 km/s
Result:Density 6730.3 kg/m3 (6.730 g/cm3) | 1.221x Earth | g = 19.18 m/s2 | v_esc = 19.77 km/s | Iron-rich rocky body. A density above 5000 kg/m3 rules out any substantial hydrogen or ice envelope, and the value sits well above Earth's, as self compression of a rocky interior requires. It falls somewhat sh
Frequently Asked Questions
What is planetary bulk density and how is it calculated from mass and radius?
Planetary bulk density, also called mean density, is a body total mass divided by its total volume. Treating the planet as a sphere of radius R gives a volume of four thirds pi R cubed, so the density is rho equals 3M divided by 4 pi R cubed. It is one of the few planetary properties that requires no interior model at all: if you can weigh the planet and measure its size, the density follows from geometry alone. The result is normally quoted in kilograms per cubic metre, where liquid water is close to 1000, or in grams per cubic centimetre, where water is 1.00. Earth value of about 5513 kilograms per cubic metre is the highest of any planet in the Solar System.
What is the formula for planetary density from mass and radius?
The formula is rho equals M divided by V, with V equal to four thirds pi R cubed for a sphere, which simplifies to rho equals 3M divided by 4 pi R cubed. Mass must be in kilograms and radius in metres to get an answer in kilograms per cubic metre; if you enter radius in kilometres you must multiply by 1000 first, since a factor of 1000 in radius becomes a factor of one billion in volume. Working in Earth units removes the arithmetic entirely: the density ratio is simply the mass ratio divided by the cube of the radius ratio. A planet with 5 Earth masses and 1.6 Earth radii therefore has 5 divided by 1.6 cubed, or 1.221 times Earth density.
What is Earth density and how does it compare with the other planets?
Using the NASA fact sheet mass of 5.9722e24 kilograms and volumetric mean radius of 6371.0 kilometres, Earth mean density works out to about 5513 kilograms per cubic metre; the NASA fact sheet lists 5514, a difference of about 0.01 percent arising from the mass value used. The rest of the Solar System, in the same units, runs Mercury 5429, Venus 5243, Mars 3933, the Moon 3344, Neptune 1638, Jupiter 1326, Uranus 1270 and Saturn 687. Saturn is the striking case because 687 is below the density of liquid water. Earth is the densest planet as measured, although Mercury has the highest density once the effect of self compression is removed, which is why Mercury is considered the most iron-rich of the terrestrial planets.
Why is Earth bulk density higher than the density of the rocks at its surface?
Surface rocks are light compared with the planet as a whole. Granite is near 2700 kilograms per cubic metre and basalt near 2900, yet the bulk figure is 5513, roughly double. The difference is the interior. Seismic models such as PREM put the upper mantle near 3400, the base of the lower mantle near 5600, the liquid outer core between about 9900 and 12200, and the solid inner core near 13000 kilograms per cubic metre. The core occupies only about one sixth of Earth volume but supplies roughly a third of its mass. The gap between surface rock density and bulk density was in fact the earliest evidence that Earth has a dense metallic centre.
What does a planet density tell you about its composition?
Density is the first compositional diagnostic available for any newly measured planet. Values above roughly 5000 kilograms per cubic metre require a substantial iron core, since iron is about 7870 at laboratory pressure while silicate rock is 2700 to 3300. Values between about 3000 and 5000 indicate a rock dominated body with a small core, which covers the Moon at 3344 and Mars at 3933. Between about 2000 and 3000 you are looking at a mixture of rock and water ice, the regime of Ceres at 2162 and Triton at 2061. Below about 2000 the body must contain a large ice fraction or a thick hydrogen and helium envelope, which is where all four giant planets sit. Density alone cannot separate every possibility, because different mixtures can produce the same mean value, but it rules out large families of compositions immediately.
How much does an error in the radius affect the calculated density?
A great deal more than an error in the mass. Because density is proportional to mass but inversely proportional to the cube of the radius, the fractional error in density equals the fractional error in mass minus three times the fractional error in radius. A one percent radius error therefore produces a three percent density error, while a one percent mass error produces only a one percent density error. This asymmetry drives observational strategy for exoplanets, where the radius comes from the depth of a transit and the mass from a radial velocity amplitude. It is also why a five percent radius uncertainty, which sounds modest, is enough to leave a small planet ambiguous between a rocky and a volatile-rich interpretation.
Which radius should I use: equatorial, polar, or mean?
Use the volumetric mean radius, which is the radius of a sphere with the same volume as the real oblate body. NASA fact sheets publish it alongside the equatorial and polar values for exactly this reason. For Earth the difference is small, with equatorial 6378.1 kilometres, polar 6356.8 and volumetric mean 6371.0, so the choice changes the answer by only a few tenths of a percent. For a rapidly rotating giant it matters enormously. Saturn has an equatorial radius of 60268 kilometres against a volumetric mean of 58232, and substituting the equatorial value would understate its density by about ten percent. Anything with significant flattening needs the mean radius.
How are surface gravity and escape velocity related to planetary density?
Both follow from the same two inputs. Surface gravity is g equals GM divided by R squared, and substituting the mass of a uniform sphere turns this into g equals four thirds pi G rho R, so for a fixed density gravity grows in direct proportion to radius. Escape velocity is v equals the square root of 2GM divided by R, which becomes R times the square root of eight thirds pi G rho, again linear in radius at fixed density. For Earth these give 9.82 metres per second squared and 11.19 kilometres per second. The conventional standard gravity of 9.80665, an exact value fixed by definition rather than a measurement, is slightly lower because the real planet is oblate and rotating, effects the spherical formula does not include.
How do astronomers measure the density of an exoplanet?
They combine two independent techniques. A transit gives the planet radius, because the fractional dip in starlight equals the ratio of the planet area to the stellar area, so the planet radius follows once the star radius is known. Radial velocity measurements of the star wobble give the planet mass, subject to the orbital inclination, which a transit conveniently fixes at close to ninety degrees. With both in hand the density follows directly. This was first done for HD 209458 b, seen in transit in 1999, which turned out to have a density of only about a third that of water and so could not possibly be rocky. Transit timing variations in multi-planet systems provide a third route to mass where the star is too faint for radial velocities.
What is uncompressed density and why do planetary scientists use it?
Bulk density is not the same as the density of the material a planet is made from, because the deep interior is squeezed by the weight of everything above it. A larger planet made of exactly the same stuff as a smaller one will therefore appear denser. Uncompressed density is the value the same material would have at zero pressure, obtained by modelling the interior with laboratory equations of state and removing the compression. Earth measured 5513 kilograms per cubic metre corresponds to an uncompressed value estimated near 4000. This correction is what allows a fair comparison between bodies of very different size, and it is the reason Mercury is judged more iron-rich than Earth despite having the slightly lower measured density.
References
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Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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