Tidal Force Calculator
Calculate the tidal force between two bodies from their masses, the distance between their centres, and the radius of the body being stretched.
Tidal Force Calculator
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Formula: F_tidal = 2GMmr / d³
Worked example — F: 6.565e18 N | Tidal acceleration: 1.099e-6 m/s^2
Formula
F_tidal = 2GMmr / d³
Tidal force is the difference in gravitational pull across an extended body, not gravity itself. M is the tide-raising mass, m the mass being stretched, r its radius and d the centre-to-centre separation, with G = 6.674×10⁻¹¹ N⋅m²/kg². Because the leading term goes as 1/d³ rather than 1/d², halving the separation multiplies the tide by eight while ordinary attraction only quadruples. Dividing by m gives the tidal acceleration 2GMr/d³, which is what sets the height of the equilibrium bulge.
Worked Examples
Example 1: The Moon's Tidal Force on Earth
Problem:Find the tide-raising force and the differential acceleration the Moon exerts across Earth. Moon mass 7.342e22 kg, Earth mass 5.972e24 kg, Earth radius 6.371e6 m, mean separation 3.844e8 m.
Solution:d^3 = (3.844e8)^3 = 5.680e25 m^3 F = 2 G M m r / d^3 = 2 x 6.674e-11 x 7.342e22 x 5.972e24 x 6.371e6 / 5.680e25 Numerator = 2 x 6.674e-11 x 7.342e22 = 9.800e12; x 5.972e24 = 5.853e37; x 6.371e6 = 3.729e44 F = 3.729e44 / 5.680e25 = 6.565e18 N Tidal acceleration a = 2 G M r / d^3 = 1.099e-6 m/s^2, about one nine-millionth of Earth's surface gravity of 9.81 m/s^2.
Result:F: 6.565e18 N | Tidal acceleration: 1.099e-6 m/s^2
Example 2: Sun Versus Moon: Why the Moon Wins
Problem:The Sun is 27 million times more massive than the Moon but 390 times farther away. Compare the two tide-raising accelerations on Earth. Sun mass 1.989e30 kg at 1.496e11 m.
Solution:Solar tidal acceleration = 2 x 6.674e-11 x 1.989e30 x 6.371e6 / (1.496e11)^3 = 5.052e-7 m/s^2 Lunar tidal acceleration (above) = 1.099e-6 m/s^2 Ratio = 5.052e-7 / 1.099e-6 = 0.46, so the Sun raises about 46 percent of the lunar tide Mass ratio favours the Sun by 2.7e7, but the inverse-cube distance term costs it 390^3 = 5.9e7, and 2.7e7 / 5.9e7 = 0.46. Spring tides occur when the two align and their bulges add; neap tides when they are at right angles and the solar bulge partly cancels the lunar one.
Result:Solar: 5.052e-7 m/s^2 | Lunar: 1.099e-6 m/s^2 | Solar tide is 46% of lunar
Example 3: Jupiter on Io, and the Roche Limit
Problem:Jupiter (1.898e27 kg) holds Io (8.932e22 kg, radius 1.822e6 m) at 4.217e8 m. Find the tidal acceleration across Io and check how far it sits from Jupiter's Roche limit.
Solution:Tidal acceleration = 2 x 6.674e-11 x 1.898e27 x 1.822e6 / (4.217e8)^3 = 6.154e-3 m/s^2 That is 5,600 times the lunar tidal acceleration on Earth, and combined with Io's forced eccentricity it drives the most vigorous volcanism in the solar system. Fluid Roche limit d_Roche = 2.44 x R_Jupiter x (rho_Jupiter / rho_Io)^(1/3) = 2.44 x 69,911 km x (1326 / 3528)^(1/3) = 2.44 x 69,911 x 0.7215 = 123,100 km Io orbits at 421,700 km, comfortably outside that limit, so self-gravity keeps it intact even under this enormous tide.
Result:Tidal acceleration on Io: 6.15e-3 m/s^2 | Roche limit: ~123,100 km | Io orbits at 421,700 km
Frequently Asked Questions
Why does tidal force depend on d³?
Tidal force is the difference in gravity across an object, which falls off as the cube of distance — much faster than gravity itself (d²). This is why you must be very close to feel tidal effects.
What is the Roche limit and how is it related to tidal force?
The Roche limit is the minimum orbital distance at which a moon or satellite held together only by self-gravity can survive tidal forces from its host planet. Inside this distance, tidal forces exceed the moon's self-gravitational binding and tear it apart, forming a ring system. Saturn's rings are thought to be remnants of a moon or comet that crossed the Roche limit. The Roche limit scales as the cube root of the density ratio between the bodies.
How do tidal forces cause ocean tides on Earth?
The Moon's tidal force creates two tidal bulges on Earth: one facing the Moon (stronger gravity stretches the ocean toward it) and one on the opposite side (weaker gravity leaves the ocean behind). As Earth rotates under these bulges, most coastal locations experience two high tides and two low tides per day. The Sun contributes about 46% as much tidal force as the Moon — spring tides occur when both align, creating maximum tidal ranges.
What is tidal locking and how long does it take?
Tidal locking occurs when tidal dissipation slows a body's rotation until its orbital period equals its rotation period, causing one face to always point toward the host body. The Moon is tidally locked to Earth (we always see the same side). The timescale for tidal locking scales strongly with orbital distance (a⁶) and the body's size — closer bodies with high-rigidity interiors lock fastest. Many of the largest moons in the solar system are tidally locked to their host planets.
What is the difference between the semidiurnal and diurnal tidal constituents?
Both groups come from the same differential gravitational field, but from different parts of it. The semidiurnal constituents such as M2 and S2 follow the two-bulge symmetry of the tidal force, so a port rotates through both bulges and sees two highs a day. The diurnal constituents K1 and O1 appear only when the Moon or Sun lies away from the equator, tilting the bulges so one daily passage is stronger. Because tidal force falls as the cube of distance, the lunar terms lead in both groups.
What is the difference between spring tides and neap tides?
Spring tides occur at new and full Moon, when the Sun and Moon are in syzygy and their tide-raising forces add, producing the largest tidal range of the fortnight. Neap tides occur at first and last quarter, when the two bodies are in quadrature and the solar bulge partly fills the lunar trough, cutting the range. Because the solar contribution is about 46 percent of the lunar one, spring ranges are typically two to three times neap ranges at the same port.
What is the difference between the equilibrium tide and the dynamic tide?
The equilibrium tide is the static bulge an ocean of uniform depth would take if it responded instantly to the tidal potential — only about half a metre for the Moon. The dynamic tide, described by the Laplace tidal equations, treats the tide as a forced shallow-water wave in a rotating, basin-bounded ocean. Resonance, friction and the Coriolis force reorganise it into rotary systems around amphidromic points, where the range is near zero, and amplify it enormously in funnel-shaped bays.
Why does tidal friction lengthen Earth's day and push the Moon outward?
Ocean friction drags the tidal bulge a little ahead of the Earth–Moon line, because Earth spins faster than the Moon orbits. The leading bulge exerts a torque that accelerates the Moon along its orbit while an equal and opposite torque brakes Earth's spin. Angular momentum is conserved, so the Moon's orbit expands — lunar laser ranging measures about 3.8 cm per year — while the length of day grows by a few milliseconds per century.
How does tidal heating keep Io volcanically active?
Io is locked in a 1:2:4 Laplace resonance with Europa and Ganymede, and the repeated conjunctions pump its orbital eccentricity. Because the tide-raising force varies as 1/d³, an eccentric orbit means the height and orientation of Jupiter's tidal bulge on Io change every orbit. Flexing a partly rigid interior dissipates that strain energy as heat, and the resulting internal melting drives the most vigorous volcanism in the solar system.
Why does a tidal field stretch a body along one axis while squeezing it along the others?
The tidal field is the gradient of gravity, so it is best pictured as a tensor rather than a single pull. Along the line joining the two bodies the near side is pulled harder and the far side less hard than the centre, producing extension in both directions. Perpendicular to that line the attraction converges toward the primary's centre, giving a compressive component of roughly half the stretching value. The net result is the familiar prolate two-bulge shape.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer · Editorial policy
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