Latitude Coriolis Deflection Calculator
Calculate latitude coriolis deflection with our free science calculator. Uses standard scientific formulas with unit conversions and explanations.
Reviewed by Daniel Agrici, Founder & Lead Developer
Formula
d = 0.5 x f x v x t2
Where d is the lateral deflection in meters, f is the Coriolis parameter (2*omega*sin(latitude)) in s-1, v is the object speed in m/s, and t is the travel time in seconds. The deflection is to the right of motion in the Northern Hemisphere and to the left in the Southern Hemisphere.
Worked Examples
Example 1: Long-Range Artillery Deflection
Problem:An artillery shell is fired at 800 m/s to a target 20 km away at 45 N latitude. Calculate the Coriolis deflection.
Solution:f = 2 x 7.2921e-5 x sin(45) = 1.031e-4 s-1\nTravel time = 20,000 / 800 = 25 s\nDeflection = 0.5 x 1.031e-4 x 800 x 25^2\n= 0.5 x 1.031e-4 x 800 x 625\n= 25.78 m to the right\nDeflection angle = atan(25.78/20000) = 0.074 degrees
Result:Deflection: 25.78 m to the right | Angle: 0.074 deg | Must correct for targeting
Example 2: Aircraft Cross-Track Deviation
Problem:An aircraft flies at 250 m/s (900 km/h) for 1000 km at 60 N latitude with no course corrections. How far off course would it drift?
Solution:f = 2 x 7.2921e-5 x sin(60) = 1.263e-4 s-1\nTravel time = 1,000,000 / 250 = 4,000 s\nDeflection = 0.5 x 1.263e-4 x 250 x 4000^2\n= 0.5 x 1.263e-4 x 250 x 16,000,000\n= 252,600 m = 252.6 km\nRossby number = 250 / (1.263e-4 x 1,000,000) = 1.98
Result:Deflection: 252.6 km to the right | Rossby No: 1.98 | Significant correction needed
Frequently Asked Questions
What is Coriolis deflection and how does it affect moving objects?
Coriolis deflection is the apparent sideways displacement of an object moving in a straight line relative to Earth's surface, caused by Earth's rotation. In a rotating reference frame (standing on Earth), a freely moving object appears to curve to the right in the Northern Hemisphere and to the left in the Southern Hemisphere. The deflection occurs because Earth rotates beneath the moving object during its travel time. The magnitude of deflection depends on the object's speed, the distance traveled, and the latitude. At the equator, the deflection is zero, and it increases with latitude, reaching maximum at the poles. This effect is negligible for short-range everyday motion like walking or driving but becomes significant for long-range phenomena such as atmospheric wind patterns, ocean currents, and long-range military projectiles.
How do you calculate the lateral deflection distance?
The lateral deflection of a horizontally moving object due to the Coriolis effect is calculated using d = 0.5 times f times v times t-squared, where d is the lateral displacement in meters, f is the Coriolis parameter (2 times omega times sin of latitude), v is the speed of the object in meters per second, and t is the travel time in seconds. Alternatively, since t = distance/speed, the deflection can be expressed as d = 0.5 times f times distance-squared divided by speed. This formula assumes constant speed, no other lateral forces, and a flat-Earth approximation valid for distances much smaller than Earth's radius. The quadratic dependence on time (or distance) means that doubling the travel distance quadruples the deflection, making the effect increasingly important for longer trajectories.
Is the Coriolis effect real or just an apparent force?
The Coriolis effect is a fictitious or pseudo force that exists only within rotating reference frames such as Earth's surface. An observer in an inertial (non-rotating) reference frame watching from space would see the object traveling in a perfectly straight line while Earth rotates beneath it. However, for all practical purposes on Earth, the Coriolis force is as real as any other force because we live and work in Earth's rotating reference frame. The Coriolis acceleration is measurable and has real, observable consequences for large-scale fluid flows, weather systems, and ocean currents. Just as centrifugal force is fictitious but produces real effects in rotating systems, the Coriolis force must be included in the equations of motion for any analysis conducted in Earth's reference frame. Ignoring it leads to incorrect predictions for large-scale motions.
Does the Coriolis effect influence draining bathtubs and toilets?
No, the Coriolis effect does not determine the direction water drains in bathtubs, sinks, or toilets. This is one of the most persistent misconceptions in popular science. The Coriolis deflection for water draining from a typical bathtub is on the order of a few micrometers, which is millions of times smaller than the effects of the basin shape, residual water motion, small asymmetries in the drain, and water surface disturbances. Carefully controlled experiments by Ascher Shapiro in 1962 did demonstrate that the Coriolis effect can influence drain rotation, but only in perfectly symmetric tanks that were left undisturbed for many hours to eliminate all residual circulation. In everyday situations, the drain rotation direction is determined by random initial conditions and basin geometry, not by the hemisphere. The Coriolis effect only becomes significant for fluid motions over large distances and long time periods.
References
Reviewed by Daniel Agrici, Founder & Lead Developer · Editorial policy