Aquifer Transmissivity Calculator
Calculate aquifer transmissivity from hydraulic conductivity and thickness. Estimate well yield and aquifer productivity for groundwater resource
Aquifer Transmissivity Calculator
Calculator
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Formula: Transmissivity (T) = K x b
Worked example โ T = 2160 m2/day | High productivity | Excellent for municipal supply
Formula
Transmissivity (T) = K x b
Transmissivity equals hydraulic conductivity (K, in m/s) multiplied by aquifer thickness (b, in meters). The result in m2/s can be converted to m2/day by multiplying by 86,400. The Thiem equation provides an alternative: T = Q x ln(R/r) / (2 x pi x s), where Q is pumping rate, R is radius of influence, r is well radius, and s is drawdown.
Worked Examples
Example 1: Sand and Gravel Aquifer
Problem:Hydraulic conductivity K = 0.001 m/s, aquifer thickness b = 25 m.
Solution:T = K x b = 0.001 x 25 = 0.025 m2/s T = 0.025 x 86400 = 2160 m2/day Aquifer class: High productivity Estimated well yield: 2160 x 1.3 = 2808 m3/day
Result:T = 2160 m2/day | High productivity | Excellent for municipal supply
Example 2: Fractured Limestone Aquifer
Problem:K = 0.00005 m/s, b = 40 m.
Solution:T = 0.00005 x 40 = 0.002 m2/s T = 0.002 x 86400 = 172.8 m2/day Aquifer class: Moderate productivity Estimated well yield: 172.8 x 1.3 = 224.6 m3/day
Result:T = 172.8 m2/day | Moderate productivity | Suitable for small community
Frequently Asked Questions
What is aquifer transmissivity?
Transmissivity (T) is the rate at which water flows through a unit width of an aquifer under a unit hydraulic gradient. It equals the product of hydraulic conductivity (K) and aquifer thickness (b): T = K x b. Units are typically m2/s or m2/day. Transmissivity integrates the flow capacity of the entire aquifer thickness into a single parameter, making it more practical than hydraulic conductivity alone for predicting well yields and regional groundwater flow rates.
How is transmissivity determined from pumping tests?
Pumping tests are the most reliable method for determining transmissivity. The Theis method and Cooper-Jacob straight-line method analyze drawdown versus time data from observation wells during a constant-rate pumping test. The Thiem equation uses steady-state drawdown data from two observation wells at different distances from the pumping well. These field methods capture the integrated properties of the aquifer including heterogeneity effects that laboratory tests on core samples would miss.
What transmissivity values indicate a productive aquifer?
Aquifer productivity classifications based on transmissivity are: greater than 500 m2/day is considered high productivity suitable for municipal water supply; 50-500 m2/day is moderate productivity adequate for irrigation and small communities; 5-50 m2/day is low productivity suitable only for domestic wells; and less than 5 m2/day is very low productivity with limited groundwater potential. Alluvial aquifers often have transmissivities of 100-1000 m2/day, while fractured bedrock typically ranges from 1-100 m2/day.
How does transmissivity relate to well yield?
Well yield is directly proportional to transmissivity. A rough estimate is that sustainable well yield (in m3/day) is approximately 1.0 to 1.5 times the transmissivity value (in m2/day) for a properly designed well. Higher transmissivity means the aquifer can deliver water to the well faster, resulting in less drawdown for a given pumping rate. Specific capacity (pumping rate divided by drawdown) provides a field-based indicator that correlates with transmissivity through empirical relationships.
What is the difference between transmissivity and storativity?
Transmissivity describes how fast an aquifer moves water, while storativity, also called the storage coefficient S, describes how much water it releases from storage per unit area per unit head decline. Transmissivity controls the shape and slope of the drawdown cone; storativity controls how quickly that cone expands with time. Confined aquifers release water by expansion of water and compression of the skeleton, giving S values near 0.00001 to 0.001, whereas unconfined aquifers drain pores directly and behave with a specific yield of roughly 0.05 to 0.30.
Why does transmissivity change during pumping in an unconfined aquifer?
Because T = K * b and, in an unconfined aquifer, b is the saturated thickness measured up to the water table. Pumping lowers that water table, so the transmitting thickness and therefore the transmissivity both shrink as drawdown grows, which makes drawdown increase faster than linearly with pumping rate. Analysts apply the Jacob correction, replacing observed drawdown s with s - s^2 / (2 * b0), before using confined-aquifer solutions. Confined aquifers avoid this entirely because the full thickness stays saturated as long as head remains above the top of the unit.
How does specific capacity relate to transmissivity?
Specific capacity is the pumping rate divided by the stabilised drawdown in the pumped well, Q/s, and is the cheapest field indicator of aquifer performance because it needs no observation wells. It correlates with transmissivity but is not equal to it, since specific capacity also absorbs well losses, partial penetration and screen condition. A common practice is to build a site-specific regression between specific capacity and transmissivity from wells that do have pumping-test data, then apply it to wells that only have driller records.
When should I use Cooper-Jacob instead of the full Theis solution?
The Cooper-Jacob straight-line method is a logarithmic approximation of the Theis well function that becomes accurate only after early time effects fade, conventionally once the dimensionless variable u = r^2 * S / (4 * T * t) falls below about 0.01. In practice that means late-time data in observation wells close to the pumping well. Use the full Theis type-curve match for early data, for distant observation wells, or when the pumping period is short; use Cooper-Jacob when late drawdown plots as a clean straight line against log time.
How does a leaky confining layer bias a transmissivity estimate?
In a semi-confined or leaky aquifer, vertical seepage through the overlying aquitard feeds the pumped unit, so drawdown stops deepening and the time-drawdown curve flattens toward a steady state. Fitting that flattened curve with a confined Theis or Cooper-Jacob solution attributes the extra water to the aquifer itself and overestimates transmissivity. The Hantush-Jacob leaky solution handles this by introducing a leakage factor that separates aquitard contribution from aquifer transmission, so recognising the flattening early matters more than refining the curve fit.
Why is the Thiem result sensitive to the radius of influence?
The Thiem equation carries the distance term inside a natural logarithm, T = Q * ln(R / r) / (2 * pi * s), so the estimate depends on the ratio of the radius of influence to the well radius rather than on either value alone. Doubling an assumed R changes ln(R/r) by only about 0.69, which is a modest shift when the logarithm is already near 5 or 6. That makes the method tolerant of a rough R but very intolerant of a wrong drawdown, since s enters directly. Well losses inflate the drawdown measured inside the pumped well, so use an observation well where possible.
References
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Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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