Tectonic Stress Calculator
Calculate lithostatic, tectonic, and effective stresses at depth. Includes pore pressure, horizontal stress ratio, and Mohr-Coulomb failure analysis.
Tectonic Stress Calculator
Calculator
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Formula: Sv = rho*g*z | Sh = (nu/(1-nu))*Sv + E*epsilon
Worked example โ Sv = 264.87 MPa, Sh = 88.29 MPa
Formula
Sv = rho*g*z | Sh = (nu/(1-nu))*Sv + E*epsilon
Vertical stress Sv equals rock density times gravity times depth. Horizontal stress Sh combines the lithostatic ratio K0 = nu/(1-nu) times Sv with any tectonic strain contribution. Effective stress equals total stress minus pore fluid pressure.
Worked Examples
Example 1: Stress at 10 km Depth
Problem:Calculate the vertical and horizontal stresses at 10 km depth in granite (density 2700 kg/m^3, Poisson ratio 0.25).
Solution:Sv = 2700 * 9.81 * 10000 = 264.87 MPa Pp = 1000 * 9.81 * 10000 = 98.1 MPa K0 = 0.25/0.75 = 0.333 Sh = 0.333 * 264.87 = 88.29 MPa Differential stress = 264.87 - 88.29 = 176.58 MPa
Result:Sv = 264.87 MPa, Sh = 88.29 MPa
Example 2: With Tectonic Strain
Problem:Add a tectonic strain of 1e-4 (E = 50 GPa) to the above scenario.
Solution:Tectonic stress = 50e9 * 1e-4 = 5 MPa Sh_total = 88.29 + 5 = 93.29 MPa Differential stress = 264.87 - 93.29 = 171.58 MPa
Result:Sh increases from 88.29 to 93.29 MPa
Frequently Asked Questions
What is tectonic stress?
Tectonic stress is the stress within the Earth's crust caused by the forces driving plate tectonics, including ridge push, slab pull, and mantle convection. It adds to the gravitational lithostatic stress that increases with depth. Tectonic stress determines whether faults are in compression (thrust faulting), extension (normal faulting), or shear (strike-slip faulting). The total stress state at any point in the crust is the sum of gravitational and tectonic contributions, and it controls where and how earthquakes occur.
How does lithostatic stress vary with depth?
Lithostatic (or overburden) stress increases linearly with depth according to Sv = rho * g * z, where rho is rock density, g is gravitational acceleration, and z is depth. For typical crustal rocks with density 2700 kg/m^3, the vertical stress gradient is approximately 26.5 MPa per kilometer of depth. At 10 km depth, the vertical stress is roughly 265 MPa. This simple relationship assumes constant density, though in reality density increases with depth due to compaction and phase changes.
What is the difference between total and effective stress?
Total stress is the force per unit area from the combined weight of rock and fluid above a point. Effective stress is the total stress minus the pore fluid pressure: sigma_eff = sigma_total - Pp. Effective stress is what actually acts on rock grains and controls rock failure, deformation, and fault slip. When pore pressure increases (for example from fluid injection), effective stress decreases, making faults more likely to slip. This principle, first formulated by Terzaghi, is fundamental to understanding earthquake triggering and induced seismicity.
What is Anderson's theory of faulting?
Anderson's theory classifies fault types based on which principal stress is vertical. If the maximum principal stress (S1) is vertical, normal faults form in an extensional regime. If the minimum principal stress (S3) is vertical, thrust or reverse faults form in a compressive regime. If the intermediate stress (S2) is vertical, strike-slip faults form. This framework predicts fault orientation and stress regime from the relative magnitudes of vertical and horizontal stresses, and is widely used in structural geology and petroleum engineering.
What does the coefficient K0 = nu/(1-nu) assume?
It comes from the uniaxial strain, or confined lateral, model: a rock element is loaded vertically by its overburden and is prevented from expanding sideways by the surrounding mass, so the horizontal stress it develops is set purely by its Poisson ratio. For nu = 0.25 this gives K0 = 0.333. The assumption is elastic, gravitational and history-free, so it is a floor rather than a forecast. Measured horizontal stresses frequently exceed it, particularly at shallow depth, because tectonic strain, erosion and thermal effects are all excluded.
How is in-situ stress actually measured in the crust?
Magnitudes come mainly from hydraulic fracturing, where a sealed borehole interval is pressurised until the rock breaks and the shut-in pressure gives the minimum horizontal stress, and from overcoring, which measures the strain relief of a core as it is freed from the rock mass. Orientations are read from borehole breakouts, which elongate along the minimum horizontal stress, and from drilling-induced tensile fractures, which align with the maximum. Earthquake focal mechanisms give regional stress directions, and these observations are compiled into world stress maps.
What is the difference between hydrostatic and overpressured pore pressure?
A hydrostatic column of fresh water gives about 9.8 MPa per kilometre, which is the value Tectonic Stress Calculator assumes, against roughly 26.5 MPa per kilometre for rock at 2700 kg/m3. Overpressure develops where fluid cannot escape as fast as it is loaded or generated, through rapid burial of low-permeability shale, hydrocarbon maturation, or clay mineral dehydration, and the gradient then climbs toward lithostatic. Since effective stress is total stress minus pore pressure, overpressured intervals are weak, prone to fault reactivation and dangerous to drill.
What is the difference between differential stress, mean stress and deviatoric stress?
Differential stress is simply the largest principal stress minus the smallest, and it is the quantity that drives shear failure; it is the diameter of the Mohr circle. Mean stress is the average of the three principal stresses and represents the isotropic part, which compresses the rock without distorting it. Deviatoric stress is what remains once the mean is subtracted, and it is the part responsible for shape change, faulting and ductile flow. Rocks fail on the deviatoric component, not on the absolute stress level.
Why is there an upper limit on how much differential stress the crust can hold?
Because a crust laced with existing faults cannot support stress beyond the level at which some favourably oriented fault slips. Byerlee's experiments showed that the frictional strength of most rock types collapses onto a narrow band, with a coefficient of friction of roughly 0.6 to 0.85 over a wide range of normal stress and largely independent of lithology. Combining that friction law with the effective vertical stress bounds the sustainable differential stress at any depth, and raising pore pressure lowers the bound proportionally.
How does erosion or the removal of an ice sheet change the stress state?
Stripping overburden reduces the vertical stress immediately and in direct proportion to the thickness removed. The horizontal stress relaxes far less, because lateral confinement by the surrounding rock mass prevents the outward expansion that would be needed to shed it. The ratio of horizontal to vertical stress therefore rises sharply toward the surface, which is why shallow excavations and tunnels in formerly deeply buried or glaciated terrain experience rock bursts, spalling, sheeting joints and valley-floor buckling.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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