Stress Drop Calculator
Calculate earthquake stress drop from seismic moment and fault dimensions or corner frequency using the Brune source model.
Stress Drop Calculator
Calculator
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Formula: Stress Drop = (7/16) * M0 / r^3
Worked example โ Stress drop = 3.92 MPa (39.2 bar)
Formula
Stress Drop = (7/16) * M0 / r^3
For a circular fault, stress drop equals (7/16) times the seismic moment M0 divided by the cube of the fault radius r (Eshelby, 1957). The fault radius can be estimated from the corner frequency using the Brune (1970) model.
Worked Examples
Example 1: M6.0 Earthquake with 5 km Fault Radius
Problem:Calculate stress drop for M0 = 1.12e18 N*m and circular fault radius of 5 km.
Solution:Stress drop = (7/16) * M0 / r^3 = (7/16) * 1.12e18 / (5000)^3 = 0.4375 * 1.12e18 / 1.25e11 = 3.92e6 Pa = 3.92 MPa = 39.2 bar
Result:Stress drop = 3.92 MPa (39.2 bar)
Example 2: Stress Drop from Corner Frequency
Problem:Estimate stress drop for a Mw 4.0 earthquake with corner frequency of 3.5 Hz.
Solution:M0 = 10^(1.5*4+9.1) = 1.26e15 N*m r = 2.34*3500/(2*pi*3.5) = 372.6 m Stress drop = (7/16)*1.26e15/372.6^3 = 10.65 MPa
Result:Stress drop = 10.65 MPa, source radius = 373 m
Frequently Asked Questions
What is earthquake stress drop?
Stress drop is the difference between the stress on a fault before and after an earthquake. It represents the amount of shear stress released during fault slip, measured in units of pressure (Pa, MPa, or bars). For most tectonic earthquakes, stress drops range from about 0.1 to 100 MPa, with a typical value around 1-10 MPa. Stress drop is a key parameter controlling the strength of high-frequency ground motion and is important for seismic hazard assessment.
What is the Brune source model?
The Brune (1970) source model describes the earthquake source spectrum as a simple function with a flat level at low frequencies proportional to the seismic moment, and a decay at high frequencies above a corner frequency fc. The corner frequency is inversely proportional to the source dimension: r = 2.34*Vs/(2*pi*fc). Combined with the seismic moment, the corner frequency allows estimation of the stress drop. This model is widely used in engineering seismology and ground motion prediction because of its simplicity and reasonable agreement with observations.
How does stress drop relate to earthquake damage?
Higher stress drop earthquakes produce relatively stronger high-frequency ground motion, which is more damaging to short-period structures such as one- to two-story buildings. Two earthquakes with the same magnitude but different stress drops will produce different shaking characteristics. A high stress drop event radiates more energy per unit fault area and generates stronger acceleration pulses. This is why stress drop is an important parameter in ground motion prediction equations used for seismic building code design.
What controls the stress drop of an earthquake?
Stress drop depends on fault roughness, rock strength, confining pressure, pore fluid pressure, and slip history. Interplate earthquakes (at plate boundaries) typically have lower stress drops of 1-5 MPa, while intraplate earthquakes (within tectonic plates) tend to have higher stress drops of 5-50 MPa. Deeper earthquakes generally have higher stress drops due to increased confining pressure. Some studies suggest that stress drop is approximately constant (self-similar) across magnitude ranges, but this remains debated in seismology.
What is seismic moment and how does it convert to moment magnitude?
Seismic moment is M0 = mu x A x D, the shear modulus of the rock multiplied by the ruptured fault area and the average slip, with units of newton metres. Crustal shear modulus is around 30 GPa, so a rupture of 100 square kilometres slipping 0.5 metres gives M0 near 1.5e18 N m. Moment magnitude follows from Mw = (2/3) x (log10 M0 - 9.1), the Hanks and Kanamori scale. Because moment is a physical quantity rather than an instrument reading, it does not saturate for great earthquakes the way older magnitude scales do.
What is the difference between static stress drop and apparent stress?
Static stress drop compares the shear stress on the fault before and after slip, so it is a before-and-after difference inferred from moment and rupture dimension, which is what Stress Drop Calculator returns. Apparent stress is mu multiplied by the radiated seismic energy divided by the seismic moment, and it measures how much energy the rupture actually broadcast as waves rather than consuming in friction and fracture. The two are related but not equal: the radiation efficiency is twice the apparent stress divided by the static stress drop, and that ratio tells you how much of the released energy was broadcast rather than dissipated.
Why do published stress drops for the same earthquake differ by an order of magnitude?
Stress drop scales with the inverse cube of source radius, so a 30 percent error in radius changes the answer by more than a factor of two. Radius comes from corner frequency, and corner frequency trades off strongly against the attenuation parameter used to correct the spectrum: too little attenuation correction pushes fc down and stress drop with it. Add the choice of source model constant, the assumed shear velocity, radiation pattern and directivity, and scatter of one to two orders of magnitude across studies is routine.
How do the Brune and Madariaga source models change the answer?
Both relate corner frequency to source radius, but with different constants. Brune's 1970 model gives r = 2.34 Vs / (2 pi fc), which is the form used here, while Madariaga's 1976 dynamic circular crack model gives a radius roughly 1.8 times smaller for the same corner frequency. Because stress drop varies as one over radius cubed, the Madariaga constant yields values around five to six times higher. Never compare stress drops between studies without checking which constant each one used.
When is the circular fault formula inappropriate?
The Eshelby circular crack expression assumes a roughly equidimensional rupture in an unbounded elastic solid, which suits small and moderate events. A large strike-slip earthquake, however, saturates the seismogenic thickness and grows only along strike, becoming a long narrow ribbon. For such a rupture the controlling dimension is the down-dip width W, not an equivalent radius, and stress drop scales approximately as mu x D / W. Applying the circular formula to a rupture hundreds of kilometres long but 15 kilometres deep will underestimate stress drop substantially.
Does stress drop tell you the absolute stress acting on the fault?
No, and this is a persistent source of confusion. Stress drop is only the change in shear stress during rupture; the fault may retain most of its load afterwards, which is called a partial stress drop. Typical values of a few MPa are much smaller than the lithostatic stress at seismogenic depth, so an earthquake usually relieves a small fraction of the stored stress. Determining the absolute level requires independent evidence such as borehole stress measurements, heat flow constraints on frictional heating, or focal mechanism inversions.
References
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Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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