Free Air Gravity Correction Calculator
Calculate free-air gravity correction, free-air anomaly, Bouguer correction, and Bouguer anomaly for geophysical gravity surveys.
Free Air Gravity Correction Calculator
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Formula: Free-Air Correction = 0.3086 x h (mGal) | Bouguer Correction = 2piGrho*h
Worked example โ Free-Air Correction: +370.32 mGal | Free-Air Anomaly: -304.68 mGal
Formula
Free-Air Correction = 0.3086 x h (mGal) | Bouguer Correction = 2piGrho*h
Where h = elevation in meters, G = gravitational constant (6.674e-11 m3/kg/s2), rho = rock density in kg/m3. The free-air gradient of 0.3086 mGal/m represents the rate of gravity decrease with elevation above the reference ellipsoid.
Worked Examples
Example 1: Mountain Gravity Station Correction
Problem:A gravity measurement of 979,500 mGal is recorded at elevation 1200 m, latitude 40 degrees. Calculate the free-air correction and free-air anomaly.
Solution:Free-air correction = 0.3086 x 1200 = 370.32 mGal Normal gravity at 40 deg = 978032.7 x (1 + 0.0053024 x sin2(40) - 0.0000058 x sin2(80)) = 978032.7 x (1 + 0.002189 - 0.0000056) = 980175.0 mGal Free-air anomaly = 979500 - 980175.0 + 370.32 = -304.68 mGal
Result:Free-Air Correction: +370.32 mGal | Free-Air Anomaly: -304.68 mGal
Example 2: Bouguer Anomaly at Coastal Station
Problem:At a coastal station (elevation 50 m, latitude 30 deg), observed gravity is 979,400 mGal with rock density 2500 kg/m3. Compute corrections.
Solution:Free-air correction = 0.3086 x 50 = 15.43 mGal Bouguer correction = 2 x pi x 6.674e-11 x 2500 x 50 x 1e5 = 5.24 mGal Normal gravity at 30 deg = 978032.7 x (1 + 0.001326 - 0.0000044) = 979329.7 mGal Free-air anomaly = 979400 - 979329.7 + 15.43 = 85.73 mGal Bouguer anomaly = 85.73 - 5.24 = 80.49 mGal
Result:Free-Air: +15.43 mGal | Bouguer: -5.24 mGal | Bouguer Anomaly: +80.49 mGal
Frequently Asked Questions
What is the free-air gravity correction?
The free-air gravity correction (also called the free-air reduction) accounts for the decrease in gravitational acceleration with increasing elevation above a reference surface, typically the geoid or sea level. Gravity decreases with height because the measurement point is farther from Earth's center of mass. The standard free-air gradient is approximately 0.3086 mGal per meter of elevation. This means for every meter you rise above the reference level, gravity decreases by about 0.3086 milligals. The correction is added to the observed gravity to compute what gravity would be at the reference level, removing the effect of elevation alone without considering the mass of rock between the station and the reference surface.
How is the free-air anomaly different from the Bouguer anomaly?
The free-air anomaly corrects only for the elevation difference between the observation point and the reference surface. It does not account for the gravitational attraction of the rock mass between the two surfaces. The Bouguer anomaly goes one step further by subtracting the gravitational effect of an infinite slab of rock with average crustal density (typically 2670 kg/m3) between the station and sea level. The formula for the Bouguer correction is 2 x pi x G x rho x h, where G is the gravitational constant and rho is rock density. The Bouguer anomaly is more useful for geological interpretation because it reveals subsurface density variations, while the free-air anomaly still contains the signal from topographic mass.
What is normal gravity and how is it calculated?
Normal gravity is the theoretical gravitational acceleration at any point on the reference ellipsoid, which approximates Earth's shape. It varies with latitude because the Earth is an oblate spheroid (flattened at the poles) and rotates. At the equator, normal gravity is about 978,032 mGal, and at the poles it is approximately 983,218 mGal, a difference of about 5,186 mGal. The International Gravity Formula (GRS80) calculates normal gravity using: g = 978032.7 x (1 + 0.0053024 sin2(phi) - 0.0000058 sin2(2phi)) mGal, where phi is geodetic latitude. This formula accounts for both the centrifugal effect of Earth's rotation and the equatorial bulge. Gravity anomalies are computed relative to this normal gravity field.
Why is rock density important in gravity corrections?
Rock density is a critical parameter in the Bouguer correction because it determines the gravitational attraction of the rock slab between the observation point and the reference level. The standard assumed density is 2670 kg/m3, representing average upper continental crust composed primarily of granite and granodiorite. Using incorrect density leads to systematic errors in the Bouguer anomaly. In areas with volcanic rock (density ~2900 kg/m3) or sedimentary basins (density ~2200-2400 kg/m3), the standard density may be inappropriate. The Nettleton method determines optimal density by selecting the value that minimizes correlation between the Bouguer anomaly and topography. Density errors become more significant at higher elevations, where the Bouguer correction magnitude is larger.
What are practical applications of free-air gravity corrections?
Free-air gravity corrections are essential in geophysics and geodesy for numerous practical applications. In mineral exploration, gravity surveys corrected for free-air and Bouguer effects reveal subsurface density anomalies that may indicate ore deposits, cavities, or geological structures. In petroleum exploration, gravity data helps map sedimentary basin depth and locate salt domes. Geodetic applications include determining the geoid shape for precise GPS height conversions. In volcanology, temporal gravity changes corrected for elevation indicate magma movement beneath volcanoes. Civil engineering uses gravity surveys to detect underground voids, abandoned mines, and karst features. Archaeologists employ microgravity surveys to find buried structures. The free-air anomaly itself is important for studying isostatic compensation and tectonic processes.
Where does the value 0.3086 mGal per metre come from?
Treat Earth as a sphere and Newton's law gives g = GM/r squared, so differentiating with respect to r yields dg/dr = -2g/r. Inserting a mean surface gravity near 9.81 m/s2 and a mean radius near 6,371 km gives about 3.08 x 10^-6 m/s2 per metre, which is 0.308 mGal per metre once expressed in the units gravimetrists use. The minus sign says gravity weakens upward, which is why the correction is added back to a station above the datum. The true vertical gradient is not universal: it varies slightly with latitude through the ellipsoid's shape and can depart by a few percent where a strong local density contrast sits beneath the station.
How accurately must station elevation be surveyed, and against which datum?
Because the correction is 0.3086 mGal for every metre, matching the 0.01 mGal repeatability of a modern LaCoste-type or Scintrex gravimeter requires height to about 3 cm. Elevation error is therefore usually the dominant term in a survey's error budget, and levelling or high-quality differential GNSS is needed rather than a handheld receiver or a topographic map. The datum matters as much as the precision: normal gravity is defined on the reference ellipsoid, whereas levelled heights are orthometric and refer to the geoid, which can sit tens of metres from the ellipsoid. Mixing the two shifts every anomaly in the survey by a common bias of several mGal.
What is the terrain correction and why is it always added?
The Bouguer slab treats the ground as an infinite flat sheet of uniform density, which is wrong in relief. A hill rising above the station pulls upward, reducing the measured downward gravity, and a valley cut below the station represents slab mass that is not actually there, so its attraction was over-subtracted. Both departures make the observed value too small relative to the slab model, so the terrain correction is positive in every case and is added to reach the complete Bouguer anomaly. It is computed from a digital elevation model using Hammer zones or prism summation, and it can exceed 10 mGal in steep alpine terrain while remaining under 0.1 mGal on a plain.
Why do free-air anomalies over mountain ranges average close to zero?
Because most mountain belts are close to isostatic equilibrium, supported by a low-density crustal root that displaces denser mantle. The mass excess of the topography and the mass deficit of the root very nearly cancel when viewed from above, so the long-wavelength free-air anomaly stays near zero even where elevations reach several kilometres. The Bouguer anomaly, having stripped away the topographic mass but not the root, is strongly negative over such ranges, commonly several hundred mGal. A large positive free-air anomaly over high ground is the signature of terrain held up dynamically or by flexural strength rather than by a root, and is a diagnostic worth chasing.
Which corrections must be applied to the raw gravimeter reading before this stage?
Anomaly reduction assumes the input is a properly conditioned observed gravity. Before elevation and latitude terms, the field record needs the solid Earth and ocean tide correction, which varies over a range of roughly 0.3 mGal through the day and is predicted from an ephemeris; the instrument drift correction, obtained by repeatedly reoccupying a base station and interpolating the creep of the spring between readings; and a tie to an absolute or national base station so the values sit on a common datum. Surveys made from a moving vehicle, ship or aircraft additionally need the Eotvos correction for the platform's east-west velocity.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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