Pump Power Calculator
Plan your water tank & vessels project with our free pump power calculator. Get precise measurements, material lists, and budgets.
Pump Power Calculator
Calculator
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Formula: WHP = Q x H x SG / 3960 | BHP = WHP / Efficiency
Worked example โ 1.80 BHP (select 2 HP motor), 1.49 kW electrical input
Formula
WHP = Q x H x SG / 3960 | BHP = WHP / Efficiency
Water Horsepower equals the flow rate (GPM) times total dynamic head (ft) times specific gravity, divided by 3960. Brake Horsepower divides WHP by pump efficiency to account for internal losses. Multiply BHP by 0.7457 to get kilowatts, then divide by motor efficiency for electrical input power.
Worked Examples
Example 1: Irrigation Pump Sizing
Problem:Size a pump for 100 GPM at 50 feet TDH with 70% pump efficiency, pumping water (SG = 1.0).
Solution:WHP = 100 x 50 x 1.0 / 3960 = 1.26 HP BHP = 1.26 / 0.70 = 1.80 HP kW = 1.80 x 0.7457 = 1.34 kW Electrical = 1.34 / 0.90 = 1.49 kW
Result:1.80 BHP (select 2 HP motor), 1.49 kW electrical input
Example 2: Industrial Chemical Transfer Pump
Problem:Calculate power for pumping brine (SG = 1.2) at 200 GPM against 80 feet TDH with 65% efficiency.
Solution:WHP = 200 x 80 x 1.2 / 3960 = 4.85 HP BHP = 4.85 / 0.65 = 7.46 HP kW = 7.46 x 0.7457 = 5.56 kW Annual cost = (5.56/0.90) x 8 x 365 x 0.12 = $2,165
Result:7.46 BHP (select 10 HP motor), annual energy cost about $2,165
Frequently Asked Questions
How do you calculate pump power in horsepower?
Pump power is calculated in two steps. First, find the Water Horsepower (WHP) using WHP = Q x H x SG / 3960, where Q is flow in gallons per minute, H is total dynamic head in feet, and SG is specific gravity of the liquid. Then divide WHP by the pump efficiency (as a decimal) to get Brake Horsepower (BHP), which is the actual shaft power the motor must deliver. The constant 3960 converts the units so the result is in horsepower.
What is total dynamic head (TDH)?
Total Dynamic Head is the total equivalent height that a pump must move fluid, including static lift (vertical distance), friction losses in piping, and pressure requirements at the discharge point. For example, if a pump lifts water 30 feet, the piping friction adds 15 feet equivalent, and 10 psi discharge pressure adds 23.1 feet, the TDH is 68.1 feet. Always calculate TDH at the design flow rate since friction losses increase with the square of velocity.
What is a typical pump efficiency?
Centrifugal pump efficiency typically ranges from 60% to 85% at the best efficiency point (BEP), depending on pump size and design. Small residential pumps may be 50-65% efficient, medium commercial pumps 65-80%, and large industrial pumps 80-90%. Efficiency drops significantly when operating far from the BEP flow rate. Positive displacement pumps like gear and diaphragm pumps typically achieve 80-95% efficiency. Always select a pump that operates near its BEP for the required flow and head.
How do I estimate pump operating costs?
Multiply the electrical power consumption in kilowatts by the daily run hours, then by 365 days and your electricity rate per kWh. Electrical power equals brake horsepower times 0.7457 divided by motor efficiency (typically 0.90 to 0.95). For example, a 10 BHP pump with a 90% efficient motor draws 8.29 kW. Running 8 hours daily at $0.12/kWh costs about $2,905 per year. Variable frequency drives (VFDs) can reduce costs by 30-50% in variable flow applications.
What is the difference between water horsepower and brake horsepower?
Water Horsepower (WHP) is the theoretical minimum power needed to move a given flow against a given head with no losses. Brake Horsepower (BHP) is the actual shaft power required, which is always higher than WHP because no pump is 100% efficient. The relationship is BHP = WHP / pump efficiency. Internal losses from fluid friction, recirculation, bearing friction, and seal drag all reduce efficiency. The motor must then provide even more power to overcome its own electrical and mechanical losses.
How do the pump affinity laws change power when speed changes?
For a fixed impeller, flow varies directly with speed, head varies with the square of speed and shaft power varies with the cube of speed. Slowing a pump to 80 percent speed therefore gives 80 percent flow, 64 percent head and 0.8 cubed, or about 51 percent of the original power, close to a halving of energy use. This cubic relationship is the whole argument for variable frequency drives on pumps that spend most of the year at part load, rather than throttling a valve to shed head.
Why does specific gravity appear in the power formula but not in the head?
Head is expressed in feet of the liquid being pumped, so a centrifugal pump develops the same head in feet regardless of fluid density. The energy transferred per unit time, however, depends on the mass being lifted, so power scales directly with specific gravity. Pumping a brine with an SG of 1.2 at the same flow and head requires 20 percent more brake horsepower than water, and the discharge pressure in psi rises by the same proportion, which is why motor and casing selection must be rechecked when a fluid changes.
What is the difference between brake horsepower and motor input power?
Brake horsepower is the mechanical power delivered to the pump shaft, obtained by dividing water horsepower by pump efficiency. Multiplying BHP by 0.7457 converts it to kilowatts at the shaft. The electricity actually drawn is higher still, because the motor has its own efficiency losses, so divide the shaft kilowatts by motor efficiency to get input kW. If a variable frequency drive is fitted, its losses apply on top. Energy cost calculations must use the input figure, not the shaft figure.
How do I pick a motor size from the calculated brake horsepower?
Select the next standard nominal motor rating above the calculated BHP, but check BHP across the whole operating range rather than at the design point alone. Many pump curves are rising to power, so brake horsepower peaks out at the end of the curve where the pump runs at maximum flow against low head. A non-overloading selection sizes the motor for that worst case, so the motor cannot be overloaded anywhere on the curve. Relying on the service factor as spare capacity is not the same thing and shortens motor life if used continuously.
What is the best efficiency point and why should a pump run near it?
The best efficiency point, or BEP, is the flow at which the pump converts the most shaft power into useful fluid power, and it is also the flow at which hydraulic forces around the impeller are most balanced. Running far to the left of BEP causes suction and discharge recirculation, high radial thrust and shaft deflection; running far to the right raises the NPSH requirement and can cavitate. Both extremes shorten seal and bearing life, which is why manufacturers publish a preferred operating region on either side of the BEP.
References
Background & Theory
History
Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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