Bending Stress Calculator
Free Bending stress Calculator for structural engineering projects. Enter dimensions to get material lists and cost estimates.
Reviewed for accuracy by Abdullah, Technical Content Specialist
Bending Stress Calculator
Calculator
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Formula: sigma = M * c / I = M / S
Worked example โ Bending stress = 6.25 ksi (6,250 psi)
Formula
sigma = M * c / I = M / S
Bending stress sigma equals the bending moment M multiplied by the distance c from the neutral axis to the extreme fiber, divided by the moment of inertia I. Equivalently, sigma equals M divided by the section modulus S, where S = I/c. The moment must be in consistent units (kip-inches when I is in in^4) to get stress in ksi.
Worked Examples
Example 1: Rectangular Timber Beam
Problem:Find the bending stress in an 8x12 inch timber beam carrying a moment of 100 kip-ft.
Solution:I = 8 * 12ยณ / 12 = 1,152 inโด c = 12 / 2 = 6 in S = 1,152 / 6 = 192 inยณ sigma = (100 * 12) / 192 = 6.25 ksi = 6,250 psi
Result:Bending stress = 6.25 ksi (6,250 psi)
Example 2: Steel Beam Check
Problem:A steel beam with S = 50 inยณ carries a moment of 80 kip-ft. Check against Fb = 24 ksi.
Solution:sigma = M / S = (80 * 12) / 50 = 19.2 ksi Utilization = 19.2 / 24 = 80% 19.2 < 24, so the beam is adequate.
Result:Bending stress = 19.2 ksi, 80% utilized
Frequently Asked Questions
What is bending stress and how is it calculated?
Bending stress is the normal stress induced at a point in a beam due to an applied bending moment. It is calculated using the flexure formula: sigma = M * c / I, where M is the bending moment, c is the perpendicular distance from the neutral axis to the point of interest (usually the extreme fiber), and I is the moment of inertia about the neutral axis. The stress varies linearly from zero at the neutral axis to a maximum at the outermost fibers. The ratio I/c is called the section modulus S, so sigma = M/S is an equivalent form.
What is the section modulus and why is it useful?
The section modulus S equals I divided by c, where I is the moment of inertia and c is the distance to the extreme fiber. It combines the geometric properties of the cross section into a single value that directly relates moment to stress through sigma = M/S. A larger section modulus means lower bending stress for the same moment. Engineers often select beams by comparing the required section modulus M/Fb to available steel shapes listed in the AISC manual.
What is an allowable bending stress for steel and wood?
For structural steel with Fy = 50 ksi, AISC allows a bending stress of 0.66 * Fy = 33 ksi for compact sections in ASD, or uses a resistance factor of 0.90 in LRFD giving phi-Mn = 0.90 * Fy * Z. For dimensional lumber, the National Design Specification (NDS) provides reference bending values Fb ranging from about 750 to 2,400 psi depending on the species and grade, which are then adjusted by multiple factors for size, duration, moisture, and other conditions.
What happens if bending stress exceeds the yield strength?
If bending stress reaches the yield strength, the outermost fibers begin to yield plastically while the interior fibers remain elastic. As the moment increases further, yielding progresses inward toward the neutral axis, forming a plastic hinge. The fully plastic moment Mp equals Fy times the plastic section modulus Z. For steel beams, the shape factor Z/S typically ranges from 1.1 to 1.5. Beyond Mp, the beam cannot carry additional moment and undergoes large rotations, potentially leading to collapse if not properly braced.
How does the cross-section shape affect bending stress?
The cross-section shape determines the moment of inertia I and the extreme fiber distance c, which together control the bending stress. I-beams and wide-flange shapes are efficient because they concentrate material at the flanges far from the neutral axis, maximizing I while minimizing weight. A rectangular section has I = bh-cubed/12 and S = bh-squared/6. Doubling the depth quadruples I and doubles S, making deeper beams much more efficient in bending.
References
Background & Theory
History
Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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