Fillet Weld Capacity Calculator
Plan your materials specifications project with our free fillet weld capacity calculator. Get precise measurements, material lists, and budgets.
Fillet Weld Capacity Calculator
Calculator
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Formula: Design Strength = phi x 0.6 x FEXX x Throat x Length
Worked example โ 187.10 kN design shear capacity
Formula
Design Strength = phi x 0.6 x FEXX x Throat x Length
The design shear strength of a fillet weld equals the resistance factor (phi = 0.75 for LRFD) multiplied by 0.6 times the electrode tensile strength, times the effective throat thickness (leg x 0.707), times the weld length. The 0.6 factor converts tensile strength to shear strength.
Worked Examples
Example 1: E70 Fillet Weld on Steel Beam
Problem:Calculate the design capacity of a 6mm fillet weld, 200mm long, using E70 (490 MPa) electrodes with LRFD phi = 0.75.
Solution:Throat = 6 x 0.707 = 4.243 mm Effective Area = 4.243 x 200 = 848.53 mm2 Nominal Strength = 0.6 x 490 x 848.53 = 249,468 N = 249.47 kN Design Strength = 0.75 x 249.47 = 187.10 kN
Result:187.10 kN design shear capacity
Example 2: E60 Weld for Light Structure
Problem:Find the capacity of a 5mm fillet weld, 150mm long, using E60 (414 MPa) electrodes.
Solution:Throat = 5 x 0.707 = 3.536 mm Effective Area = 3.536 x 150 = 530.33 mm2 Nominal = 0.6 x 414 x 530.33 = 131,734 N Design = 0.75 x 131.73 = 98.80 kN
Result:98.80 kN design shear capacity
Frequently Asked Questions
What is the throat thickness of a fillet weld?
The effective throat thickness of a fillet weld is the shortest distance from the root of the joint to the face of the weld. For equal-leg fillet welds, this equals the leg size multiplied by the cosine of 45 degrees, which is the leg size divided by the square root of 2 (approximately 0.707 times the leg size). This throat dimension is critical because it represents the weakest cross-section of the weld where failure would occur under shear loading.
How is fillet weld capacity calculated per AISC standards?
Per AISC 360, the design shear strength of a fillet weld is calculated as phi times 0.6 times the electrode tensile strength (FEXX) times the effective throat area. The resistance factor phi is 0.75 for LRFD design. The effective area equals the throat thickness multiplied by the weld length. For E70 electrodes (70 ksi or 490 MPa), the allowable shear stress on the weld metal is 0.6 times 490 equals 294 MPa nominal.
What are common electrode classifications and their strengths?
E60 electrodes have a tensile strength of 60 ksi (414 MPa) and are used for mild steel. E70 electrodes at 70 ksi (490 MPa) are the most common for structural steel work. E80 at 80 ksi (552 MPa) and E90 at 90 ksi (621 MPa) are used for higher-strength steels. The electrode strength must match or exceed the base metal strength, and the number in the classification directly indicates the minimum tensile strength in ksi.
What is the minimum and maximum fillet weld size?
The minimum fillet weld size depends on the thicker plate being joined, per AISC Table J2.4. For plates up to 6mm (1/4 inch), minimum leg size is 3mm (1/8 inch). For plates 6-13mm, minimum is 5mm (3/16 inch). The maximum fillet weld size along an edge should not exceed the plate thickness minus 1.6mm (1/16 inch) for plates thicker than 6mm. These limits ensure proper fusion and prevent burn-through on thin members.
What is the difference between LRFD and ASD for fillet weld design?
Both methods start from the same nominal strength, 0.6 times FEXX acting on the effective throat area. LRFD multiplies that by a resistance factor of 0.75 and compares it with factored loads. ASD divides it by a safety factor of 2.00 and compares with service loads, which works out to an allowable stress of 0.3 times FEXX on the throat. The two approaches give closely comparable weld sizes; pick one and apply it consistently across the whole connection.
How does the directional strength increase for transversely loaded welds work?
A fillet weld loaded perpendicular to its axis is stronger and less ductile than one loaded parallel to it, because the critical failure plane rotates away from the 45 degree throat. AISC permits the nominal strength to be multiplied by 1.0 plus 0.5 times sin theta raised to the 1.5 power, where theta is the angle between the load and the weld axis. That gives no increase for longitudinal welds and up to 1.5 times for purely transverse ones.
How do I convert a required force into a fillet weld length?
Compute the capacity per inch of weld first, then divide the demand by it. For a 1/4 inch leg with E70 electrodes, phi times 0.6 times FEXX is 0.75 x 0.6 x 70 = 31.5 ksi, and the throat is 0.25 x 0.707 = 0.1768 inch, so each inch of weld carries about 5.57 kips. A 100 kip demand therefore needs roughly 18 inches of weld, distributed symmetrically about the line of action to avoid eccentricity.
Why is effective length reduced for long end-loaded fillet welds?
Stress along an end-loaded lap weld is not uniform: it peaks at the ends and slackens in the middle, so adding length past a point buys less than proportional capacity. AISC handles this with a reduction factor applied once the weld length exceeds 100 times the leg size, tapering the effective length down, with a floor applied to very long welds. The practical fix is a larger leg over a shorter run rather than an extremely long thin weld.
What is the difference between a fillet weld and a partial joint penetration groove weld?
A fillet weld is deposited in the corner of a lapped or tee joint and its throat is derived from the leg geometry, so no edge preparation is needed and it is cheap to lay. A partial joint penetration groove weld requires a bevelled or grooved edge and develops throat inside the joint, giving more capacity per unit of deposited metal on thick members. Fatigue is a separate question: a complete joint penetration groove weld, dressed and fully fused, outperforms a fillet weld whose toe and root are sharp stress raisers, but a partial penetration root is itself an unfused notch and can be just as severe.
Why must the connected base metal be checked as well as the weld metal?
The weld is only one of the possible failure paths. The plate it attaches to can yield or rupture in shear along the fusion face, tear out in a block shear pattern, or fail in tension on the net section, and any of those can govern before the weld metal reaches its capacity, especially on thin material or short connections. AISC requires the smaller of weld strength and base metal strength to control, so run both checks on every joint.
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Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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