Bolt Shear Capacity Calculator
Free Bolt shear capacity Calculator for materials specifications projects. Enter dimensions to get material lists and cost estimates.
Bolt Shear Capacity Calculator
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Formula: Rn = Fnv x Ab (per bolt per shear plane)
Worked example โ Total LRFD capacity of 71,568 lbs; DCR = 0.279 (passes)
Formula
Rn = Fnv x Ab (per bolt per shear plane)
The nominal bolt shear strength (Rn) equals the nominal shear stress (Fnv) multiplied by the nominal bolt area (Ab). Fnv is 0.450 x Fu for threads included or 0.563 x Fu for threads excluded. Apply phi = 0.75 for LRFD or divide by omega = 2.00 for ASD.
Worked Examples
Example 1: Standard Beam Connection
Problem:Check 4 A325-N 3/4-inch bolts in single shear against 20,000 lbs applied load using LRFD.
Solution:Ab = pi x 0.75^2 / 4 = 0.4418 sq in Fnv = 0.450 x 120,000 = 54,000 psi Rn = 54,000 x 0.4418 = 23,856 lbs/bolt Phi-Rn = 0.75 x 23,856 = 17,892 lbs/bolt Total = 4 x 17,892 = 71,568 lbs > 20,000 OK
Result:Total LRFD capacity of 71,568 lbs; DCR = 0.279 (passes)
Example 2: Heavy Truss Gusset Plate
Problem:Determine capacity of 6 A490-X 1-inch bolts in double shear.
Solution:Ab = pi x 1.0^2 / 4 = 0.7854 sq in Fnv = 0.563 x 150,000 = 84,450 psi Rn = 84,450 x 0.7854 = 66,307 lbs/bolt/plane Total nominal = 6 x 2 x 66,307 = 795,684 lbs LRFD = 0.75 x 795,684 = 596,763 lbs
Result:Total LRFD capacity of 596,763 lbs in double shear
Frequently Asked Questions
What determines the shear capacity of a bolt?
Bolt shear capacity depends on the bolt diameter, material grade (ultimate tensile strength), whether the shear plane passes through the threaded or unthreaded portion, and the number of shear planes. The nominal shear stress is a fraction of the ultimate tensile strength: 0.450 times Fu when threads are in the shear plane, and 0.563 times Fu when threads are excluded. Larger bolts and higher grades provide greater shear resistance.
What is the difference between LRFD and ASD design methods?
LRFD (Load and Resistance Factor Design) applies a resistance factor phi of 0.75 to the nominal strength and uses factored loads with load combinations. ASD (Allowable Stress Design) divides the nominal strength by a safety factor omega of 2.00 and uses unfactored service loads. Both methods produce similar designs when properly applied. LRFD is preferred in modern practice because it provides more consistent reliability across different load combinations.
Why does it matter if threads are in the shear plane?
When the shear plane passes through the threaded portion of a bolt, the effective cross-sectional area is reduced by the thread roots, and the irregular geometry creates stress concentrations. This reduces the shear capacity by about 20 percent compared to shearing through the smooth unthreaded shank. Connection details should specify whether threads are included (N-type) or excluded (X-type), and the bolt length must be chosen accordingly to ensure the desired condition.
What is a double shear connection?
A double shear connection occurs when a bolt passes through three plates and the applied load creates two shear planes on the bolt. Common examples include a gusset plate sandwiched between two connection angles, or a clevis pin with two side plates. Double shear effectively doubles the bolt shear capacity compared to single shear because the load is shared across two cross-sections. Multi-shear-plane connections with more than two planes are also possible in specialized connections.
Why can bearing or tear-out on the connected plate govern before the bolt shears?
A bolt in a bearing type joint pushes against the side of its hole, and a thin ply can deform or split out toward the free edge before the bolt itself fails. AISC checks this separately: the strength depends on the clear distance to the next hole or the edge, the ply thickness and the tensile strength of the connected material, with an upper limit tied to the bolt diameter and ply thickness. With thin plates or short edge distances this plate check, not the bolt shear value, sets the connection capacity.
How does a slip critical connection differ from a bearing type connection?
A bearing type joint accepts that the plies slip until the bolts bear on the holes, and is checked purely on shear and bearing. A slip critical joint resists load by friction generated by the clamping force of pretensioned bolts acting on prepared faying surfaces, so its strength depends on the pretension, the surface slip coefficient and the number of slip planes. It is required where slip would be unacceptable, such as oversized or slotted holes and joints subject to load reversal or fatigue.
What is the difference between the nominal bolt area and the tensile stress area?
The nominal area Ab used here is the gross area of the unthreaded shank, pi times the diameter squared over four. The tensile stress area is smaller because it reflects the reduced section at the threads. AISC keeps the calculation on the gross area and instead lowers the nominal shear stress when threads lie in the shear plane, which is why Fnv is about 0.450 times Fu with threads included and about 0.563 times Fu with them excluded rather than the area changing.
How does eccentricity in a bolt group reduce the connection capacity?
If the line of action of the load does not pass through the centroid of the bolt group, the group carries a moment as well as direct shear. The bolts furthest from the instantaneous center of rotation then pick up the largest resultant force, so the group capacity is less than the number of bolts times the single bolt value. Design tables give a coefficient C, so usable strength is C times the single bolt strength, and reducing the eccentricity is usually cheaper than adding bolts.
When do long joint or filler plate reductions apply to bolt shear?
In a very long line of bolts the end fasteners are loaded more heavily than those in the middle because the plies stretch unevenly, so the specification reduces the tabulated nominal shear stress once the distance between the extreme fasteners in a line becomes large, on the order of a metre. Fillers used to pack out a mismatch in ply thickness also matter: undeveloped fillers beyond a certain thickness require either a strength reduction or extra bolts to develop the filler.
How are shear and tension combined when a bolt carries both?
A bolt in a bracket or hanger connection can see shear and axial tension at once, and the two interact. AISC handles this by reducing the available tensile stress as the required shear stress rises, using a modified nominal tensile stress equal to 1.3 Fnt minus Fnt divided by phi Fnv times the required shear stress, capped at Fnt. If the shear stress is small relative to the available shear strength, the reduction is negligible and the checks behave as if independent.
References
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Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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