Power Factor Calculator
Calculate power factor from real and apparent power or voltage and current. Determine capacitor size needed for power factor correction and estimate
Power Factor Calculator
Calculator
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Formula: PF = kW / kVA = cos(phi)
Worked example โ PF: 0.80 | Capacitor: 210.7 kVAR | New kVA: 526.3
Formula
PF = kW / kVA = cos(phi)
Power factor equals real power (kW) divided by apparent power (kVA), which is also the cosine of the phase angle between voltage and current. Reactive power (kVAR) equals kW times the tangent of the phase angle. To correct power factor, a capacitor bank rated at the difference between current kVAR and target kVAR is installed.
Worked Examples
Example 1: Factory Power Factor Correction
Problem:A factory draws 500 kW at 625 kVA. Calculate the power factor and capacitor size needed to reach 0.95 PF.
Solution:Power factor: 500 / 625 = 0.80 Phase angle: acos(0.80) = 36.87 degrees Reactive power: 500 x tan(36.87) = 375 kVAR Target kVAR at 0.95: 500 x tan(acos(0.95)) = 164.3 kVAR Capacitor needed: 375 - 164.3 = 210.7 kVAR
Result:PF: 0.80 | Capacitor: 210.7 kVAR | New kVA: 526.3
Example 2: Motor Load Analysis
Problem:A 480V, 3-phase system has 200A current draw and 120 kW real power. Find the power factor.
Solution:Apparent power: 480 x 200 x 1.732 / 1000 = 166.3 kVA Power factor: 120 / 166.3 = 0.722 Reactive power: 120 x tan(acos(0.722)) = 115.1 kVAR This is below the 0.9 penalty threshold.
Result:PF: 0.722 | kVA: 166.3 | kVAR: 115.1 | Penalty risk: Yes
Frequently Asked Questions
What is power factor?
Power factor is the ratio of real power (kW) to apparent power (kVA) in an AC electrical system. It ranges from 0 to 1, where 1.0 (unity) means all the power drawn is being used productively. A power factor of 0.8 means only 80% of the current drawn is doing useful work, while 20% is circulating as reactive power. Low power factor is caused by inductive loads like motors, transformers, and fluorescent lighting that require reactive power to maintain their magnetic fields. Poor power factor increases current draw, causes voltage drops, and results in utility penalties.
How do I improve power factor?
The most common method to improve power factor is installing capacitor banks that supply reactive power locally, reducing the reactive power drawn from the utility. Capacitors are sized in kVAR to offset the inductive kVAR of the load. Other methods include synchronous motors (which can generate leading reactive power), active power factor correction circuits in electronic equipment, and replacing lightly loaded motors with properly sized ones. Automatic power factor correction systems switch capacitor banks in and out based on real-time monitoring to maintain the target power factor as loads change throughout the day.
Why do utilities charge penalties for low power factor?
Utilities charge power factor penalties because low power factor forces them to generate, transmit, and distribute more current than necessary to deliver the same amount of useful power. This extra current causes increased losses in utility transformers and transmission lines, requires larger capacity infrastructure, and reduces the efficiency of the entire power grid. Most commercial and industrial utility tariffs require a minimum power factor of 0.85 to 0.95. Penalties can be calculated as a surcharge on the demand charge, a multiplier on the energy charge, or as an adjustment to billed demand.
What is the power triangle?
The power triangle is a right triangle that visually represents the relationship between real power (kW), reactive power (kVAR), and apparent power (kVA). Real power forms the horizontal base and represents useful work. Reactive power forms the vertical side and represents the power needed to sustain magnetic fields in inductive loads. Apparent power is the hypotenuse and represents the total power the supply must deliver. The angle between real and apparent power is the phase angle (phi), and the cosine of this angle is the power factor. The Pythagorean relationship gives: kVA squared equals kW squared plus kVAR squared.
What is the difference between displacement power factor and true power factor?
Displacement power factor is the cosine of the phase angle between the fundamental voltage and current waveforms, which is what the classic power triangle describes. True power factor also accounts for harmonic current drawn by non-linear loads such as variable frequency drives, rectifiers, and switch-mode supplies. True power factor equals displacement power factor divided by the square root of one plus the square of the current total harmonic distortion, so a badly distorted load can measure poorly even at unity displacement.
What is the difference between leading and lagging power factor?
Lagging power factor means current lags voltage, the normal condition for inductive loads such as induction motors and transformers, and it is what capacitor banks correct. Leading power factor means capacitance dominates, typically from an oversized capacitor bank left connected at light load or from long lightly loaded cables. Leading power factor is not a bonus: it can raise system voltage, cause self-excitation of motors as they coast down, and still attract a utility penalty.
Does correcting power factor reduce the kilowatt-hours on my bill?
No. Real power in kilowatts, and therefore energy in kilowatt-hours, is unchanged by adding capacitors, because reactive power does no net work. The savings come from elsewhere: lower billed demand where the utility bills in kVA or applies a power factor adjustment, avoidance of low power factor penalties, and reduced resistive losses in your own cables and transformers, since those losses vary with the square of current. Released capacity in existing feeders is often the larger benefit.
How does power factor affect cable, breaker, and transformer sizing?
Current for a given real power varies inversely with power factor. In a three-phase system, current equals real power in watts divided by the product of the square root of three, line-to-line voltage, and power factor. Dropping from 0.95 to 0.75 raises current by about 27 percent for the same useful output, pushing up conductor size, breaker rating, and transformer kVA. Because conductor heating rises with the square of current, the losses climb faster still.
Why can a capacitor bank make harmonic problems worse?
A capacitor bank and the upstream source inductance form a parallel resonant circuit. If the resonant frequency lands near a harmonic the site already produces, commonly the fifth or seventh, the resulting circulating current can be many times the harmonic current injected, overheating capacitors and blowing fuses. The usual remedy is a detuned bank, in which a series reactor shifts the resonance below the lowest significant harmonic so amplification cannot occur.
How is power factor determined from three-phase meter readings?
Measure real power in kilowatts with a wattmeter, then measure line voltage and line current. Apparent power in kVA equals the square root of three multiplied by line-to-line voltage and line current, divided by 1000. Power factor is the ratio of the two. This works only when the three phases are reasonably balanced; with significant unbalance or waveform distortion, use a power analyser that computes true power factor from sampled waveforms instead.
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Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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