Slope Stability Calculator
Calculate factor of safety for slope stability using infinite slope analysis, Culmann method, and simplified force analysis with soil cohesion.
Slope Stability Calculator
Calculator
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Formula: FOS = c/(gamma*H*cos(beta)*sin(beta)) + tan(phi)/tan(beta)
Worked example โ FOS = 1.000, marginally stable, requires remediation
Formula
FOS = c/(gamma*H*cos(beta)*sin(beta)) + tan(phi)/tan(beta)
The infinite slope factor of safety equals the sum of the cohesion component and the friction component. The cohesion component divides the soil cohesion by the product of unit weight, slope height, and the sine and cosine of the slope angle. The friction component is the ratio of the tangent of the friction angle to the tangent of the slope angle. A FOS greater than 1.5 is generally considered stable for permanent slopes.
Worked Examples
Example 1: Highway Cut Slope Analysis
Problem:Analyze stability of a 20 ft high cut slope at 30 degrees with cohesion 200 psf, friction angle 25 degrees, and unit weight 120 pcf.
Solution:Infinite slope FOS: Cohesion component = 200 / (120 x 20 x cos30 x sin30) = 0.192 Friction component = tan(25) / tan(30) = 0.808 FOS = 0.192 + 0.808 = 1.000 Culmann critical height Hc = 4c sin(beta) cos(phi) / (gamma (1 - cos(beta - phi))) Hc = 4 x 200 x 0.500 x 0.906 / (120 x (1 - cos 5)) = 362.5 / 0.457 = 794 ft Hc is far above 20 ft, so a planar toe wedge does not govern; the shallow infinite-slope mechanism does
Result:FOS = 1.000, marginally stable, requires remediation
Example 2: Embankment Fill Slope
Problem:Check stability of a 15 ft embankment at 45 degrees, cohesion 500 psf, friction 30 degrees, unit weight 125 pcf.
Solution:Infinite slope FOS: Cohesion component = 500 / (125 x 15 x cos45 x sin45) = 0.533 Friction component = tan(30) / tan(45) = 0.577 FOS = 0.533 + 0.577 = 1.110 Culmann critical height Hc = 4 x 500 x sin45 x cos30 / (125 x (1 - cos15)) = 1,225 / 4.26 = 288 ft (planar wedge not critical)
Result:FOS = 1.110, marginally stable
Frequently Asked Questions
What is the factor of safety for slope stability and what values are acceptable?
The factor of safety (FOS) is the ratio of resisting forces (or moments) to driving forces acting on a slope. A FOS of 1.0 means the slope is at the verge of failure, where driving forces exactly equal resisting forces. Most engineering codes require a minimum FOS of 1.5 for permanent slopes, 1.3 for temporary construction slopes, and 1.25 for slopes where consequences of failure are minor. Critical infrastructure such as dams and bridge abutments may require FOS of 1.75 or higher.
What is the difference between infinite slope and finite slope analysis?
Infinite slope analysis assumes the slope extends indefinitely with a uniform failure surface parallel to the slope face. It is applicable for shallow translational slides where the failure depth is small relative to the slope length. Finite slope analysis considers slopes with defined boundaries and potential circular or non-circular failure surfaces. The Culmann method analyzes planar failure in finite slopes, while methods like Bishop and Spencer analyze circular failure surfaces using slice methods.
How do soil properties affect slope stability?
Two key soil properties govern slope stability: cohesion and internal friction angle. Cohesion provides shear resistance independent of normal stress, which is critical for clay soils and steep slopes. The friction angle provides resistance proportional to the normal force on the failure plane, dominating in granular soils. Saturated conditions reduce effective stress and friction resistance, which is why many slope failures occur during heavy rainfall. Vegetation roots provide additional cohesion of 50 to 300 psf in the root zone.
What are common methods to improve slope stability?
Slope stability can be improved through several methods: reducing the slope angle by excavating material from the top or adding material at the toe, installing drainage systems to lower the water table and reduce pore water pressure, constructing retaining walls or soil nail walls, using geosynthetic reinforcement, planting deep-rooted vegetation for added cohesion, and installing ground anchors or tiebacks. The most cost-effective approach depends on the site conditions, failure mechanism, and required factor of safety increase.
How does pore water pressure change a slope's factor of safety?
Shear strength depends on effective stress, the total normal stress minus pore water pressure u. Raising the water table does not reduce the weight driving the slide, but it does reduce the effective normal stress on the failure surface, so the frictional resisting term shrinks and the factor of safety falls. Seepage running parallel to a slope can cut the friction contribution roughly in half compared with dry conditions. The infinite-slope expression used here assumes dry soil, so wet-season conditions must be checked separately.
What does the Mohr-Coulomb model say about cohesion and friction angle?
Mohr-Coulomb expresses shear strength as tau = c + sigma' tan(phi), a cohesion intercept plus a frictional component proportional to effective normal stress. Cohesion c is roughly independent of depth, so its stabilising contribution scales as c divided by gamma H and fades in tall slopes. The friction term depends only on the ratio tan(phi) over tan(beta) in an infinite slope, which is why a clean dry sand with negligible cohesion is stable at any height as long as the slope angle stays below the friction angle.
What is the Taylor stability number used for?
The stability number is the dimensionless group c divided by gamma times H, formed from cohesion, unit weight and slope height. Because it is dimensionless it collapses many geometries onto a single chart: for a given slope angle and friction angle a critical stability number can be read off, and from it the critical height at which the factor of safety equals one. Comparing your computed number with the critical value tells you immediately whether the slope is limited by cohesion or by geometry.
When is the Culmann planar wedge appropriate rather than a method of slices?
Culmann's method assumes a single plane failure surface through the toe and finds the worst plane analytically. It suits steep slopes and situations where the failure really is planar, such as sliding on a bedding plane, joint or soil-rock interface. Shallow slopes in homogeneous soil fail on curved surfaces instead, which is why design work uses limit-equilibrium slice methods such as Bishop or Spencer that can also carry layered strata, phreatic surfaces and reinforcement.
What does the critical height tell you about a cut?
Critical height is the slope height at which the resisting and driving forces balance exactly, giving a factor of safety of one. Any excavation taller than that is theoretically at failure with no reserve, so the usable design height is the critical height divided by the target factor of safety, or the slope must be flattened, benched or reinforced. It scales directly with cohesion and inversely with unit weight, which is why the same geometry stands in stiff clay and collapses in loose granular fill.
Should a slope be analysed in drained or undrained conditions?
Undrained analysis uses total stresses and the undrained shear strength, representing loading fast enough that pore pressures cannot dissipate; drained analysis uses effective-stress parameters c' and phi' for the long term. Which case governs depends on the direction of pore pressure change: a cut in clay generates suctions that dissipate over time, so its long-term drained condition is critical, whereas an embankment built on soft clay generates positive excess pressures and is usually most at risk at the end of construction.
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Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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