Hole Volume Calculator
Calculate the volume of cylindrical, conical, or rectangular holes and determine concrete or fill material needed.
Hole Volume Calculator
Calculator
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Formula: Cylinder: V = pi x r^2 x h | Frustum: V = (pi x h / 3)(R^2 + Rr + r^2) | Box: V = L x W x H
Worked example โ Volume: 1.36 cu ft | 3 bags of 80-lb concrete | 10.2 gallons
Formula
Cylinder: V = pi x r^2 x h | Frustum: V = (pi x h / 3)(R^2 + Rr + r^2) | Box: V = L x W x H
Volume formulas depend on hole shape. Cylindrical holes use pi times radius squared times depth. Tapered (conical) holes use the frustum formula with top and bottom radii. Rectangular holes multiply length times width times depth.
Worked Examples
Example 1: Fence Post Hole
Problem:Calculate the volume and concrete needed for a cylindrical post hole 10 inches in diameter and 30 inches deep.
Solution:Radius = 10 / 2 = 5 inches Volume = pi x 5^2 x 30 = pi x 25 x 30 = 2,356.19 cubic inches Convert to cubic feet: 2,356.19 / 1,728 = 1.364 cubic feet 80-lb bags needed: 1.364 / 0.6 = 2.27, round up to 3 bags Concrete weight: 1.364 x 150 = 204.6 lbs
Result:Volume: 1.36 cu ft | 3 bags of 80-lb concrete | 10.2 gallons
Example 2: Rectangular Planting Hole
Problem:A rectangular planting hole measures 24 inches long, 18 inches wide, and 20 inches deep. How much soil fill is needed?
Solution:Volume = L x W x D = 24 x 18 x 20 = 8,640 cubic inches Convert to cubic feet: 8,640 / 1,728 = 5.0 cubic feet Convert to cubic yards: 5.0 / 27 = 0.185 cubic yards Gallons: 5.0 x 7.48 = 37.4 gallons Liters: 5.0 x 28.317 = 141.6 liters
Result:Volume: 5.0 cu ft (0.185 cu yd) | 37.4 gallons | 141.6 liters
Frequently Asked Questions
How do you calculate the volume of a cylindrical hole?
The volume of a cylindrical hole is calculated using the formula V = pi times r squared times h, where r is the radius of the hole and h is the depth. First, measure the diameter of the hole and divide by two to get the radius. Then square the radius, multiply by pi (approximately 3.14159), and multiply by the depth. For example, a hole that is 12 inches in diameter and 36 inches deep has a radius of 6 inches. The volume would be pi times 36 times 36, which equals approximately 4,071.5 cubic inches or about 2.36 cubic feet. This formula works for any perfectly round hole with straight vertical sides.
How much concrete do I need to fill a post hole?
To determine concrete needs, first calculate the volume of the hole in cubic feet, then account for the volume displaced by the post itself. A standard fence post hole is typically 8 to 12 inches in diameter and 24 to 36 inches deep. An 80-pound bag of pre-mixed concrete yields approximately 0.6 cubic feet when mixed, while a 60-pound bag yields about 0.45 cubic feet. For a typical 10-inch diameter hole that is 30 inches deep, the volume is about 0.91 cubic feet, requiring approximately 2 bags of 80-pound mix. Always buy an extra bag or two because holes are rarely perfectly cylindrical and the ground absorbs some moisture from the concrete.
What is the difference between a cylindrical and conical hole volume?
A cylindrical hole has the same diameter from top to bottom, producing straight vertical walls. Its volume is simply pi times radius squared times depth. A conical or tapered hole has a wider opening at the top that narrows toward the bottom, which is common when digging by hand with a shovel. The volume of a tapered hole uses the frustum formula: V = (pi times h divided by 3) times (R squared + R times r + r squared), where R is the top radius, r is the bottom radius, and h is the depth. A conical hole always has less volume than a cylindrical hole of the same top diameter and depth, which means you need less material to fill it.
How do you convert between cubic inches, cubic feet, and cubic yards?
Converting between cubic volume units requires cubing the linear conversion factors. There are 12 inches in a foot, so there are 12 cubed or 1,728 cubic inches in one cubic foot. Similarly, there are 3 feet in a yard, so there are 3 cubed or 27 cubic feet in one cubic yard. To convert cubic inches to cubic feet, divide by 1,728. To convert cubic feet to cubic yards, divide by 27. For metric conversions, one cubic meter equals 35.3147 cubic feet or approximately 264.172 US gallons. One cubic foot equals approximately 7.48 US gallons or 28.317 liters. These conversions are essential when ordering materials like concrete, gravel, or soil.
What depth should a post hole be for different applications?
Post hole depth depends on the application, soil conditions, and local building codes. For fence posts, the general rule is one-third of the total post length should be below ground, with a minimum depth of 24 inches. In areas with frost, posts must extend below the frost line, which varies from 12 inches in southern states to 48 inches or more in northern climates. Deck posts typically require 36 to 48 inches of depth depending on the load and local codes. Mailbox posts usually need 18 to 24 inches. Structural posts for pergolas or carports may need 36 to 60 inches depending on the structure height and wind loads. Always check your local building codes before digging.
How do I subtract the post volume to find the concrete actually needed?
Fill volume equals hole volume minus the volume of whatever occupies the hole. Use lumber's actual dimensions, not the nominal ones: a 4x4 measures 3.5 by 3.5 inches, an area of 12.25 square inches, so 24 inches of embedment displaces 294 cubic inches, which is 294 divided by 1728, about 0.17 cubic feet. Round posts displace pi x radius squared x embedded length. Skipping this step is harmless on a wide hole but noticeably over-orders when the post nearly fills a narrow one.
How do I size the gravel drainage layer at the bottom of a post hole?
The drainage plug is just a short cylinder of the same diameter as the hole, so its volume is pi x radius squared x the layer thickness, and that volume must be deducted from the concrete fill above it. A 10 inch diameter hole with a 6 inch gravel base holds pi x 25 x 6, about 471 cubic inches, or 0.27 cubic feet of stone. Use angular crushed stone rather than rounded pea gravel so the plug compacts and stays put under the post.
How do you estimate the volume of an irregular hole that is not round?
Where no single formula fits, treat the excavation as a prism and average its cross-sections. Measure the plan area at the top, at mid-depth and at the base, then apply the prismoidal rule: volume equals the depth divided by six, multiplied by the top area plus four times the mid area plus the base area. It handles bulges and undercuts that a simple average of top and bottom misses, and it is the same method quantity surveyors use for trench and pit earthworks.
How do I estimate the spoil volume from an excavated hole?
Soil bulks when it is dug, because excavation destroys the in-situ packing and introduces voids, so the loose pile is always larger than the hole it came from. Granular sands and gravels swell modestly, while stiff clays and rock swell a great deal more. Since the calculator returns the in-place hole volume, multiply by a bulking factor appropriate to the material when sizing a wheelbarrow count, a spoil heap or a skip, and remember that soil re-compacts only partially when backfilled.
How do I calculate the volume of a hole drilled at an angle?
Volume follows the length measured along the drilled axis, not the vertical depth, so a battered or raking hole uses the full along-axis length in pi x radius squared x length. Vertical depth is a separate quantity, equal to the axis length times the cosine of the angle from vertical: a 10 ft hole inclined 30 degrees from vertical reaches only 8.66 ft below grade while still holding a full 10 ft of material. Confusing the two under-orders fill on every raked hole.
References
Background & Theory
History
Reviewed for accuracy by Abdullah, Technical Content Specialist ยท Editorial policy
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