Young Laplace Equation Calculator
Calculate pressure difference across curved interfaces using the Young-Laplace equation. Supports spherical droplets, soap bubbles, general curvature.
Young Laplace Equation Calculator
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Formula: delta-P = gamma * (1/R1 + 1/R2)
Worked example โ Excess pressure = 145.6 Pa (about 0.0014 atm)
Formula
delta-P = gamma * (1/R1 + 1/R2)
The Young-Laplace equation gives the pressure difference across a curved interface. gamma is surface tension, R1 and R2 are principal radii of curvature. For spheres: delta-P = 2*gamma/R. For bubbles: delta-P = 4*gamma/R (two surfaces).
Worked Examples
Example 1: Water Droplet Pressure
Problem:Find the excess pressure inside a water droplet of radius 1 mm (surface tension = 0.0728 N/m).
Solution:delta-P = 2 * gamma / R delta-P = 2 * 0.0728 / 0.001 delta-P = 145.6 Pa
Result:Excess pressure = 145.6 Pa (about 0.0014 atm)
Example 2: Capillary Rise in Glass Tube
Problem:Water (gamma = 0.0728 N/m, theta = 0) rises in a glass tube of radius 0.5 mm. Find the height.
Solution:h = 2 * 0.0728 * cos(0) / (998 * 9.81 * 0.0005) h = 0.1456 / 4.895 h = 0.02975 m = 29.75 mm
Result:Capillary rise height = 29.75 mm
Frequently Asked Questions
What is the Young-Laplace equation?
The Young-Laplace equation describes the pressure difference across a curved interface between two fluids due to surface tension. The equation is delta-P = gamma * (1/R1 + 1/R2), where gamma is the surface tension and R1 and R2 are the principal radii of curvature. For a sphere, both radii are equal, simplifying to delta-P = 2*gamma/R. This equation is fundamental in understanding capillary action, bubble formation, droplet behavior, and many biological processes like alveolar mechanics in the lungs.
Why does a soap bubble have 4*gamma/R instead of 2*gamma/R?
A soap bubble has two liquid-air interfaces: one on the inside and one on the outside of the thin soap film. Each interface contributes a pressure jump of 2*gamma/R according to the Young-Laplace equation. Since the bubble has two surfaces, the total pressure difference between the inside and outside is 4*gamma/R. A liquid droplet, by contrast, has only one interface and follows the standard 2*gamma/R formula. This is why soap bubbles are easier to pop than liquid drops of the same size.
What is capillary action?
Capillary action is the ability of a liquid to flow in narrow spaces against gravity due to surface tension and adhesive forces between the liquid and the tube walls. The height of capillary rise is h = 2*gamma*cos(theta)/(rho*g*r), where theta is the contact angle, rho is liquid density, g is gravitational acceleration, and r is the tube radius. Water in glass has a contact angle near 0, giving strong capillary rise. Mercury in glass has a contact angle greater than 90 degrees, causing capillary depression instead.
What determines surface tension?
Surface tension arises from the imbalance of intermolecular forces at a liquid surface. Molecules at the surface experience a net inward pull because they have fewer neighbors than bulk molecules, creating a tension that minimizes surface area. Water has a relatively high surface tension of 0.0728 N/m at 20 C due to hydrogen bonding. Surfactants reduce surface tension by adsorbing at the interface. Temperature generally decreases surface tension because thermal energy weakens intermolecular cohesion.
What is the capillary length and why does it limit this equation?
The capillary length is sqrt(gamma/(rho*g)), the scale at which surface tension and gravity contribute equally to the shape of an interface. For water at 20 degrees C it works out at about 2.7 mm. Below that size a droplet or meniscus is essentially spherical and the Young-Laplace result applies cleanly. Above it, hydrostatic pressure varies appreciably over the interface, the drop flattens into a puddle, and the radii of curvature stop being constant, so a single delta-P value no longer describes the whole surface.
Why does the smaller of two connected bubbles empty into the larger one?
Excess pressure scales as one over the radius, so the smaller bubble is at higher pressure. With gamma at 25 mN/m, a 1 cm soap bubble holds 4*gamma/R = 10 Pa while a 2 cm bubble holds only 5 Pa. Open a tube between them and gas flows from the small, high-pressure bubble into the large one until the small one vanishes. The same instability drives Ostwald ripening in foams and emulsions, where small droplets dissolve and redeposit onto larger ones.
How does pulmonary surfactant stop small alveoli from collapsing?
An alveolus behaves like a bubble at delta-P = 2*gamma/R, so if surface tension were fixed the smallest alveoli would sit at the highest pressure and drain into their larger neighbours. Pulmonary surfactant, a lipid-protein film, lowers the surface tension of the air-liquid lining and does so most strongly when the film is compressed, that is when the alveolus is small. Gamma falling in step with R keeps the pressure comparable across alveoli of different size and stabilises the lung.
What does Young's equation say about the contact angle?
Where a droplet edge meets a solid, the horizontal balance of the three interfacial tensions gives cos(theta) = (gamma_SV - gamma_SL)/gamma_LV, with the subscripts denoting solid-vapour, solid-liquid and liquid-vapour interfaces. A high-energy solid surface makes gamma_SV large, drives cos(theta) toward one and gives a spreading, wetting liquid. Contamination or a low-energy coating such as a fluoropolymer raises theta beyond 90 degrees, which flips capillary rise into capillary depression and reverses the sign of the pressure term.
How do you handle a concave interface and negative radii of curvature?
The radii carry a sign set by which fluid the interface curves toward. Convex outward, as for a droplet in air, gives a positive radius and pressure that is higher on the concave side, inside the drop. A wetting meniscus inside a capillary curves the other way, so the radius is taken as negative and the liquid just under the meniscus sits below atmospheric pressure. That negative capillary pressure is exactly what pulls the column upward. A saddle-shaped interface has radii of opposite sign and can give zero net pressure jump.
How does temperature change the pressure predicted by this equation?
Surface tension falls roughly linearly with temperature and vanishes at the critical point, where the liquid and vapour phases become indistinguishable and there is no interface left to hold tension. Water drops from about 72.8 mN/m at 20 degrees C to roughly 58.9 mN/m at 100 degrees C, so the excess pressure in a droplet of fixed radius falls by about the same proportion. Any surface tension value used here should therefore be quoted at the working temperature, not at room temperature by default.
References
Background & Theory
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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