STP Calculator
Calculate gas volume, moles, and mass at Standard Temperature and Pressure (STP). Convert between mass, moles, and volume using the molar volume of 22.414
STP Calculator
Calculator
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Formula: V = n * 22.414 L/mol (at STP)
Worked example โ V = 78.449 L at STP
Formula
V = n * 22.414 L/mol (at STP)
At STP (0 C, 1 atm), one mole of ideal gas occupies 22.414 liters. Volume equals moles times molar volume. To convert mass to volume, first divide mass by molar mass to get moles, then multiply by 22.414.
Worked Examples
Example 1: Volume of Oxygen at STP
Problem:What volume does 3.5 moles of O2 occupy at STP?
Solution:V = n * 22.414 L/mol V = 3.5 * 22.414 V = 78.449 L
Result:V = 78.449 L at STP
Example 2: Mass to Volume Conversion
Problem:What volume does 100 g of nitrogen gas (N2, M=28.014) occupy at STP?
Solution:n = mass / M = 100 / 28.014 = 3.5697 mol V = n * 22.414 = 3.5697 * 22.414 V = 80.013 L
Result:V = 80.013 L at STP
Frequently Asked Questions
What is STP in chemistry?
STP stands for Standard Temperature and Pressure, defined as 0 degrees Celsius (273.15 K) and 1 atmosphere (101.325 kPa) of pressure. At STP, one mole of an ideal gas occupies exactly 22.414 liters, known as the molar volume. This standard provides a common reference point for comparing gas properties and performing stoichiometric calculations. Note that IUPAC updated the standard in 1982 to 0 C and exactly 1 bar (100 kPa), giving a molar volume of 22.711 L, but the 1 atm definition remains widely used in education.
What is the molar volume of a gas at STP?
The molar volume at STP is 22.414 liters per mole for an ideal gas at 0 C and 1 atm. This value comes directly from the ideal gas law: V = nRT/P = (1 mol)(0.08206 L atm/mol K)(273.15 K)/(1 atm) = 22.414 L. Real gases deviate slightly from this value due to intermolecular forces and molecular volume. For example, CO2 has a molar volume of about 22.26 L at STP due to stronger intermolecular attractions, while helium is very close to ideal at 22.434 L.
How do I convert between mass and volume of a gas at STP?
To convert mass to volume at STP, first find moles by dividing mass by molar mass (n = m/M), then multiply by the molar volume (V = n * 22.414 L). For example, 44 g of CO2 (M = 44 g/mol) equals 1 mole, which occupies 22.414 L at STP. To go from volume to mass, divide the volume by 22.414 to get moles, then multiply by the molar mass. The density of any gas at STP equals its molar mass divided by 22.414 L/mol.
What is the difference between STP and NTP?
STP (Standard Temperature and Pressure) is 0 C and 1 atm, with a molar volume of 22.414 L/mol. NTP (Normal Temperature and Pressure) is 20 C (293.15 K) and 1 atm, with a molar volume of about 24.04 L/mol. Some references also define SATP (Standard Ambient Temperature and Pressure) as 25 C and 1 bar. The choice of standard conditions affects calculated volumes, so it is important to specify which standard is being used in any gas calculation.
How do you scale a gas volume from STP to other conditions?
Use the combined gas law, V2 = V1 x (P1/P2) x (T2/T1), with both temperatures in Kelvin and both pressures in the same unit. Warming one mole of an ideal gas from 273.15 K to 310 K at constant pressure gives 22.414 x 310 / 273.15, about 25.4 L. Working from the STP molar volume and then correcting is usually quicker than restarting from PV = nRT, and it makes it obvious which variable is driving the change.
How does STP simplify gas stoichiometry?
Avogadro's law says equal volumes of gases at the same temperature and pressure hold equal numbers of moles, so for gaseous reactants and products the coefficient ratios in the balanced equation are also volume ratios. In the reaction of two moles of hydrogen with one mole of oxygen to make water, 44.83 L of hydrogen at STP consumes 22.414 L of oxygen. You can therefore work in litres directly, without converting to moles and back.
How do you calculate the density of a gas at STP?
Density at STP is simply the molar mass divided by the molar volume, since one mole occupies 22.414 L. Oxygen at 32.00 g/mol gives 32.00 / 22.414 = 1.43 g/L, and nitrogen at 28.02 g/mol gives 1.25 g/L. Reversing this identifies an unknown gas: multiply a measured STP density in g/L by 22.414 to obtain its molar mass. Gases denser than air, whose mean molar mass is about 29 g/mol, collect in low spaces.
Why do real gases deviate from 22.414 L per mole?
The ideal gas law ignores both the finite size of molecules and the attractions between them. Attractions pull molecules together and shrink the volume below the ideal value, while the space the molecules themselves occupy pushes it above. The compressibility factor Z = PV/nRT captures the net effect and equals 1 for an ideal gas. Deviations grow at high pressure and near the condensation point, so gases such as carbon dioxide and ammonia depart more than helium or neon.
Which value of the gas constant R goes with which units?
R must match the units of pressure and volume. Use 0.08206 L x atm/(mol x K) with litres and atmospheres, 8.314 J/(mol x K) with cubic metres and pascals, and 62.36 L x Torr/(mol x K) with litres and torr. They are the same constant expressed differently: 8.314 divided by 101,325 pascals per atmosphere and multiplied by 1000 L per cubic metre gives 0.08206. Mismatched units are the single most common source of wrong gas-law answers.
How is a mixture of gases handled at STP?
In an ideal mixture each gas behaves independently, so partial volumes add (Amagat's law) just as partial pressures do (Dalton's law), and the total volume follows from the total number of moles: multiply the sum of the moles by 22.414 L/mol. Because all gases share the same molar volume, the mole fraction of a component equals its volume fraction, which is why air is described as roughly 21% oxygen by volume. Convert each component's mass to moles separately, then add, rather than averaging molar masses.
References
Background & Theory
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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