Packing Efficiency Calculator
Calculate packing efficiency and void space for crystal structures including SC, BCC, FCC, and HCP unit cells.
Packing Efficiency Calculator
Calculator
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Formula: PE = (Z * 4/3 * pi * r^3) / a^3 * 100%
Worked example โ Packing efficiency = 74.05%
Formula
PE = (Z * 4/3 * pi * r^3) / a^3 * 100%
Packing efficiency equals the total volume of atoms in the unit cell divided by the unit cell volume, expressed as a percentage. Z is atoms per cell, r is atomic radius, and a is edge length.
Worked Examples
Example 1: FCC Packing (Copper)
Problem:Calculate the packing efficiency of FCC copper with atomic radius 1.28 angstroms.
Solution:a = 2*sqrt(2)*r = 2 * 1.414 * 1.28 = 3.62 angstroms Atom volume = 4 * (4/3) * pi * (1.28)^3 = 35.09 Cell volume = 3.62^3 = 47.44 Packing efficiency = 35.09 / 47.44 = 74.05%
Result:Packing efficiency = 74.05%
Example 2: BCC Packing (Iron)
Problem:Calculate the packing efficiency of BCC iron with atomic radius 1.26 angstroms.
Solution:a = 4r/sqrt(3) = 4 * 1.26 / 1.732 = 2.91 angstroms Atom volume = 2 * (4/3) * pi * (1.26)^3 = 16.72 Cell volume = 2.91^3 = 24.58 Packing efficiency = 16.72 / 24.58 = 68.02%
Result:Packing efficiency = 68.02%
Frequently Asked Questions
What is packing efficiency in crystallography?
Packing efficiency is the percentage of total crystal volume that is occupied by atoms, assuming atoms are hard spheres. It measures how tightly atoms are packed in a crystal structure. Higher packing efficiency means less empty space (void) between atoms. The formula is (volume of atoms in unit cell / volume of unit cell) times 100. This property affects material density, mechanical strength, and how the material interacts with other substances at the atomic level.
What are the packing efficiencies for common crystal structures?
Simple cubic (SC) has a packing efficiency of 52.36%, meaning nearly half the volume is empty space. Body-centered cubic (BCC) achieves 68.02% packing efficiency. Face-centered cubic (FCC) and hexagonal close-packed (HCP) both reach the theoretical maximum for identical spheres at 74.05%. Diamond cubic, used by silicon and carbon diamond, has only 34.01% packing efficiency due to directional covalent bonding requiring specific geometric arrangements that leave more void space.
How does packing efficiency relate to material properties?
Materials with higher packing efficiency tend to have higher densities because more mass fits into the same volume. FCC metals like copper, aluminum, and gold are typically more ductile because their close-packed planes can slide over each other. BCC metals like iron and tungsten are generally harder and stronger. The void spaces in less efficiently packed structures can accommodate interstitial atoms, which is the basis for alloys like steel where carbon atoms fit into iron lattice voids.
What is the coordination number and how does it relate to packing?
The coordination number is the number of nearest neighbor atoms touching a given atom in a crystal structure. Simple cubic has a coordination number of 6, BCC has 8, and both FCC and HCP have 12. Higher coordination numbers generally correspond to higher packing efficiencies because each atom has more neighbors filling the surrounding space. The coordination number also influences bonding characteristics, melting points, and electrical conductivity of crystalline materials.
How is the edge length related to atomic radius in each cubic cell?
The relation depends on which direction the spheres actually touch. In simple cubic, neighbours touch along the cell edge, so a = 2r. In body-centred cubic, the corner atoms touch the central atom along the body diagonal, whose length is a*sqrt(3) and must equal 4r, giving a = 4r/sqrt(3). In face-centred cubic, contact runs along the face diagonal of length a*sqrt(2), which equals 4r, giving a = 2*sqrt(2)*r. Getting this geometry right is essential, because the edge length is cubed in the denominator and any error is tripled.
If FCC and HCP both reach 74 percent, what actually differs between them?
Both are built from identical close-packed layers of spheres; only the stacking sequence differs. Hexagonal close packing repeats every two layers in an ABAB pattern, placing the third layer directly above the first. Cubic close packing, which is the same arrangement as face-centred cubic viewed along a body diagonal, repeats every three layers as ABCABC. The local environment and coordination number of 12 are identical, so the density matches exactly, but the long-range symmetry differs and with it the number and orientation of slip systems, which is why FCC metals are generally more ductile.
Why is the diamond cubic structure so poorly packed?
Diamond cubic is not a sphere-packing arrangement at all; it is dictated by directional sp3 bonding, with each atom bonded tetrahedrally to exactly four neighbours instead of the 12 that close packing allows. The nearest-neighbour distance is one quarter of the body diagonal, so 2r = a*sqrt(3)/4 and a = 8r/sqrt(3). With eight atoms per cell that gives a packing efficiency of 34.01 percent, less than half the close-packed value. The open framework is why silicon, germanium and diamond are relatively low in density for their atomic masses, and why the open channels of the lattice allow interstitial diffusion of species such as lithium and copper.
How do I calculate theoretical density from the unit cell?
Density is the mass of the atoms in one cell divided by the cell volume: rho = Z*M / (NA * a^3), with Z atoms per cell, M the molar mass in g/mol, NA the Avogadro constant and a the edge length in centimetres. For face-centred cubic copper with Z = 4, M = 63.55 g/mol and a = 3.615e-8 cm, the cell volume is 4.724e-23 cm^3 and the density works out to about 8.94 g/cm^3, matching the measured value. Comparing calculated and measured density is a standard way to detect vacancies or non-stoichiometry.
What are tetrahedral and octahedral holes in a close-packed structure?
The 26 percent of space left empty in a close-packed array is not one continuous void but a regular set of interstitial sites. For every N spheres there are exactly N octahedral holes, surrounded by six spheres, and 2N tetrahedral holes, surrounded by four. Hard-sphere geometry sets their maximum guest sizes at radius ratios of 0.414 for octahedral and 0.225 for tetrahedral. Filling these sites in an ordered way generates whole structure families: rock salt fills every octahedral hole, zinc blende half the tetrahedral holes, and interstitial carbon in steel occupies octahedral sites in iron.
How does random close packing compare with a crystalline arrangement?
Pouring equal spheres into a container and shaking them produces a disordered arrangement that saturates near 64 percent, well below the 74 percent of an ordered close-packed lattice; gently poured without vibration the value falls closer to 60 percent. The gap explains why powders, catalyst beds and granular materials always contain more void space than the crystal structure of the same material implies. It is also why a poured bed can settle and densify under vibration, and why bulk density and true crystallographic density are different quantities that should never be substituted for one another.
References
Background & Theory
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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