Ligand Field Splitting Calculator
Calculate ligand field splitting energy (delta) for octahedral, tetrahedral, and square planar complexes.
Ligand Field Splitting Calculator
Calculator
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Formula: delta = hc/lambda = 1/lambda (cm-1)
Worked example โ Delta = 20,284 cm-1 | 242.6 kJ/mol | Purple-red complex
Formula
delta = hc/lambda = 1/lambda (cm-1)
Ligand field splitting delta can be measured from absorption spectra: delta = 1/lambda (in cm-1 when lambda is in cm). Conversion factors: 1 cm-1 = 0.01196 kJ/mol = 1.2398e-4 eV. For different geometries: delta_tet = (4/9) delta_oct, and delta_sq.planar is approximately 1.3 delta_oct. The color observed is complementary to the wavelength absorbed.
Worked Examples
Example 1: Ti3+ Aqua Complex Color
Problem:The [Ti(H2O)6]3+ ion absorbs at 493 nm. Calculate the ligand field splitting.
Solution:Wavelength = 493 nm Delta = 1/lambda = 10,000,000/493 = 20,284 cm-1 Delta in kJ/mol = 20,284 x 0.01196 = 242.6 kJ/mol Absorbed: blue-green (493 nm) Observed color: red-purple (complementary)
Result:Delta = 20,284 cm-1 | 242.6 kJ/mol | Purple-red complex
Example 2: Comparing Octahedral and Tetrahedral
Problem:For Co2+ with delta_oct = 9,300 cm-1, find the tetrahedral and square planar splitting values.
Solution:Delta_oct = 9,300 cm-1 Delta_tet = (4/9) x 9,300 = 4,133 cm-1 Delta_sq planar = 1.3 x 9,300 = 12,090 cm-1 Wavelength (oct) = 10^7/9,300 = 1,075 nm (infrared) Octahedral Co2+ complexes are often pink-red
Result:Oct = 9,300 | Tet = 4,133 | Sq. Planar = 12,090 cm-1
Frequently Asked Questions
What is ligand field splitting?
Ligand field splitting is the separation of d-orbital energies that occurs when ligands surround a transition metal ion, breaking the degeneracy of the five d orbitals. In a free ion, all five d orbitals have the same energy, but in a coordination complex, the electrostatic field of the ligands raises the energy of orbitals pointing toward the ligands and lowers the energy of those pointing between them. In octahedral complexes, this creates two groups: the lower-energy t2g set (dxy, dxz, dyz) and the higher-energy eg set (dx2-y2, dz2). The energy gap between these groups, called delta (or 10Dq), determines the complex color, magnetic properties, and thermodynamic stability.
How does the spectrochemical series rank ligand field strength?
The spectrochemical series arranges ligands from weakest to strongest field strength based on the magnitude of delta they produce. The approximate order is: I- < Br- < S2- < Cl- < N3- < F- < OH- < ox2- < H2O < NCS- < CH3CN < py < NH3 < en < bipy < phen < NO2- < PPh3 < CN- < CO < NO+. Weak field ligands like halides produce small splitting and tend to form high-spin complexes, while strong field ligands like cyanide and carbon monoxide produce large splitting and low-spin complexes. The position of a ligand depends on its sigma-donating ability, pi-donating or pi-accepting character, and the overlap between ligand and metal orbitals.
How does ligand field splitting determine the color of transition metal complexes?
The color of a transition metal complex arises from d-d electronic transitions where an electron absorbs visible light to jump from a lower to higher energy d orbital. The energy of the absorbed photon equals the ligand field splitting energy delta. Since delta corresponds to a specific wavelength, the complex absorbs that color and appears as the complementary color. For example, [Ti(H2O)6]3+ absorbs at about 500 nm (blue-green light) and appears purple-red. The relationship is delta = hc/lambda, where h is Planck constant, c is the speed of light, and lambda is the absorbed wavelength. Complexes with delta outside the visible range (380-740 nm) appear colorless.
Why does tetrahedral splitting differ from octahedral splitting?
Tetrahedral splitting differs from octahedral splitting in both magnitude and orbital ordering. In a tetrahedral field, ligands approach between the axes rather than along them, so the orbital energies are inverted: the e set (dx2-y2, dz2) is lower and the t2 set (dxy, dxz, dyz) is higher. The magnitude of tetrahedral splitting (delta-tet) is only about 4/9 of the octahedral value (delta-oct) for the same metal and ligands because there are fewer ligands (4 vs 6) and they interact less directly with the d orbitals. This smaller splitting means tetrahedral complexes are almost always high spin, since delta-tet is rarely large enough to force electron pairing.
What is the relationship between ligand field theory and crystal field theory?
Crystal field theory (CFT) and ligand field theory (LFT) both explain d-orbital splitting but differ in their treatment of metal-ligand bonding. CFT uses a purely electrostatic model where ligands are treated as point charges or dipoles, successfully predicting orbital splitting patterns and magnetic properties. However, CFT fails to explain the spectrochemical series order since uncharged ligands like CO should not produce stronger fields than charged ones like F-. Ligand field theory incorporates molecular orbital concepts, treating metal-ligand bonds as having both sigma and pi components. LFT explains why pi-acceptor ligands like CO are strong field (they stabilize t2g through backbonding) and why pi-donor ligands like halides are weak field.
What decides whether a complex is high spin or low spin?
The competition is between the splitting energy delta and the mean pairing energy P, the cost of forcing two electrons into the same orbital. When delta is smaller than P the electrons spread out across t2g and eg to stay unpaired, giving a high-spin complex; when delta exceeds P they fill the t2g set first, giving a low-spin complex. The question only arises for d4 through d7 configurations, since d1 to d3 and d8 to d10 have the same arrangement either way. Pairing energies for first-row ions typically fall in the range of roughly 15,000 to 25,000 cm-1.
What is crystal field stabilisation energy and how do I calculate it?
Crystal field stabilisation energy, or CFSE, is the net electronic energy gained relative to a hypothetical spherical field. In an octahedral complex each t2g electron contributes minus 0.4 delta and each eg electron plus 0.6 delta, so a low-spin d6 ion such as cobalt(III) in ammonia gives 6 times minus 0.4 = minus 2.4 delta, the largest value available. A high-spin d5 ion has three t2g and two eg electrons and a CFSE of exactly zero. CFSE helps rationalise the double-humped trends in hydration enthalpies and lattice energies across the first transition series.
How does the number of unpaired electrons relate to the measured magnetic moment?
For most first-row complexes the orbital contribution is largely quenched, so the spin-only formula applies: the magnetic moment in Bohr magnetons equals the square root of n times n plus 2, where n is the number of unpaired electrons. One unpaired electron gives 1.73, four gives the square root of 24 or 4.90, and five gives the square root of 35 or 5.92. Measuring the moment therefore distinguishes high-spin from low-spin directly, which is how iron(II) complexes with 4.9 and near 0 Bohr magnetons are assigned as high and low spin respectively.
Why are d8 complexes such as those of nickel, palladium and platinum often square planar?
Removing the two ligands along the z axis of an octahedron drops the energy of the dz2, dxz and dyz orbitals sharply and pushes dx2-y2 far above the rest. A d8 ion can then place all eight electrons in the four lower orbitals and leave the high dx2-y2 empty, which is strongly stabilising when the splitting is large. Because delta increases substantially on descending from 3d to 4d and 5d metals, palladium(II) and platinum(II) are almost invariably square planar and diamagnetic, while nickel(II) can be square planar with strong-field ligands such as cyanide but tetrahedral or octahedral with weak ones.
Why does the absorption maximum equal delta only for d1 and d9 ions?
With a single d electron, or a single hole in the d9 case, there is no electron-electron repulsion to complicate the excited state, so the one d-d band sits exactly at delta. Configurations from d2 to d8 have several electronic terms arising from interelectron repulsion, so the spectrum shows two or three bands, none of which corresponds directly to the splitting energy. Extracting delta then requires fitting the band positions to a Tanabe-Sugano diagram, which plots term energies against delta scaled by the Racah parameter B. Intense charge-transfer bands can also obscure the weaker d-d transitions.
References
Background & Theory
History
Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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