Average Atomic Mass Calculator
Calculate the weighted average atomic mass from isotope masses and their natural abundances. Supports 2-3 isotopes with percent or decimal input.
Average Atomic Mass Calculator
Calculator
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Formula: Average Mass = sum(mass_i * fractional_abundance_i)
Worked example โ Average atomic mass = 35.453 amu
Formula
Average Mass = sum(mass_i * fractional_abundance_i)
The average atomic mass is the sum of each isotope mass multiplied by its fractional natural abundance. This weighted average appears on the periodic table and represents the expected mass of a random atom from a natural sample.
Worked Examples
Example 1: Chlorine Average Atomic Mass
Problem:Cl-35: mass 34.969 amu, abundance 75.77%. Cl-37: mass 36.966 amu, abundance 24.23%
Solution:Average = 34.969(0.7577) + 36.966(0.2423) = 26.496 + 8.957 = 35.453 amu
Result:Average atomic mass = 35.453 amu
Example 2: Silicon with Three Isotopes
Problem:Si-28: 27.977 amu (92.23%), Si-29: 28.976 amu (4.67%), Si-30: 29.974 amu (3.10%)
Solution:Average = 27.977(0.9223) + 28.976(0.0467) + 29.974(0.0310) = 25.803 + 1.353 + 0.929 = 28.085 amu
Result:Average atomic mass = 28.085 amu
Frequently Asked Questions
What is average atomic mass?
Average atomic mass is the weighted average of the masses of all naturally occurring isotopes of an element, taking into account their relative abundances. It is the value reported on the periodic table and represents the expected mass of a randomly selected atom of that element from a natural sample. For example, chlorine has two stable isotopes: Cl-35 (75.77% abundance, 34.969 amu) and Cl-37 (24.23% abundance, 36.966 amu), giving an average atomic mass of 35.453 amu.
How do you calculate average atomic mass from isotope data?
Average atomic mass is calculated by multiplying each isotope mass by its fractional abundance (decimal form) and summing the products. The formula is: Average Mass = (mass_1 * fraction_1) + (mass_2 * fraction_2) + ... If abundances are given as percentages, divide each by 100 first. The fractional abundances must sum to 1.0 (or percentages to 100%). For example, boron has B-10 (19.9%, 10.013 amu) and B-11 (80.1%, 11.009 amu): Average = 10.013(0.199) + 11.009(0.801) = 10.811 amu.
Why is average atomic mass not a whole number?
Average atomic mass is almost never a whole number because it is a weighted average of multiple isotope masses, each of which is also not exactly a whole number due to nuclear binding energy effects. The mass of each isotope differs from its mass number because of mass defect, and the averaging across isotopes with different abundances produces a non-integer result. The only exception is fluorine, which has only one stable isotope (F-19), but even its precise atomic mass is 18.998 amu, not exactly 19. Carbon-12 is defined as exactly 12 amu by convention.
Can you determine isotope abundance from average atomic mass?
Yes, if you know the average atomic mass and the individual isotope masses, you can calculate the relative abundances for an element with two stable isotopes. Set the abundance of one isotope as x and the other as (1-x), then solve: Average Mass = mass_1(x) + mass_2(1-x). Rearranging gives x = (Average Mass - mass_2) / (mass_1 - mass_2). For elements with three or more isotopes, you need additional information such as the abundance of at least one isotope to solve the system of equations.
How do mass spectrometers determine isotope masses and abundances?
Mass spectrometers ionize atoms and accelerate them through a magnetic field, where they separate based on their mass-to-charge ratio. Lighter isotopes curve more in the magnetic field while heavier isotopes curve less, creating distinct peaks at each mass. The position of each peak gives the exact isotope mass, and the relative height or area of each peak corresponds to the relative abundance. Modern mass spectrometers can measure atomic masses to six or more decimal places and abundances to within 0.01%, making them the primary tool for determining the isotopic composition of elements.
What is the difference between mass number, isotopic mass, and atomic weight?
Mass number A is a whole-number count of protons plus neutrons in one nucleus, so chlorine-35 has A = 35 exactly. Isotopic mass is the actual measured mass of that nuclide in unified atomic mass units, 34.9689 u for chlorine-35, which differs from A because of nuclear binding energy. Atomic weight, the value on the periodic table, is the abundance-weighted mean of the isotopic masses for a natural sample, 35.45 for chlorine. Only the third is what Average Atomic Mass Calculator produces.
How is the unified atomic mass unit defined?
One unified atomic mass unit, symbol u and also called the dalton, is defined as one twelfth of the mass of a single free carbon-12 atom in its ground state, which fixes carbon-12 at exactly 12 u. In SI terms one u is approximately 1.6605e-27 kg. The choice of carbon-12 replaced earlier oxygen-based scales in 1961. Because of this definition, the molar mass of an element in grams per mole is numerically equal to its atomic weight in u for all practical laboratory purposes.
Why does IUPAC publish a range instead of a single atomic weight for some elements?
Isotopic abundances are not universal constants. Evaporation, diffusion, biological uptake and geological processes fractionate isotopes, so the same element genuinely differs in composition depending on where the sample came from. For elements where that variation exceeds measurement uncertainty, including hydrogen, lithium, boron, carbon, nitrogen, oxygen, silicon, sulfur, chlorine and bromine, the tabulated value is given as an interval. Boron spans roughly 10.806 to 10.821. Precise work should use abundances measured on the actual sample rather than a table value.
Why do mole conversions use the average atomic mass rather than the most abundant isotope?
A weighable sample contains on the order of 1e20 atoms drawn in their natural proportions, so its total mass reflects the whole mixture, not the dominant nuclide. Using 34.9689 for chlorine instead of 35.45 would understate the mass of a mole by about 1.4 percent, which propagates directly into every stoichiometric result. The weighted average is the expected mass per atom, so multiplying it by the Avogadro number gives exactly the mass per mole that a balance would register.
Why do chlorine and bromine compounds show a large M+2 peak in a mass spectrum?
Because the abundance ratio of the heavy isotope is large enough to be visible in a single molecule. Chlorine-35 and chlorine-37 occur in roughly a 3 to 1 ratio, so a monochlorinated compound shows a molecular ion peak and an M+2 peak about one third its height. Bromine-79 and bromine-81 are close to 1 to 1, giving twin peaks of nearly equal height. Carbon-13, at about 1.1 percent, instead produces a small M+1 peak whose relative height rises roughly in proportion to the number of carbon atoms.
References
Background & Theory
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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