COD/BOD Ratio Calculator
Calculate the COD to BOD ratio to assess wastewater biodegradability, determine treatment approach, and estimate pollutant loading rates.
COD/BOD Ratio Calculator
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Formula: COD/BOD Ratio = COD (mg/L) / BOD (mg/L)
Worked example โ Ratio = 2.0 (Biodegradable) - Biological treatment effective
Formula
COD/BOD Ratio = COD (mg/L) / BOD (mg/L)
The COD/BOD ratio divides Chemical Oxygen Demand by Biochemical Oxygen Demand. Low ratios indicate biodegradable waste suitable for biological treatment, while high ratios indicate recalcitrant compounds requiring chemical treatment.
Worked Examples
Example 1: Domestic Wastewater Assessment
Problem:COD = 500 mg/L, BOD = 250 mg/L, Flow = 1000 m3/day
Solution:COD/BOD = 500 / 250 = 2.0 Biodegradable fraction = 250/500 = 50% COD Load = 500 * 1000 / 1000 = 500 kg/day BOD Load = 250 * 1000 / 1000 = 250 kg/day
Result:Ratio = 2.0 (Biodegradable) - Biological treatment effective
Example 2: Industrial Effluent Evaluation
Problem:COD = 3000 mg/L, BOD = 400 mg/L
Solution:COD/BOD = 3000 / 400 = 7.5 Biodegradable fraction = 400/3000 = 13.3% Non-biodegradable COD = 3000 - 400 = 2600 mg/L
Result:Ratio = 7.5 (Poorly Biodegradable) - Chemical pretreatment required
Frequently Asked Questions
What does the COD/BOD ratio indicate?
The COD/BOD ratio is a key indicator of the biodegradability of wastewater. A low ratio (below 2.0) means most organic matter is biodegradable and can be efficiently treated using biological processes like activated sludge systems. A ratio between 2.0 and 4.0 indicates partial biodegradability, suggesting a combination of biological and chemical treatment may be needed. Ratios above 4.0 indicate predominantly non-biodegradable organic compounds that require advanced chemical oxidation or physical treatment methods.
What are typical COD/BOD ratios for different wastewaters?
Raw domestic sewage is the one well-characterised case, and it is conventionally quoted at around 2, which is why activated sludge works on it so reliably. Industrial figures vary far too much between sites, products and process stages to be treated as fixed per-industry bands, and any such table should be read as illustrative rather than used as a design input. What actually drives the number is the chemistry of the load: streams dominated by sugars, starches, fats and proteins stay low, while streams carrying synthetic dyes, surfactants, solvents, lignin, chelating agents or pharmaceutical residues run high, because dichromate oxidises those and a microbial seed largely does not. Measure your own effluent at the point you intend to treat it.
How are COD and BOD measured differently?
COD is measured by chemical oxidation using potassium dichromate under acidic conditions at high temperature, giving results within 2-3 hours. BOD is measured by incubating a sample with microorganisms for 5 days at 20 degrees Celsius (BOD5) and measuring dissolved oxygen consumption. Because COD chemically oxidizes all organic matter (biodegradable and non-biodegradable) plus some inorganic reducing agents, it always gives a higher value than BOD. The BOD test only measures the portion that microorganisms can metabolize.
Why is the COD/BOD ratio important for treatment plant design?
The COD/BOD ratio directly influences treatment plant design decisions, sizing, and operational parameters. A ratio below 2.5 allows engineers to design conventional activated sludge systems with confidence, knowing biological treatment will achieve 85-95 percent removal. Higher ratios require incorporating chemical treatment stages such as Fenton oxidation, ozonation, or electrochemical oxidation before biological stages. The ratio also affects sludge production estimates, aeration requirements, and the selection of specialized microorganism consortia for bioreactors.
Can I use a measured ratio to estimate BOD from COD and skip the five-day wait?
Only as a control tool on a stream you have already characterised. A plant that runs both tests in parallel for several weeks can regress BOD against COD and then infer BOD from the same-day COD, which is useful because a five-day result arrives long after the operating decision it should have informed. The correlation belongs to that effluent and holds only while the influent composition is stable, so a new trade discharge, a seasonal product change or a process upset breaks it without warning. Regulatory reporting still requires the actual determination, so a correlation supplements the test rather than replacing it.
How does nitrification distort a BOD5 result and shift the ratio?
The BOD bottle carries nitrifying bacteria alongside the heterotrophs, and once ammonia oxidation takes hold, which for raw municipal sewage is typically somewhere around the fifth to eighth day and only earlier when the seed is already nitrified, the oxygen those nitrifiers consume is added to the carbonaceous demand. BOD5 is inflated and the COD/BOD ratio comes out artificially low. Laboratories suppress this with a nitrification inhibitor such as allylthiourea or TCMP and report carbonaceous demand, cBOD5. Comparing an inhibited value for one stream against an uninhibited value for another makes the ratios meaningless, so always record which convention the number came from.
What does the optional COD/TSS ratio tell you?
Total suspended solids measure the particulate load retained on a filter, so dividing COD by TSS shows how much of the oxygen demand travels as particles rather than dissolved. A low COD/TSS means the organics are locked in settleable and filterable solids, which primary clarification, fine screening or dissolved air flotation can strip out cheaply before any biology. A high ratio means the demand is largely soluble and that same equipment will barely touch it. Filtering an aliquot and rerunning COD separates soluble from total COD directly.
How does the COD/BOD ratio change as water moves through a treatment plant?
Biological stages consume the readily degradable fraction first, so BOD falls faster than COD and the ratio climbs along the train. An influent at 2.0 can easily leave the secondary clarifier above 5, not because anything deteriorated but because only the refractory residue is left. Landfill leachate ages the same way: a young acidogenic leachate rich in volatile fatty acids sits near 2, while an aged methanogenic cell can exceed 10. Ratios are therefore only comparable when sampled at matching points in a process.
Why can a toxic industrial sample produce a misleadingly high ratio?
BOD5 records what the seed organisms actually metabolised, not what was metabolisable in principle. Heavy metals, solvents, biocides or extreme pH inhibit that seed, suppressing the measured BOD and driving the ratio up even when the organic matter is intrinsically degradable. The diagnostic clue is a dilution series that fails to scale, with heavily diluted bottles implying a higher BOD than concentrated ones. An acclimated seed, a seed control blank, and where the answer matters commercially a Zahn-Wellens inherent biodegradability test, separate toxicity from genuine recalcitrance.
What is ultimate BOD and how much of it does the five-day test capture?
Oxygen demand is exerted roughly as first-order kinetics, BOD_t = L x (1 - e^(-kt)), where L is the ultimate carbonaceous demand and k the deoxygenation rate constant at 20 degrees Celsius. The five-day figure is therefore only a portion of the total: with a rate constant near 0.23 per day, typical of municipal sewage, BOD5 recovers about 68 percent of L. Slowly degrading industrial waste has a smaller k, so its BOD5 understates the ultimate demand more severely and its ratio looks worse than the chemistry warrants.
References
Background & Theory
History
Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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