Gibbs Free Energy Calculator
Calculate Gibbs free energy to determine reaction spontaneity. Find deltaG from enthalpy and entropy, equilibrium constants, and crossover temperatures.
Gibbs Free Energy Calculator
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Formula: deltaG = deltaH - T * deltaS
Worked example — deltaG = -818.15 kJ/mol (Spontaneous) | K is astronomically large
Formula
deltaG = deltaH - T * deltaS
Where deltaG is the Gibbs free energy change (kJ/mol), deltaH is the enthalpy change (kJ/mol), T is absolute temperature (Kelvin), and deltaS is the entropy change (J/mol*K). A negative deltaG indicates a spontaneous process.
Worked Examples
Example 1: Combustion of Methane at 298 K
Problem:Calculate deltaG for CH4 combustion: deltaH = -890.3 kJ/mol, deltaS = -242.0 J/(mol*K), T = 298.15 K.
Solution:deltaG = deltaH - T * deltaS deltaG = -890.3 - (298.15)(-242.0/1000) deltaG = -890.3 - (-72.15) deltaG = -890.3 + 72.15 deltaG = -818.15 kJ/mol Since deltaG < 0, the reaction is spontaneous. K = exp(-deltaG / RT) = exp(818150 / (8.314 * 298.15)) = extremely large
Result:deltaG = -818.15 kJ/mol (Spontaneous) | K is astronomically large
Example 2: Equilibrium Temperature for CaCO3 Decomposition
Problem:CaCO3 -> CaO + CO2: deltaH = +178.3 kJ/mol, deltaS = +160.5 J/(mol*K). At what temperature is this spontaneous?
Solution:At equilibrium: deltaG = 0 0 = deltaH - T*deltaS T = deltaH / deltaS = 178.3 / (160.5/1000) T = 178.3 / 0.1605 = 1110.9 K = 837.8 C Above 1111 K, the reaction is spontaneous.
Result:Equilibrium temperature: 1110.9 K (837.8 C) | Spontaneous above this temperature
Frequently Asked Questions
What is Gibbs free energy and why is it important?
Gibbs free energy (G) is a thermodynamic potential that determines whether a process will occur spontaneously at constant temperature and pressure. The change in Gibbs free energy, deltaG = deltaH - T*deltaS, combines both the enthalpy change (heat absorbed or released) and the entropy change (disorder) into a single criterion for spontaneity. If deltaG is negative, the reaction proceeds spontaneously in the forward direction. If positive, the reverse reaction is favored. If zero, the system is at equilibrium. Gibbs free energy is arguably the most important quantity in chemical thermodynamics because it directly predicts reaction feasibility under the conditions most commonly encountered in chemistry and biology.
How do enthalpy and entropy compete to determine spontaneity?
The Gibbs equation reveals a competition between enthalpy (deltaH) and entropy (T*deltaS). There are four possible combinations. When deltaH is negative and deltaS is positive, deltaG is always negative and the reaction is spontaneous at all temperatures — energy is released and disorder increases. When deltaH is positive and deltaS is negative, deltaG is always positive and the reaction is never spontaneous. The interesting cases are when both terms have the same sign. If both deltaH and deltaS are negative (exothermic but ordering), spontaneity depends on temperature — the reaction is spontaneous at low temperatures where enthalpy dominates. If both are positive (endothermic but disordering), spontaneity occurs at high temperatures where the T*deltaS term overcomes deltaH.
What is the relationship between Gibbs free energy and equilibrium constant?
Gibbs free energy is directly related to the equilibrium constant through the equation deltaG_standard = -RT * ln(K), where R is the gas constant (8.314 J/mol*K) and K is the equilibrium constant. A large negative deltaG means a very large K (products strongly favored at equilibrium). A large positive deltaG means a very small K (reactants favored). When deltaG = 0, K = 1 and products and reactants are present in equal thermodynamic amounts. This relationship is fundamental to predicting the extent of chemical reactions and is used extensively in biochemistry to understand metabolic pathways, where coupled reactions with negative deltaG drive otherwise unfavorable reactions forward.
How does temperature affect Gibbs free energy?
Temperature appears explicitly in the Gibbs equation as the coefficient of the entropy term: deltaG = deltaH - T*deltaS. As temperature increases, the entropy contribution becomes more important. For reactions with positive deltaS (increasing disorder), higher temperatures make deltaG more negative, favoring spontaneity. For reactions with negative deltaS, higher temperatures make deltaG more positive, disfavoring the reaction. The crossover temperature where deltaG = 0 can be calculated as T = deltaH/deltaS. This temperature dependence explains many natural phenomena, such as why ice melts above 273 K (positive deltaS makes the process spontaneous) and why proteins denature at high temperatures (the entropy gain of unfolding overcomes the enthalpy of hydrogen bonds).
How do living cells use Gibbs free energy to power unfavorable reactions?
Many essential biochemical reactions, like building a protein from amino acids, have a positive deltaG on their own and would never occur spontaneously. Cells solve this by coupling those reactions to ATP hydrolysis, which has a strongly negative deltaG (about -30.5 kJ/mol under cellular conditions); combining the two reactions gives a net negative deltaG for the pair, making the overall coupled process spontaneous. This deltaG-coupling strategy is the thermodynamic basis of nearly all biosynthesis, active transport across cell membranes, and muscle contraction.
Why can a reaction have a favorable (negative) deltaG but still not happen quickly?
Gibbs free energy tells you only whether a reaction is thermodynamically favorable and how far it will proceed at equilibrium — it says nothing about how fast it gets there. A reaction can have a large negative deltaG yet be kinetically trapped by a high activation energy barrier, proceeding at an imperceptibly slow rate without a catalyst. Diamond converting to graphite (the more stable, lower-energy form of carbon) is the classic example: deltaG strongly favors graphite, yet diamonds persist indefinitely at room temperature because the activation energy for the conversion is enormous. This is why thermodynamics (deltaG) and kinetics (rate constants, activation energy) are always evaluated as two separate questions.
What is the difference between standard deltaG and deltaG under actual reaction conditions?
Standard deltaG refers to every species at its standard state, one bar for gases and one molar for solutes, and it is a fixed number for a given reaction and temperature. The working value under real conditions is deltaG equal to standard deltaG plus RT times the natural logarithm of the reaction quotient Q. As reactants convert to products Q rises, deltaG climbs toward zero, and the reaction halts when Q equals K. A positive standard deltaG can still permit net forward reaction while Q is small.
Why is entropy entered in J/(mol*K) while enthalpy is in kJ/mol?
The two quantities are tabulated in different units by convention: entropy changes are small numbers naturally expressed in joules, enthalpy changes are large ones expressed in kilojoules. The equation demands consistency, so the entropy term must be divided by 1000 before subtraction. For methane combustion, an entropy change of minus 242.0 J/(mol*K) at 298.15 K contributes minus 72.15 kJ/mol, not minus 72150. Forgetting this conversion produces an answer wrong by a factor of a thousand.
How does Gibbs free energy relate to the voltage of an electrochemical cell?
For a reaction run as a cell, standard deltaG equals minus n times the Faraday constant times the standard cell potential, where n is the number of electrons transferred and the Faraday constant is about 96485 coulombs per mole. A spontaneous reaction with negative deltaG therefore corresponds to a positive cell potential. A two-electron cell delivering 1.10 volts has a standard deltaG near minus 212 kJ/mol. The same relation run backwards gives the minimum voltage needed to drive an electrolysis.
How reliable is the crossover temperature when deltaH and deltaS come from room-temperature data?
Setting deltaG to zero and dividing enthalpy by entropy assumes both are independent of temperature, which they are not: each varies with the heat capacity difference between products and reactants, as Kirchhoff's law describes. Over a span of tens of degrees the error is usually small. Extrapolating tabulated 298 K values to the roughly 1111 K crossover for calcium carbonate decomposition is a much bigger stretch, so treat such a figure as an estimate to be checked against high-temperature data.
References
Background & Theory
History
Reviewed for accuracy by Manoj Kumar, Mathematics Educator · Editorial policy
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