Entropy Calculator: ΔS for Reactions & Phase Changes
Calculate the change in entropy for a reaction or phase change from the standard molar entropies of products and reactants.
Entropy Calculator: ΔS for Reactions & Phase Changes
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Formula: deltaS = Q_rev / T; deltaS_rxn = sum(S_products) - sum(S_reactants)
Worked example — deltaS = 22.00 J/(mol*K) — entropy increases during melting
Formula
deltaS = Q_rev / T; deltaS_rxn = sum(S_products) - sum(S_reactants)
For a reversible process, entropy change equals heat transferred divided by absolute temperature. For chemical reactions, entropy change is the difference between total standard molar entropies of products and reactants, weighted by stoichiometric coefficients.
Worked Examples
Example 1: Entropy Change of Ice Melting
Problem:Calculate the entropy change when 1 mole of ice melts at 273.15 K. The enthalpy of fusion is 6,010 J/mol.
Solution:deltaS = Q / T deltaS = 6010 J / 273.15 K deltaS = 22.00 J/(mol*K) This is positive because melting increases molecular disorder — liquid water has more microstates than solid ice.
Result:deltaS = 22.00 J/(mol*K) — entropy increases during melting
Example 2: Reaction Entropy for Combustion of Carbon
Problem:Find deltaS for C(s) + O2(g) -> CO2(g). Standard entropies: C(s) = 5.7, O2(g) = 205.2, CO2(g) = 213.8 J/(mol*K).
Solution:deltaS_rxn = S(products) - S(reactants) deltaS_rxn = [213.8] - [5.7 + 205.2] deltaS_rxn = 213.8 - 210.9 deltaS_rxn = 2.9 J/(mol*K)
Result:deltaS = 2.9 J/(mol*K) — slight entropy increase (1 mol gas produces 1 mol gas)
Frequently Asked Questions
What is entropy in chemistry?
Entropy (S) is a thermodynamic quantity that measures the degree of randomness or disorder in a system. In statistical mechanics, entropy is defined as S = k_B * ln(W), where k_B is Boltzmann constant and W is the number of microstates available to the system. A higher entropy means more possible arrangements of particles and energy. Entropy always increases for the universe as a whole (Second Law of Thermodynamics), though individual systems can decrease in entropy if a greater increase occurs elsewhere. In chemistry, entropy changes during reactions help determine whether a process is spontaneous by contributing to the Gibbs free energy equation deltaG = deltaH - T*deltaS.
What is the Second Law of Thermodynamics?
The Second Law states that the total entropy of an isolated system can only increase over time, or remain constant in the case of a reversible process. It never spontaneously decreases. This law explains why heat flows from hot to cold, why gases expand to fill their containers, and why certain reactions proceed in one direction but not the reverse. For chemical processes, the total entropy change includes both the system entropy and the surroundings entropy: deltaS_total = deltaS_system + deltaS_surroundings. A spontaneous process always has deltaS_total greater than zero. The surroundings entropy change equals -deltaH_system / T, which connects the Second Law directly to heat transfer and temperature.
How do you predict the sign of entropy change for a reaction?
Several qualitative rules help predict whether entropy increases or decreases in a chemical reaction. Entropy generally increases when: solids dissolve into solution, liquids vaporize to gases, the number of gas molecules increases (e.g., 1 mol gas producing 2 mol gas), temperature increases, or complex molecules decompose into simpler ones. Entropy generally decreases when: gases condense or are absorbed, molecules combine to form larger molecules, or crystallization occurs from solution. For example, the reaction 2H2O(l) producing 2H2(g) + O2(g) has a large positive entropy change because liquid water becomes three moles of gas, dramatically increasing the number of possible microstates.
What are standard molar entropies and how are they used?
Standard molar entropies (S degrees) are the absolute entropy of one mole of a substance at 298.15 K and 1 atm pressure, measured in J/(mol*K). Unlike enthalpies of formation, standard entropies are never zero because even perfect crystals at 0 K have S = 0 (Third Law of Thermodynamics), and heating to 298 K always adds entropy. Typical values range from about 5 J/(mol*K) for diamond to over 200 J/(mol*K) for gases. To calculate the entropy change of a reaction: deltaS_rxn = sum(n*S_products) - sum(n*S_reactants). These values are extensively tabulated in thermochemical reference databases and are essential for calculating Gibbs free energy and determining reaction spontaneity.
Why must the heat used in deltaS equals Q over T come from a reversible path?
Entropy is a state function, so its change depends only on the endpoints, but the Clausius inequality says the heat actually exchanged along an irreversible path divided by T underestimates it. The standard trick is to invent any convenient reversible path between the same initial and final states and integrate along that instead. An ideal gas expanding freely into a vacuum exchanges no heat at all, yet its entropy rises by nR times the natural log of the volume ratio, a value obtained from an imagined isothermal reversible expansion.
How does the Gibbs free energy criterion follow from the second law?
Spontaneity is decided by the total entropy of system plus surroundings. At constant pressure the surroundings absorb the reaction enthalpy, so their entropy change is minus deltaH of the system divided by T. Writing deltaS total as deltaS system minus deltaH over T and multiplying through by minus T gives deltaH minus T deltaS, which is deltaG. A negative deltaG is therefore just a restatement that total entropy increased, which is why the free energy criterion needs no separate justification.
At what temperature does an endothermic reaction with a positive entropy change become spontaneous?
Set deltaG to zero in deltaH minus T deltaS and solve: the crossover temperature is deltaH divided by deltaS, with both quantities on the same energy basis. A reaction absorbing 100 kJ per mole while raising entropy by 150 J per mole per kelvin turns spontaneous above 100,000 divided by 150, about 667 K. Below that the enthalpy penalty dominates. Endothermic decompositions that release gas behave this way, which is why they need heating while exothermic entropy-losing reactions reverse on heating.
How are absolute standard molar entropies actually measured?
Calorimetrically, using the third law as the zero point. Heat capacity is measured from as close to absolute zero as the apparatus allows and the quantity Cp divided by T is integrated with respect to temperature up to 298.15 K, with the entropy of each phase change added separately as the transition enthalpy divided by the transition temperature. Below the lowest measured point a Debye cubic extrapolation fills the gap. This is why tabulated entropies are absolute values rather than differences from an arbitrary reference state.
Why do gases have far larger molar entropies than solids?
Translational freedom dominates the microstate count. A gas molecule can occupy an enormous number of position and momentum states within its container, whereas atoms in a crystal only vibrate about fixed lattice sites. Within each phase the value rises with molar mass and molecular complexity, since heavier molecules have more closely spaced translational levels and polyatomic ones add rotational and vibrational modes. That is the spread from about 2.4 for diamond through 69.9 for liquid water to 213.8 for carbon dioxide gas, in joules per mole per kelvin.
What is residual entropy and does it contradict the third law?
Some substances freeze into a disordered arrangement that cannot relax as they are cooled, so they retain entropy at absolute zero. Carbon monoxide, whose molecules can point either way in the lattice with almost no energy difference, keeps close to R times the natural log of 2, about 5.8 joules per mole per kelvin, and ordinary ice retains around 3.4 from the many allowed hydrogen bonding arrangements. The third law refers to a perfect crystal in true equilibrium, so these frozen-in cases are an exception to the ideal, not a violation.
References
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator · Editorial policy
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