Reaction Order Calculator (Rate Law Method)
Determine reaction order from concentration and rate data using the integrated rate law method, plus the rate constant.
Reaction Order Calculator (Rate Law Method)
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Formula: n = ln(rate2/rate1) / ln([A]2/[A]1)
Worked example โ Order = 2 (second order), k = 1.5 M^-1 s^-1
Formula
n = ln(rate2/rate1) / ln([A]2/[A]1)
The reaction order n is found by comparing rates from two experiments where only one reactant concentration changes. Taking the natural log of the rate ratio divided by the natural log of the concentration ratio gives the order. The rate constant k is then found by substituting back into the rate law.
Worked Examples
Example 1: Determining Order from Two Experiments
Problem:Experiment 1: [A] = 0.10 M, rate = 0.015 M/s. Experiment 2: [A] = 0.20 M, rate = 0.060 M/s. Find the reaction order.
Solution:Rate ratio = 0.060 / 0.015 = 4.0 Conc ratio = 0.20 / 0.10 = 2.0 n = ln(4.0) / ln(2.0) = 1.386 / 0.693 = 2 k = 0.015 / (0.10)^2 = 1.5 M^-1 s^-1
Result:Order = 2 (second order), k = 1.5 M^-1 s^-1
Example 2: First Order Reaction Identification
Problem:Experiment 1: [A] = 0.50 M, rate = 0.010 M/s. Experiment 2: [A] = 1.50 M, rate = 0.030 M/s.
Solution:Rate ratio = 0.030 / 0.010 = 3.0 Conc ratio = 1.50 / 0.50 = 3.0 n = ln(3.0) / ln(3.0) = 1 k = 0.010 / 0.50 = 0.02 s^-1
Result:Order = 1 (first order), k = 0.02 s^-1
Frequently Asked Questions
What is reaction order in chemistry?
Reaction order describes how the rate of a chemical reaction depends on the concentration of a particular reactant. A first-order reaction rate doubles when the reactant concentration doubles, a second-order reaction rate quadruples when concentration doubles, and a zero-order reaction rate is independent of concentration. The overall reaction order is the sum of all individual orders. Reaction orders are determined experimentally using the method of initial rates or integrated rate law analysis.
How does the method of initial rates work?
The method of initial rates involves running a reaction multiple times with different initial concentrations while measuring the initial rate each time. By changing only one reactant concentration between experiments and keeping others constant, you can isolate the effect of that reactant. The reaction order is found by taking the ratio of rates and concentrations: n = ln(rate2/rate1) / ln([A]2/[A]1). This method requires at least two experiments per reactant to determine each individual order.
Can reaction order be a fraction or negative?
Yes, reaction orders can be fractional, zero, or even negative. Fractional orders (like 0.5 or 1.5) often indicate complex reaction mechanisms with multiple elementary steps. Negative orders mean that increasing the concentration of a reactant actually slows the reaction, which can occur when a reactant inhibits a catalytic surface or competes for active sites. Zero-order reactions proceed at a constant rate regardless of concentration, commonly seen in enzyme-catalyzed reactions at saturation.
What are integrated rate laws and how do they relate to reaction order?
Integrated rate laws describe how concentration changes over time for each reaction order. For zero order: [A] = [A]0 - kt (linear in [A] vs t). For first order: ln[A] = ln[A]0 - kt (linear in ln[A] vs t). For second order: 1/[A] = 1/[A]0 + kt (linear in 1/[A] vs t). By plotting experimental data in these forms, the one that gives a straight line reveals the reaction order. The slope of the straight line gives the rate constant k.
How does the half-life method reveal the reaction order?
Watch how successive half-lives behave. For a first-order reaction each half-life is identical, since it equals ln(2)/k regardless of concentration. For a second-order reaction the half-life is 1/(k x initial concentration), so it doubles with each successive halving. For a zero-order reaction the half-life is the initial concentration over 2k, so it halves each time. Comparing the first and second half-life from a single run is often enough to pin the order without any plotting.
Why must rates be measured at the very start of the reaction?
At time zero the concentrations are exactly what you weighed out, no products have accumulated, so the reverse reaction is negligible and there is no product inhibition or catalyst poisoning yet. Once the reaction has progressed, the measured rate reflects a mixture of forward and reverse processes and the working concentrations are no longer known precisely. Using an initial slope, taken from the tangent to the concentration curve at t equals zero, keeps the comparison between experiments clean.
Why can the exponents not be read off the balanced equation?
Stoichiometric coefficients describe the overall bookkeeping of atoms, while the exponents in the rate law describe only the species involved up to and including the rate-determining elementary step. Coefficients equal orders solely for a single elementary step, where molecularity and order coincide. For any multi-step reaction the two can differ, and a species that appears in the balanced equation may not appear in the rate law at all. Orders must therefore be measured, never assumed.
How do you calculate the rate constant once the order is known?
Substitute back into the rate law: k = rate divided by concentration raised to the order. If the measured rate is 4.0 x 10 to the minus 3 mol/(L x s) at a reactant concentration of 0.20 mol/L and the order is 2, then 0.20 squared is 0.040, and k = 4.0 x 10 to the minus 3 divided by 0.040 = 0.10 L/(mol x s). Repeating this with each experiment and checking that k comes out the same is the standard consistency test on the fitted order.
How does an isolation experiment simplify order determination?
Flood the mixture with a large excess of every reactant except the one being studied. Those excess concentrations then stay effectively constant, so the observed rate depends only on the isolated reactant and the measured pseudo-order is that reactant's true order. Repeat with a different reactant isolated to get the next order, then combine them for the overall rate law. This avoids the algebra of solving for several exponents at once from mixed experiments.
Why can the measured order change at different concentrations?
An order is only constant while the same step limits the rate. Enzyme-catalysed and surface-catalysed reactions look first order at low substrate concentration but shift toward zero order once the binding sites are saturated, because the rate is then set by the number of sites rather than by concentration. Similar changeovers occur when a fast pre-equilibrium becomes rate limiting. Report the concentration range over which an order was measured, not just the number.
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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