Percent Purity Calculator
Calculate the percent purity of a chemical sample from mass data. Determine impurity content, moles of pure substance, and concentration in solution.
Percent Purity Calculator
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Formula: Percent Purity = (Mass of Pure Substance / Mass of Impure Sample) x 100
Worked example โ Percent Purity: 90.00% | Impurity: 0.50 g (10.00%)
Formula
Percent Purity = (Mass of Pure Substance / Mass of Impure Sample) x 100
Where Mass of Pure Substance is the mass of the desired compound isolated or measured, and Mass of Impure Sample is the total mass of the original sample containing both the pure substance and impurities.
Worked Examples
Example 1: Recrystallization Purity Check
Problem:A student dissolves 5.00 g of impure sodium chloride and recovers 4.50 g of pure NaCl after recrystallization. What is the percent purity?
Solution:Percent Purity = (Mass of Pure / Mass of Sample) x 100 Percent Purity = (4.50 g / 5.00 g) x 100 Percent Purity = 0.900 x 100 = 90.00% Mass of impurity = 5.00 - 4.50 = 0.50 g
Result:Percent Purity: 90.00% | Impurity: 0.50 g (10.00%)
Example 2: Pharmaceutical Aspirin Analysis
Problem:A 500 mg aspirin tablet is analyzed and found to contain 487 mg of acetylsalicylic acid. Determine the percent purity.
Solution:Percent Purity = (Mass of Pure / Mass of Sample) x 100 Percent Purity = (487 mg / 500 mg) x 100 Percent Purity = 0.974 x 100 = 97.40% Impurity content = 500 - 487 = 13 mg (2.60%)
Result:Percent Purity: 97.40% | Impurity: 13 mg (2.60%) - Technical Grade
Frequently Asked Questions
What is percent purity and why is it important in chemistry?
Percent purity is a measure of how much of a desired substance is present in a sample compared to the total mass of the sample, expressed as a percentage. It is calculated by dividing the mass of the pure substance by the total mass of the sample and multiplying by 100. This measurement is critically important in analytical chemistry because impurities can affect reaction yields, product quality, and safety. Pharmaceutical companies must ensure drug purity exceeds strict thresholds set by regulatory agencies. In industrial chemistry, knowing the purity of reagents ensures accurate stoichiometric calculations and reproducible experimental results.
How do you calculate percent purity from experimental data?
To calculate percent purity from experimental data, you need two key measurements: the mass of the pure substance recovered or identified and the total mass of the original impure sample. The formula is Percent Purity = (Mass of Pure Substance / Mass of Impure Sample) x 100. For example, if you dissolve 5.0 grams of impure sodium chloride and recover 4.5 grams of pure NaCl through recrystallization, your percent purity is (4.5 / 5.0) x 100 = 90%. Various analytical techniques such as titration, chromatography, and spectroscopy can be used to determine the mass of the pure component.
What factors can affect the purity of a chemical sample?
Several factors influence the purity of a chemical sample. The synthesis method plays a major role, as side reactions can produce unwanted byproducts that contaminate the desired product. Storage conditions matter because exposure to moisture, air, or light can degrade substances over time, introducing impurities. The quality of starting reagents directly impacts final product purity. Purification techniques such as distillation, recrystallization, filtration, and chromatography each have different efficiencies depending on the substance. Handling and contamination during transfer between containers can also introduce impurities. Temperature fluctuations during storage may cause decomposition of sensitive compounds.
What are common methods for purifying chemical substances?
Common purification methods include recrystallization, where a substance is dissolved in a hot solvent and slowly cooled to form pure crystals while impurities remain in solution. Distillation separates substances based on differences in boiling points and is effective for liquid mixtures. Chromatography separates components based on their differential affinity for a stationary phase versus a mobile phase, and is widely used in pharmaceutical and biochemical analysis. Filtration removes insoluble impurities from solutions. Sublimation purifies substances that transition directly from solid to gas phase. Extraction uses two immiscible solvents to separate compounds based on their solubility preferences.
How does percent purity relate to chemical grades and standards?
Chemical grades define the minimum purity levels required for specific applications. ACS Reagent Grade chemicals meet American Chemical Society standards and typically have purity above 99.0 percent, suitable for quantitative analytical work. USP/NF Grade meets United States Pharmacopeia standards for pharmaceutical use. Technical Grade chemicals have purities around 90 to 95 percent and are acceptable for industrial applications but not precise analytical work. Laboratory Grade is suitable for educational experiments but not quantitative analysis. Crude or practical grade chemicals have the lowest purity. Understanding these grades helps researchers select appropriate chemicals for their applications and budget constraints.
What is the difference between percent purity and percent yield?
They answer different questions and are calculated from different quantities. Percent purity is a property of a sample: the mass of the target compound divided by the total mass of that sample. Percent yield is a property of a reaction: the mass actually obtained divided by the theoretical mass predicted by stoichiometry from the limiting reagent. A synthesis can give a high yield of a badly contaminated solid, or a low yield of material that is essentially pure. Rigorous work reports both, and often multiplies them to state a corrected yield of pure product.
How much impure reagent should you weigh out to get a required amount of the pure substance?
Divide the mass you need by the purity expressed as a decimal fraction. Suppose a procedure calls for 0.100 mol of sodium chloride, molar mass 58.44 g/mol, which is 5.844 g of the pure salt, and your bottle is certified at 90 percent. Weighing 5.844 divided by 0.90 gives 6.49 g of the impure solid, which contains the required 5.844 g of sodium chloride. Skipping this correction makes the reagent the unintentional limiting component and quietly shifts the stoichiometry of every subsequent step.
How does purity change the molarity of a solution prepared from a weighed solid?
Only the pure fraction contributes solute, so convert that mass to moles before dividing by the volume in litres. Taking 4.50 g of genuine sodium chloride from a 5.00 g sample and dividing by the molar mass of 58.44 g/mol gives 0.0770 mol; made up to 250 mL, that is 0.0770 divided by 0.250, or 0.308 mol/L. Using the full 5.00 g would have overstated the concentration by about eleven percent. The error propagates directly into any titre, dilution or calibration curve built on that stock solution.
How is percent purity determined by titration?
Titration measures the moles of the active component, which are then converted back to a mass. React the weighed sample with a standardised titrant to a defined endpoint, multiply the titrant volume in litres by its molarity to get moles of titrant, apply the stoichiometric ratio of the reaction to obtain moles of analyte, and multiply by the analyte molar mass. Dividing that mass by the sample mass gives the purity. The method assumes no impurity reacts with the titrant, which is why acid-base assays of an acidic solid can read high if acidic contaminants are present.
Why can chromatographic area-percent purity disagree with a mass-balance assay?
Area normalisation in HPLC assumes every component elutes and responds to the detector in proportion to its mass, which is rarely true. Inorganic salts, residual solvent and water give no ultraviolet absorbance at all, and strongly retained species may never leave the column, so they are simply invisible and the area percent looks flattering. A mass-balance assay instead subtracts separately measured water, usually by Karl Fischer titration or loss on drying, plus residual solvent and ash, and therefore often lands one or two percent lower on hygroscopic solids.
References
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Reviewed for accuracy by Manoj Kumar, Mathematics Educator ยท Editorial policy
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