Restriction MAP Calculator
Find restriction enzyme recognition sites in DNA sequences. Calculate fragment sizes, visualize cut positions, and plan digestion experiments.
Restriction MAP Calculator
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Formula: Fragments (linear) = Cut sites + 1; Fragments (circular) = Cut sites
Worked example โ 3 EcoRI sites found, producing 4 fragments (4, 14, 24, 10 bp)
Formula
Fragments (linear) = Cut sites + 1; Fragments (circular) = Cut sites
For linear DNA, each restriction cut divides a fragment into two, so n cuts produce n+1 fragments. For circular DNA (plasmids), n cuts produce exactly n fragments since there are no free ends. Fragment sizes are determined by the distances between consecutive cut positions.
Worked Examples
Example 1: EcoRI Digestion of a Plasmid Insert
Problem:A 52 bp linear DNA fragment ATCGAATTCGATCGATCGAATTCGATCGGGATCCATCGATCGAATTCGATCG contains EcoRI (GAATTC) sites. How many fragments result?
Solution:Scan for GAATTC in the sequence (EcoRI cuts G^AATTC, i.e. after the G): Site starts at position 4: cut after base 4 Site starts at position 18: cut after base 18 Site starts at position 42: cut after base 42 3 cut sites in linear DNA = 4 fragments Fragment sizes: 4, 14 (5-18), 24 (19-42), and 10 (43-52) bp = 52 bp total
Result:3 EcoRI sites found, producing 4 fragments (4, 14, 24, 10 bp)
Example 2: Double Digest with EcoRI and BamHI
Problem:The same 52 bp sequence also contains a BamHI site (GGATCC). Perform a double digest.
Solution:EcoRI cuts after bases 4, 18 and 42 (3 cuts) BamHI (G^GATCC) site starts at position 29, so it cuts after base 29 (1 cut) Total: 4 unique cut positions Linear DNA: 4 cuts = 5 fragments Fragment sizes: 4, 14 (5-18), 11 (19-29), 13 (30-42) and 10 (43-52) bp = 52 bp total
Result:4 total cuts (3 EcoRI + 1 BamHI) = 5 fragments of 4, 10, 11, 13 and 14 bp for gel analysis
Frequently Asked Questions
What is a restriction map and why is it important?
A restriction map is a diagram showing the locations of restriction enzyme recognition sites along a DNA molecule. It is one of the most fundamental tools in molecular biology, used for cloning strategy design, vector construction, and DNA fingerprinting. By digesting DNA with known restriction enzymes and analyzing fragment sizes on agarose gels, researchers can verify plasmid constructs, map gene locations, and plan subcloning experiments. Restriction maps were historically the first step in characterizing unknown DNA before sequencing became affordable.
How do restriction enzymes cut DNA?
Restriction enzymes (restriction endonucleases) are bacterial proteins that recognize specific palindromic DNA sequences and cleave the phosphodiester backbone at precise positions. Type II restriction enzymes (used in cloning) cut within or near their recognition site. For example, EcoRI recognizes GAATTC and cuts between G and AATTC on both strands, creating 4-nucleotide 5-prime overhangs called sticky ends. Some enzymes like SmaI cut at the center of their recognition site creating blunt ends. The position and type of cut determines which fragments can be ligated together during cloning.
What is the difference between single and double digestion?
Single digestion uses one restriction enzyme to cut DNA, producing fragments whose number equals the number of cut sites plus one (for linear DNA). Double digestion uses two enzymes simultaneously, potentially producing more and smaller fragments. Double digestion is essential for directional cloning, where an insert is cut with two different enzymes to ensure it can only ligate into the vector in one orientation. When planning a double digest, it is important to verify that both enzymes are active in the same buffer conditions and at the same temperature, which is why tools like NEB DoubleDigest Finder exist.
How does circular vs linear DNA affect the restriction map?
For linear DNA, the number of fragments equals the number of cut sites plus one, because the two ends of the molecule create additional fragment boundaries. For circular DNA (like plasmids), the number of fragments equals exactly the number of cut sites, because the molecule has no free ends. A single cut in a circular plasmid linearizes it into one fragment. Two cuts produce two fragments. This distinction is critical when predicting gel patterns. A 5 kb circular plasmid cut once gives a single 5 kb band, while cutting the same sequence if it were linear gives two fragments whose sizes sum to 5 kb.
How do I choose the right restriction enzymes for cloning?
Selecting restriction enzymes for cloning requires checking several criteria. First, the enzymes should cut at the desired insert boundaries but not internally within the insert or vector backbone. Second, the two enzymes should produce compatible but non-identical ends for directional cloning. Third, both enzymes should be active in a common buffer at the same temperature. Fourth, methylation sensitivity must be considered since some enzymes are blocked by Dam or Dcm methylation in E. coli. Finally, ensure adequate flanking sequence outside the recognition site for efficient cutting near DNA ends, typically requiring 4-6 extra base pairs beyond the recognition sequence.
How often is a recognition site expected to occur by chance?
In random DNA of balanced base composition, each position has a one in four chance of matching a given base, so an n-base site is expected roughly once every 4 to the power n bases. A four-cutter turns up about every 256 bp, a six-cutter such as EcoRI or BamHI about every 4,096 bp, and an eight-cutter such as NotI about every 65,536 bp. Real genomes depart from this because base composition is skewed: the all-GC NotI site is far rarer than predicted in AT-rich genomes, which is why it is chosen for mapping very large fragments.
Why do blunt-end ligations work less efficiently than sticky-end ligations?
An enzyme that cuts off-centre leaves single-stranded overhangs, so an insert and vector cut with the same enzyme anneal transiently through complementary base pairing and hold the nick in place while DNA ligase seals the backbone. SmaI and other centre-cutting enzymes leave flush ends with nothing to base pair, so the two molecules must collide in the correct register by chance alone. Blunt ligations therefore need higher DNA concentrations and longer incubations, and because any blunt end joins any other, they lose the directionality that a two-enzyme digest provides.
How do Dam and Dcm methylation block a digest that the map predicts?
Standard laboratory Escherichia coli strains carry two methyltransferases. Dam methylates the adenine in GATC and Dcm methylates the internal cytosine in CCWGG. When one of these motifs overlaps a recognition site, the modified base can prevent the enzyme binding, so a site that is present in the sequence is simply not cut in plasmid prepared from that host. The remedies are to grow the plasmid in a dam minus dcm minus strain, to amplify the region by PCR, which yields unmethylated product, or to choose an insensitive isoschizomer.
What is star activity and what conditions provoke it?
Star activity is relaxed specificity: under non-optimal conditions an enzyme cleaves sequences that differ from its true recognition site, usually by one base. It is promoted by too much enzyme relative to DNA, glycerol carried over from the storage buffer above roughly five percent of the reaction volume, prolonged incubation, low ionic strength, and substituting manganese for magnesium. The result is extra bands the map does not predict. Keeping the enzyme below about ten percent of the reaction volume, using the recommended buffer, and shortening the incubation prevent it.
How are fragment sizes read off an agarose gel?
Duplex DNA migrates through the gel matrix at a rate that varies roughly with the logarithm of its length, so plotting log size against migration distance for a ladder gives a calibration line from which unknown bands are interpolated. Gel percentage sets the useful window: low percentage gels resolve large fragments while higher percentages separate small ones. Fragments that differ by only a few percent co-migrate, and very small fragments can run off the gel entirely, so a digest that appears to produce fewer bands than the map predicts may simply be under-resolved.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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