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Solar System Scale Model Calculator

Calculate scaled distances and sizes for a solar system scale model at any chosen scale. Enter values for instant results with step-by-step formulas.

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Astronomy & Space Science

Solar System Scale Model Calculator

Calculate scaled distances and sizes for a solar system scale model at any chosen scale. See how planet sizes and orbital distances translate to a hands-on model.

Last updated: December 2025Reviewed by NovaCalculator Mathematics Team

Calculator

Adjust values & calculate
30 cm
Scale Ratio
1 : 46,423
Model Sun: 30 cm

Scaled Planet Sizes and Distances

Mercury
Real: 4,879 km diameter
1.05 mm
12.47 m away
Venus
Real: 12,104 km diameter
2.61 mm
23.31 m away
Earth
Real: 12,756 km diameter
2.75 mm
32.23 m away
Mars
Real: 6,792 km diameter
1.46 mm
49.09 m away
Jupiter
Real: 142,984 km diameter
3.08 cm
167.72 m away
Saturn
Real: 120,536 km diameter
2.60 cm
308.79 m away
Uranus
Real: 51,118 km diameter
1.10 cm
618.76 m away
Neptune
Real: 49,528 km diameter
1.07 cm
968.28 m away
Moon (scaled)
0.75 mm
8.28 cm from Earth
Pluto (dwarf planet)
0.51 mm
1.27 km away
Nearest Star (Proxima Centauri)
8194.16 km
at this model scale
Tip: Planet sizes and distances use the same scale factor. In reality, most scale models cannot show both sizes and distances at the same scale because the distances are so enormous compared to the sizes.
Your Result
Scale: 1:46,423 | Earth: 2.75 mm at 32.23 m
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Understand the Math

Formula

Scaled Size = Real Size x (Model Sun Diameter / 1,392,700 km)

The scale factor is determined by dividing your chosen model Sun diameter by the real Sun diameter (1,392,700 km). This same factor is applied uniformly to all planet diameters and orbital distances to maintain correct proportions throughout the model.

Last reviewed: December 2025

Worked Examples

Example 1: Classroom Model with 30 cm Sun

Build a solar system scale model with the Sun represented by a 30 cm ball. What are the scaled planet sizes and distances?
Solution:
Scale factor: 30 cm / 1,392,700 km = 1:4,642,333,333 Earth diameter: 12,756 km x scale = 0.275 cm (2.75 mm, like a peppercorn) Earth distance: 149,600,000 km x scale = 32.2 meters Jupiter diameter: 142,984 km x scale = 3.08 cm (a large marble) Jupiter distance: 778,600,000 km x scale = 167.7 meters Neptune distance: 4,495,100,000 km x scale = 968 meters (nearly 1 km away)
Result: At this scale, inner planets fit in a building but outer planets span a neighborhood

Example 2: City-Wide Model with 1 Meter Sun

Create a scale model with a 1-meter Sun. How far away is Neptune?
Solution:
Scale factor: 100 cm / 1,392,700 km = 1:1,392,700,000 Earth diameter: 12,756 km x scale = 0.916 cm (a small marble) Earth distance: 149,600,000 km x scale = 107.4 meters Jupiter: 10.27 cm diameter at 559 meters Saturn: 8.66 cm diameter at 1,029 meters Neptune: 3.56 cm at 3,228 meters (3.2 km away) Proxima Centauri: 27,320 km away
Result: With a 1-meter Sun, Neptune is 3.2 km away and the nearest star is 27,320 km distant
Expert Insights

Background & Theory

The Solar System Scale Model Calculator applies the following established principles and formulas. Astronomy and space science rely on a set of precisely defined physical relationships that allow distances, sizes, motions, and energies of celestial objects to be calculated from observational data. Kepler's three laws of planetary motion, derived empirically in the early seventeenth century, describe elliptical orbits, equal areas swept in equal times, and the harmonic law Tยฒ = aยณ, where T is the orbital period in Earth years and a is the semi-major axis in astronomical units (AU). This relationship holds for any object orbiting the Sun and can be generalized using Newton's law of gravitation. Distances in astronomy are expressed in multiple units: one light-year equals approximately 9.461 ร— 10ยนโต meters, one parsec equals 3.086 ร— 10ยนโถ meters or about 3.26 light-years, defined as the distance at which one AU subtends one arcsecond of parallax. Angular size is calculated as ฮธ = 206,265 ร— (d / D) arcseconds, where d is the physical diameter and D is the distance. The stellar magnitude system uses Pogson's formula: m1 โˆ’ m2 = โˆ’2.5 ร— log10(F1 / F2), where F represents flux. Each magnitude step corresponds to a flux ratio of approximately 2.512, meaning a first-magnitude star is 100 times brighter than a sixth-magnitude star. Hubble's Law relates recessional velocity to distance: v = Hโ‚€d, where the Hubble constant Hโ‚€ is approximately 70 km/s/Mpc. Escape velocity from any body is given by v = โˆš(2GM/r), yielding 11.2 km/s for Earth. Orbital period for a circular orbit follows T = 2ฯ€โˆš(rยณ/GM). Luminosity and distance are linked by the inverse square law: F = L / (4ฯ€dยฒ). Stars are classified by spectral type using the mnemonic OBAFGKM, corresponding to surface temperatures from approximately 30,000 K (O-type) to under 3,500 K (M-type). Each type reflects characteristic absorption spectra tied to ionization states of elements in the stellar photosphere.

History

The history behind the Solar System Scale Model Calculator traces back through the following developments. The history of astronomy is one of progressive scale โ€” each era expanding humanity's conception of the universe's size and structure. The Copernican revolution of 1543, when Nicolaus Copernicus published De revolutionibus orbium coelestium, displaced Earth from the center of the cosmos and placed the Sun at the center of the planetary system. Decades later, Galileo Galilei turned a Dutch-invented telescope toward the sky in 1609, discovering the moons of Jupiter, the phases of Venus, and the cratered surface of the Moon โ€” observations that provided compelling evidence for the heliocentric model and led to his conflict with the Catholic Church. Johannes Kepler, working from Tycho Brahe's meticulous naked-eye observations, derived his three laws of planetary motion between 1609 and 1619. Isaac Newton unified celestial and terrestrial mechanics with his law of universal gravitation in 1687, explaining the cause behind Kepler's empirical laws and enabling precise prediction of planetary positions. The eighteenth and nineteenth centuries brought systematic sky surveys, stellar parallax measurements, and the discovery that the Milky Way is itself a galaxy among many. Edwin Hubble's 1929 observations using the 100-inch Hooker Telescope at Mount Wilson demonstrated that galaxies are receding from us at velocities proportional to their distance โ€” the first direct evidence for an expanding universe and the empirical basis for Big Bang cosmology. NASA was founded in 1958 following the Sputnik shock, and the Apollo 11 mission landed humans on the Moon on July 20, 1969. The Hubble Space Telescope, launched in 1990, revolutionized observational astronomy by operating above Earth's atmosphere and producing imagery from ultraviolet to near-infrared wavelengths. The first confirmed exoplanet around a Sun-like star was detected in 1995 by Michel Mayor and Didier Queloz using the radial velocity method. The James Webb Space Telescope, launched in December 2021 and fully operational by 2022, extended infrared observations to probe the earliest galaxies formed after the Big Bang.

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Frequently Asked Questions

Solar system scale models are extremely challenging because the vast differences in scale between planet sizes and orbital distances make it nearly impossible to represent both accurately in the same model. If you make the Sun the size of a basketball (about 24 cm), Earth would be a tiny grain of sand just 2.2 mm across, located 26 meters away. Jupiter would be a marble-sized sphere roughly 2.5 cm wide but placed 134 meters from the basketball. Neptune would be over 770 meters away. Most classroom models cheat by using different scales for size and distance, which gives a completely misleading picture of how empty the solar system actually is.
For a classroom solar system scale model, a Sun diameter of 20 to 30 centimeters works well for demonstrating planet sizes, though the distances will far exceed the room. At 20 cm, Earth becomes about 1.8 mm and fits inside the classroom at about 21.5 meters away. However, Jupiter would need to be 2 cm across and positioned 112 meters away, while Neptune would be almost 650 meters from the Sun. For a model that fits in a single room showing both sizes and distances, you would need the Sun to be approximately 1 to 2 millimeters, making planets essentially invisible to the naked eye. This fundamental tradeoff is what makes solar system models so instructive.
If you scale the solar system to fit the inner planets on a standard American football field of 100 yards (91.4 meters), the Sun would be about 1.3 cm in diameter placed at one end zone. Mercury would be a barely visible speck 0.045 mm across at the 3.5 yard line. Venus at the 6.6 yard line would be 0.11 mm, and Earth at the 9.1 yard line would be 0.12 mm. Mars would sit at about the 13.9 yard line at 0.065 mm. However, Jupiter would need to be at about the 47.5 yard line at 1.37 mm, and Neptune would be far beyond the field at roughly 275 yards away. The actual model demonstrates just how close together the inner planets cluster compared to the vast outer solar system.
A properly scaled solar system model teaches one of the most profound lessons in astronomy: space is overwhelmingly empty. Even within our own solar system, the planets are separated by enormous voids. If you could drive a car at highway speed from the Sun to Neptune, the trip would take over 5,000 years. The model also reveals how small the planets are compared to the Sun, which contains 99.86 percent of the solar system total mass. Students are often shocked to discover that Earth is essentially invisible at many common model scales. This visceral understanding of cosmic distances is difficult to convey through numbers alone, making scale models one of the most effective teaching tools in astronomy education.
The scale factor for a solar system model is calculated by dividing your chosen model Sun diameter by the actual Sun diameter of 1,392,700 kilometers. For example, if you want the Sun to be 30 cm, the scale factor is 30 divided by 1,392,700,000 (in centimeters) which equals approximately 1 to 4.64 billion. Once you have this scale factor, multiply any real solar system measurement by it to get the model equivalent. Earth real diameter of 12,756 km becomes 12,756,000,000 cm times the scale factor, yielding approximately 0.275 cm or about 2.75 mm. The same factor applies to distances: Earth is 149,600,000 km from the Sun, which scales to roughly 32.2 meters in the model.
Including the nearest star, Proxima Centauri, in a solar system scale model dramatically illustrates interstellar distances. Proxima Centauri is 4.024 light-years or approximately 38 trillion kilometers from the Sun. In a model with a 30 cm Sun, Proxima Centauri would be placed approximately 8,200 kilometers away, roughly the distance from New York to Tokyo. Even in a model where the Sun is only 1 millimeter across, the nearest star would still be over 27 kilometers away. This comparison powerfully demonstrates why interstellar travel is such an enormous engineering challenge and why even our fastest spacecraft would take tens of thousands of years to reach the nearest star system.
Educational Note: This calculator is provided for educational and informational purposes. Results are based on the formulas and inputs provided. Always verify important calculations independently. NovaCalculator processes calculator inputs client-side; optional analytics follow visitor consent settings.Reviewed by: NovaCalculator Mathematics Team โ€” Verified against standard mathematical and scientific references. Last reviewed: December 2025. ยฉ 2024โ€“2026 NovaCalculator.

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Formula

Scaled Size = Real Size x (Model Sun Diameter / 1,392,700 km)

The scale factor is determined by dividing your chosen model Sun diameter by the real Sun diameter (1,392,700 km). This same factor is applied uniformly to all planet diameters and orbital distances to maintain correct proportions throughout the model.

Worked Examples

Example 1: Classroom Model with 30 cm Sun

Problem: Build a solar system scale model with the Sun represented by a 30 cm ball. What are the scaled planet sizes and distances?

Solution: Scale factor: 30 cm / 1,392,700 km = 1:4,642,333,333\nEarth diameter: 12,756 km x scale = 0.275 cm (2.75 mm, like a peppercorn)\nEarth distance: 149,600,000 km x scale = 32.2 meters\nJupiter diameter: 142,984 km x scale = 3.08 cm (a large marble)\nJupiter distance: 778,600,000 km x scale = 167.7 meters\nNeptune distance: 4,495,100,000 km x scale = 968 meters (nearly 1 km away)

Result: At this scale, inner planets fit in a building but outer planets span a neighborhood

Example 2: City-Wide Model with 1 Meter Sun

Problem: Create a scale model with a 1-meter Sun. How far away is Neptune?

Solution: Scale factor: 100 cm / 1,392,700 km = 1:1,392,700,000\nEarth diameter: 12,756 km x scale = 0.916 cm (a small marble)\nEarth distance: 149,600,000 km x scale = 107.4 meters\nJupiter: 10.27 cm diameter at 559 meters\nSaturn: 8.66 cm diameter at 1,029 meters\nNeptune: 3.56 cm at 3,228 meters (3.2 km away)\nProxima Centauri: 27,320 km away

Result: With a 1-meter Sun, Neptune is 3.2 km away and the nearest star is 27,320 km distant

Frequently Asked Questions

Why are solar system scale models so hard to build?

Solar system scale models are extremely challenging because the vast differences in scale between planet sizes and orbital distances make it nearly impossible to represent both accurately in the same model. If you make the Sun the size of a basketball (about 24 cm), Earth would be a tiny grain of sand just 2.2 mm across, located 26 meters away. Jupiter would be a marble-sized sphere roughly 2.5 cm wide but placed 134 meters from the basketball. Neptune would be over 770 meters away. Most classroom models cheat by using different scales for size and distance, which gives a completely misleading picture of how empty the solar system actually is.

What is the best Sun size for a classroom scale model?

For a classroom solar system scale model, a Sun diameter of 20 to 30 centimeters works well for demonstrating planet sizes, though the distances will far exceed the room. At 20 cm, Earth becomes about 1.8 mm and fits inside the classroom at about 21.5 meters away. However, Jupiter would need to be 2 cm across and positioned 112 meters away, while Neptune would be almost 650 meters from the Sun. For a model that fits in a single room showing both sizes and distances, you would need the Sun to be approximately 1 to 2 millimeters, making planets essentially invisible to the naked eye. This fundamental tradeoff is what makes solar system models so instructive.

How far apart would planets be in a football field scale model?

If you scale the solar system to fit the inner planets on a standard American football field of 100 yards (91.4 meters), the Sun would be about 1.3 cm in diameter placed at one end zone. Mercury would be a barely visible speck 0.045 mm across at the 3.5 yard line. Venus at the 6.6 yard line would be 0.11 mm, and Earth at the 9.1 yard line would be 0.12 mm. Mars would sit at about the 13.9 yard line at 0.065 mm. However, Jupiter would need to be at about the 47.5 yard line at 1.37 mm, and Neptune would be far beyond the field at roughly 275 yards away. The actual model demonstrates just how close together the inner planets cluster compared to the vast outer solar system.

What does a solar system scale model teach us about space?

A properly scaled solar system model teaches one of the most profound lessons in astronomy: space is overwhelmingly empty. Even within our own solar system, the planets are separated by enormous voids. If you could drive a car at highway speed from the Sun to Neptune, the trip would take over 5,000 years. The model also reveals how small the planets are compared to the Sun, which contains 99.86 percent of the solar system total mass. Students are often shocked to discover that Earth is essentially invisible at many common model scales. This visceral understanding of cosmic distances is difficult to convey through numbers alone, making scale models one of the most effective teaching tools in astronomy education.

How do you calculate the scale factor for a model?

The scale factor for a solar system model is calculated by dividing your chosen model Sun diameter by the actual Sun diameter of 1,392,700 kilometers. For example, if you want the Sun to be 30 cm, the scale factor is 30 divided by 1,392,700,000 (in centimeters) which equals approximately 1 to 4.64 billion. Once you have this scale factor, multiply any real solar system measurement by it to get the model equivalent. Earth real diameter of 12,756 km becomes 12,756,000,000 cm times the scale factor, yielding approximately 0.275 cm or about 2.75 mm. The same factor applies to distances: Earth is 149,600,000 km from the Sun, which scales to roughly 32.2 meters in the model.

Where does the nearest star fit in a solar system scale model?

Including the nearest star, Proxima Centauri, in a solar system scale model dramatically illustrates interstellar distances. Proxima Centauri is 4.024 light-years or approximately 38 trillion kilometers from the Sun. In a model with a 30 cm Sun, Proxima Centauri would be placed approximately 8,200 kilometers away, roughly the distance from New York to Tokyo. Even in a model where the Sun is only 1 millimeter across, the nearest star would still be over 27 kilometers away. This comparison powerfully demonstrates why interstellar travel is such an enormous engineering challenge and why even our fastest spacecraft would take tens of thousands of years to reach the nearest star system.

References

Reviewed by Daniel Agrici, Founder & Lead Developer ยท Editorial policy