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Satellite Speed Calculator

Calculate the orbital speed of a satellite at any altitude above Earth. Enter values for instant results with step-by-step formulas.

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Astronomy & Space Science

Satellite Speed Calculator

Calculate the orbital speed of a satellite at any altitude above Earth, Moon, Mars, or Jupiter. Find orbital period, escape velocity, and gravitational acceleration.

Last updated: December 2025Reviewed by NovaCalculator Mathematics Team

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Orbital Speed around Earth
27,604 km/h
7,667.8 m/s | 17,152.4 mph | Mach 22.4
Orbital Period
1h 32m 34s
92.6 min
Orbits Per Day
15.55
Circumference
42,593.7 km
Escape Velocity
39,038 km/h
10,843.9 m/s
Gravity at Altitude
8.6731 m/s2
88.3% of surface gravity

Orbital Parameters

Altitude408.0 km
Orbital Radius6,779 km
Surface Gravity9.8195 m/s2
Specific Orbital Energy-29.40 MJ/kg
Geostationary Altitude35,869 km
Your Result
Speed: 27604.0 km/h (7667.8 m/s) | Period: 1h 32m 34s | Escape: 39038.0 km/h
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Understand the Math

Formula

v = sqrt(GM/r)

Orbital speed v equals the square root of the gravitational constant G times the central body mass M divided by the orbital radius r (center of body to satellite). The orbital period T = 2*pi*r/v. Escape velocity = sqrt(2) times the orbital speed.

Last reviewed: December 2025

Worked Examples

Example 1: International Space Station Orbital Speed

Calculate the orbital speed and period of the ISS at 408 km altitude above Earth.
Solution:
G = 6.674 x 10^-11, M(Earth) = 5.972 x 10^24 kg r = 6,371,000 + 408,000 = 6,779,000 m v = sqrt(GM/r) = sqrt(6.674e-11 x 5.972e24 / 6,779,000) v = sqrt(5.878e7) = 7,667 m/s = 27,601 km/h Period = 2*pi*r/v = 2 x 3.14159 x 6,779,000 / 7,667 T = 5,553 seconds = 92 minutes 33 seconds Orbits per day = 86,400 / 5,553 = 15.56
Result: Speed: 7,667 m/s (27,601 km/h) | Period: 92.5 min | 15.56 orbits/day

Example 2: Mars Reconnaissance Orbiter

Calculate the orbital speed of a satellite at 300 km altitude above Mars (M = 6.417 x 10^23 kg, R = 3,389.5 km).
Solution:
r = 3,389,500 + 300,000 = 3,689,500 m v = sqrt(GM/r) = sqrt(6.674e-11 x 6.417e23 / 3,689,500) v = sqrt(1.160e7) = 3,406 m/s = 12,262 km/h Period = 2*pi*r/v = 2 x 3.14159 x 3,689,500 / 3,406 T = 6,806 seconds = 113 minutes 26 seconds
Result: Speed: 3,406 m/s (12,262 km/h) | Period: 113.4 min | 12.7 orbits/day
Expert Insights

Background & Theory

The Satellite Speed Calculator applies the following established principles and formulas. Astronomy and space science rely on a set of precisely defined physical relationships that allow distances, sizes, motions, and energies of celestial objects to be calculated from observational data. Kepler's three laws of planetary motion, derived empirically in the early seventeenth century, describe elliptical orbits, equal areas swept in equal times, and the harmonic law Tยฒ = aยณ, where T is the orbital period in Earth years and a is the semi-major axis in astronomical units (AU). This relationship holds for any object orbiting the Sun and can be generalized using Newton's law of gravitation. Distances in astronomy are expressed in multiple units: one light-year equals approximately 9.461 ร— 10ยนโต meters, one parsec equals 3.086 ร— 10ยนโถ meters or about 3.26 light-years, defined as the distance at which one AU subtends one arcsecond of parallax. Angular size is calculated as ฮธ = 206,265 ร— (d / D) arcseconds, where d is the physical diameter and D is the distance. The stellar magnitude system uses Pogson's formula: m1 โˆ’ m2 = โˆ’2.5 ร— log10(F1 / F2), where F represents flux. Each magnitude step corresponds to a flux ratio of approximately 2.512, meaning a first-magnitude star is 100 times brighter than a sixth-magnitude star. Hubble's Law relates recessional velocity to distance: v = Hโ‚€d, where the Hubble constant Hโ‚€ is approximately 70 km/s/Mpc. Escape velocity from any body is given by v = โˆš(2GM/r), yielding 11.2 km/s for Earth. Orbital period for a circular orbit follows T = 2ฯ€โˆš(rยณ/GM). Luminosity and distance are linked by the inverse square law: F = L / (4ฯ€dยฒ). Stars are classified by spectral type using the mnemonic OBAFGKM, corresponding to surface temperatures from approximately 30,000 K (O-type) to under 3,500 K (M-type). Each type reflects characteristic absorption spectra tied to ionization states of elements in the stellar photosphere.

History

The history behind the Satellite Speed Calculator traces back through the following developments. The history of astronomy is one of progressive scale โ€” each era expanding humanity's conception of the universe's size and structure. The Copernican revolution of 1543, when Nicolaus Copernicus published De revolutionibus orbium coelestium, displaced Earth from the center of the cosmos and placed the Sun at the center of the planetary system. Decades later, Galileo Galilei turned a Dutch-invented telescope toward the sky in 1609, discovering the moons of Jupiter, the phases of Venus, and the cratered surface of the Moon โ€” observations that provided compelling evidence for the heliocentric model and led to his conflict with the Catholic Church. Johannes Kepler, working from Tycho Brahe's meticulous naked-eye observations, derived his three laws of planetary motion between 1609 and 1619. Isaac Newton unified celestial and terrestrial mechanics with his law of universal gravitation in 1687, explaining the cause behind Kepler's empirical laws and enabling precise prediction of planetary positions. The eighteenth and nineteenth centuries brought systematic sky surveys, stellar parallax measurements, and the discovery that the Milky Way is itself a galaxy among many. Edwin Hubble's 1929 observations using the 100-inch Hooker Telescope at Mount Wilson demonstrated that galaxies are receding from us at velocities proportional to their distance โ€” the first direct evidence for an expanding universe and the empirical basis for Big Bang cosmology. NASA was founded in 1958 following the Sputnik shock, and the Apollo 11 mission landed humans on the Moon on July 20, 1969. The Hubble Space Telescope, launched in 1990, revolutionized observational astronomy by operating above Earth's atmosphere and producing imagery from ultraviolet to near-infrared wavelengths. The first confirmed exoplanet around a Sun-like star was detected in 1995 by Michel Mayor and Didier Queloz using the radial velocity method. The James Webb Space Telescope, launched in December 2021 and fully operational by 2022, extended infrared observations to probe the earliest galaxies formed after the Big Bang.

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Frequently Asked Questions

The orbital speed of a satellite is calculated using the vis-viva equation simplified for circular orbits: v = sqrt(GM/r), where G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), M is the mass of the central body (5.972 x 10^24 kg for Earth), and r is the orbital radius measured from the center of the body (Earth's radius plus altitude). For the International Space Station at 408 km altitude, r = 6,371 + 408 = 6,779 km = 6,779,000 m. This gives v = sqrt(6.674e-11 x 5.972e24 / 6,779,000) = 7,661 m/s or about 27,580 km/h. The key insight is that orbital speed depends only on altitude and the central body's mass, not on the satellite's own mass.
Escape velocity is the minimum speed an object must reach to break free from a celestial body's gravitational pull without further propulsion. It is calculated as v_esc = sqrt(2GM/r), which is exactly sqrt(2) (approximately 1.414) times the circular orbital speed at the same altitude. For Earth's surface, escape velocity is about 11,186 m/s (40,270 km/h), while orbital speed at the surface would theoretically be 7,910 m/s. At the ISS altitude of 408 km, escape velocity drops to about 10,834 m/s. This means a satellite already in orbit needs to increase its speed by only about 41.4% to escape the planet entirely. This mathematical relationship holds true for any altitude around any gravitationally bound body.
Low Earth Orbit (LEO) is 200-2,000 km altitude with 90-minute periods and is used for the ISS and imaging satellites. Medium Earth Orbit (MEO) at 2,000-35,786 km is used for GPS. Geostationary Orbit (GEO) at 35,786 km matches Earth's rotation for communication satellites. Sun-synchronous orbits pass over areas at the same local time.
You may use the results for reference and educational purposes. For professional reports, academic papers, or critical decisions, we recommend verifying outputs against peer-reviewed sources or consulting a qualified expert in the relevant field.
All calculations use established mathematical formulas and are performed with high-precision arithmetic. Results are accurate to the precision shown. For critical decisions in finance, medicine, or engineering, always verify results with a qualified professional.
No. All calculations run entirely in your browser using JavaScript. No data you enter is ever transmitted to any server or stored anywhere. Your inputs remain completely private.
Educational Note: This calculator is provided for educational and informational purposes. Results are based on the formulas and inputs provided. Always verify important calculations independently. NovaCalculator processes calculator inputs client-side; optional analytics follow visitor consent settings.Reviewed by: NovaCalculator Mathematics Team โ€” Verified against standard mathematical and scientific references. Last reviewed: December 2025. ยฉ 2024โ€“2026 NovaCalculator.

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Formula

v = sqrt(GM/r)

Orbital speed v equals the square root of the gravitational constant G times the central body mass M divided by the orbital radius r (center of body to satellite). The orbital period T = 2*pi*r/v. Escape velocity = sqrt(2) times the orbital speed.

Worked Examples

Example 1: International Space Station Orbital Speed

Problem: Calculate the orbital speed and period of the ISS at 408 km altitude above Earth.

Solution: G = 6.674 x 10^-11, M(Earth) = 5.972 x 10^24 kg\nr = 6,371,000 + 408,000 = 6,779,000 m\nv = sqrt(GM/r) = sqrt(6.674e-11 x 5.972e24 / 6,779,000)\nv = sqrt(5.878e7) = 7,667 m/s = 27,601 km/h\nPeriod = 2*pi*r/v = 2 x 3.14159 x 6,779,000 / 7,667\nT = 5,553 seconds = 92 minutes 33 seconds\nOrbits per day = 86,400 / 5,553 = 15.56

Result: Speed: 7,667 m/s (27,601 km/h) | Period: 92.5 min | 15.56 orbits/day

Example 2: Mars Reconnaissance Orbiter

Problem: Calculate the orbital speed of a satellite at 300 km altitude above Mars (M = 6.417 x 10^23 kg, R = 3,389.5 km).

Solution: r = 3,389,500 + 300,000 = 3,689,500 m\nv = sqrt(GM/r) = sqrt(6.674e-11 x 6.417e23 / 3,689,500)\nv = sqrt(1.160e7) = 3,406 m/s = 12,262 km/h\nPeriod = 2*pi*r/v = 2 x 3.14159 x 3,689,500 / 3,406\nT = 6,806 seconds = 113 minutes 26 seconds

Result: Speed: 3,406 m/s (12,262 km/h) | Period: 113.4 min | 12.7 orbits/day

Frequently Asked Questions

How is the orbital speed of a satellite calculated?

The orbital speed of a satellite is calculated using the vis-viva equation simplified for circular orbits: v = sqrt(GM/r), where G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), M is the mass of the central body (5.972 x 10^24 kg for Earth), and r is the orbital radius measured from the center of the body (Earth's radius plus altitude). For the International Space Station at 408 km altitude, r = 6,371 + 408 = 6,779 km = 6,779,000 m. This gives v = sqrt(6.674e-11 x 5.972e24 / 6,779,000) = 7,661 m/s or about 27,580 km/h. The key insight is that orbital speed depends only on altitude and the central body's mass, not on the satellite's own mass.

What is escape velocity and how does it relate to orbital speed?

Escape velocity is the minimum speed an object must reach to break free from a celestial body's gravitational pull without further propulsion. It is calculated as v_esc = sqrt(2GM/r), which is exactly sqrt(2) (approximately 1.414) times the circular orbital speed at the same altitude. For Earth's surface, escape velocity is about 11,186 m/s (40,270 km/h), while orbital speed at the surface would theoretically be 7,910 m/s. At the ISS altitude of 408 km, escape velocity drops to about 10,834 m/s. This means a satellite already in orbit needs to increase its speed by only about 41.4% to escape the planet entirely. This mathematical relationship holds true for any altitude around any gravitationally bound body.

How are satellite orbits classified?

Low Earth Orbit (LEO) is 200-2,000 km altitude with 90-minute periods and is used for the ISS and imaging satellites. Medium Earth Orbit (MEO) at 2,000-35,786 km is used for GPS. Geostationary Orbit (GEO) at 35,786 km matches Earth's rotation for communication satellites. Sun-synchronous orbits pass over areas at the same local time.

Can I use the results for professional or academic purposes?

You may use the results for reference and educational purposes. For professional reports, academic papers, or critical decisions, we recommend verifying outputs against peer-reviewed sources or consulting a qualified expert in the relevant field.

What inputs do I need to use Satellite Speed Calculator accurately?

Each field is labelled with the required unit (metric or imperial). Gather your source values before starting โ€” for example, a weight measurement in kilograms, a distance in metres, or a dollar amount โ€” and enter them exactly as measured. The formula section on this page lists every variable and explains what each represents.

Does Satellite Speed Calculator work offline?

Once the page is loaded, the calculation logic runs entirely in your browser. If you have already opened the page, most calculators will continue to work even if your internet connection is lost, since no server requests are needed for computation.

References

Reviewed by Daniel Agrici, Founder & Lead Developer ยท Editorial policy