Hohmann Transfer Calculator
Calculate delta-v requirements for a Hohmann transfer orbit between two circular orbits.
Hohmann Transfer Calculator
Calculator
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Formula: delta-v_total = |v_periapsis - v1| + |v2 - v_apoapsis|
Worked example โ Total delta-v: 3.980 km/s | Transfer time: ~5.3 hours
Formula
delta-v_total = |v_periapsis - v1| + |v2 - v_apoapsis|
Where v1 and v2 are circular orbit velocities at r1 and r2, v_periapsis and v_apoapsis are velocities on the transfer ellipse at closest and farthest points, computed using the vis-viva equation: v = sqrt(mu * (2/r - 1/a)).
Worked Examples
Example 1: LEO to Geostationary Orbit
Problem:Calculate the delta-v for a Hohmann transfer from a 300 km LEO (r = 6,678 km) to geostationary orbit (r = 42,164 km) around Earth (mu = 398,600 km^3/s^2).
Solution:v1 = sqrt(398600/6678) = 7.726 km/s v2 = sqrt(398600/42164) = 3.075 km/s a_transfer = (6678+42164)/2 = 24421 km v_periapsis = sqrt(398600*(2/6678-1/24421)) = 10.252 km/s v_apoapsis = sqrt(398600*(2/42164-1/24421)) = 1.621 km/s dV1 = 10.252-7.726 = 2.526 km/s dV2 = 3.075-1.621 = 1.454 km/s Total = 3.980 km/s
Result:Total delta-v: 3.980 km/s | Transfer time: ~5.3 hours
Example 2: Earth to Mars Hohmann Transfer
Problem:Calculate the heliocentric Hohmann transfer from Earth orbit (r = 149,598,023 km) to Mars orbit (r = 227,939,366 km) with Sun mu = 1.327e11 km^3/s^2.
Solution:v_Earth = sqrt(1.327e11/149598023) = 29.78 km/s v_Mars = sqrt(1.327e11/227939366) = 24.13 km/s a_transfer = (149598023+227939366)/2 = 188768694.5 km v_departure = sqrt(mu*(2/r1-1/a)) = 32.73 km/s v_arrival = sqrt(mu*(2/r2-1/a)) = 21.48 km/s dV1 = 32.73-29.78 = 2.95 km/s dV2 = 24.13-21.48 = 2.65 km/s
Result:Total delta-v: ~5.60 km/s | Transfer time: ~259 days
Frequently Asked Questions
What is a Hohmann transfer orbit and why is it important?
A Hohmann transfer orbit is the most fuel-efficient two-impulse maneuver to move a spacecraft between two circular orbits in the same plane. Named after Walter Hohmann who proposed it in 1925, this transfer uses an elliptical orbit that is tangent to both the inner and outer circular orbits. The spacecraft fires its engines at periapsis to enter the transfer ellipse and again at apoapsis to circularize into the target orbit. While it requires the least delta-v of any two-burn transfer, it takes the longest time. This trade-off between fuel efficiency and transfer time makes it fundamental to mission planning for satellite deployment, interplanetary travel, and orbital rendezvous.
What does delta-v mean and how is it calculated for a Hohmann transfer?
Delta-v (change in velocity) is the key metric for orbital maneuvers, representing how much a spacecraft must change its velocity to perform a specific maneuver. For a Hohmann transfer, two delta-v burns are needed. The first burn at periapsis accelerates the spacecraft from its circular orbit velocity to the transfer ellipse velocity. The second burn at apoapsis accelerates it from the ellipse velocity to the target circular orbit velocity. The total delta-v is the sum of both burns. Delta-v directly determines fuel requirements through the Tsiolkovsky rocket equation, making it the primary measure of maneuver cost in astrodynamics. Lower delta-v means less fuel needed.
How long does a Hohmann transfer take compared to other methods?
A Hohmann transfer takes exactly half the orbital period of the transfer ellipse, calculated as pi times the square root of the semi-major axis cubed divided by the gravitational parameter. For a LEO to GEO transfer, this is approximately 5.3 hours. For an Earth-to-Mars heliocentric transfer, it takes about 259 days. While the Hohmann transfer is the slowest two-burn option, it uses the minimum delta-v. Faster alternatives include bi-elliptic transfers for very large orbit ratio changes, and direct high-energy transfers that trade fuel for speed. Spacecraft with continuous low-thrust propulsion like ion engines use spiral trajectories instead.
When is a bi-elliptic transfer more efficient than a Hohmann transfer?
A bi-elliptic transfer becomes more fuel-efficient than a Hohmann transfer when the ratio of the outer orbit radius to the inner orbit radius exceeds approximately 11.94. In a bi-elliptic transfer, the spacecraft first enters a highly elliptical orbit that goes far beyond the target orbit, then performs a second burn at apoapsis to adjust, and a third burn to circularize at the target orbit. Despite requiring three burns and taking much longer, the total delta-v can be less than the Hohmann two-burn approach for large orbit ratio changes. This scenario is relatively rare in practical applications but important for theoretical understanding of orbital mechanics optimization.
Can Hohmann transfers be used for interplanetary travel?
Yes, Hohmann transfers are the foundational concept for interplanetary mission planning. For travel between planets, the two circular orbits represent the planetary orbits around the Sun, and the gravitational parameter is that of the Sun. The transfer ellipse connects the departure planet orbit to the arrival planet orbit. Real interplanetary missions use patched conic approximations that combine the Hohmann heliocentric transfer with hyperbolic escape and capture trajectories at each planet. Launch windows for Hohmann transfers occur at specific intervals called synodic periods when the planets are properly aligned. Most Mars missions use near-Hohmann trajectories, though gravity assists can reduce fuel requirements further.
What is the vis-viva equation and why does every speed here depend on it?
Vis-viva states that v squared equals mu times the quantity 2 over r minus 1 over a, tying speed at any point to the current radius and the semi-major axis of the orbit. Set a equal to r and it collapses to the circular case sqrt(mu/r); let a grow without bound and it becomes the escape speed. Both transfer-ellipse velocities on this page come from it with a set to the mean of the two radii, and each burn is simply the difference between two vis-viva speeds at the same radius.
What is the standard gravitational parameter mu and why is it used instead of G and M?
Mu is the product of the gravitational constant and the central body mass, in units of km cubed per second squared: about 398,600 for Earth and 1.327 x 10^11 for the Sun. Spacecraft tracking and planetary ranging measure this product directly and to very high precision, whereas G itself is one of the least precisely known constants and the mass of a planet cannot be weighed separately. Using mu keeps the accuracy and removes an unnecessary division into two poorly separated quantities.
Why does a burn at periapsis raise the altitude on the opposite side of the orbit?
A prograde burn adds orbital energy, which raises the semi-major axis, but it barely moves the point where the burn occurred because the spacecraft is still passing through that same location at that instant. The extra speed carries it further out over the following half revolution, so the apoapsis 180 degrees away rises. That is why the Hohmann geometry is tangential: both burns are applied along the velocity vector, at the two points where the ellipse touches the circular orbits.
How do launch windows and phase angle work for an interplanetary Hohmann transfer?
The target must arrive at the transfer apoapsis exactly when the spacecraft does. Mars circles the Sun in about 687 days, so during a 259-day transfer it sweeps roughly 136 degrees, meaning it has to be about 44 degrees ahead of Earth at departure. That alignment repeats at the synodic period, given by one over the difference of the two orbital frequencies, which works out near 26 months for Earth and Mars and sets the familiar rhythm of Mars launch campaigns.
Why is a plane change combined with the apoapsis burn instead of performed separately?
Combining them adds the two velocity changes as vectors rather than as scalars. Arriving at geostationary radius on the transfer ellipse at 1.621 km/s and needing 3.075 km/s in a plane inclined 28.5 degrees away, the single combined burn is sqrt(1.621 squared plus 3.075 squared minus 2 x 1.621 x 3.075 x cos 28.5 degrees), about 1.82 km/s. Circularising first and then rotating the plane would cost roughly 1.45 plus 1.51, close to 2.97 km/s.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer ยท Editorial policy
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