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Orbital Period Calculator

Compute orbital period using validated scientific equations. See step-by-step derivations, unit analysis, and reference values.

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Astronomy & Space Science

Orbital Period Calculator

Calculate orbital periods using Kepler's Third Law. Find orbital velocity, periapsis, and apoapsis for planets, satellites, and exoplanets.

Last updated: December 2025Reviewed by NovaCalculator Mathematics Team

Calculator

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0 = circular, 0.0167 = Earth, 0.967 = Halley's Comet

Orbital Period
365.21 days
365.21 days | 8765.05 hours
Circular Velocity
29.79 km/s
V at Periapsis
30.29 km/s
V at Apoapsis
29.30 km/s
Periapsis Distance
0.9833 AU
Apoapsis Distance
1.0167 AU

Solar System Comparison

Mercury0.387 AU87.97 days
Venus0.723 AU224.7 days
Earth1 AU365.25 days
Mars1.524 AU687 days
Jupiter5.203 AU4332.6 days
Saturn9.537 AU10759 days
Your Result
Period: 365.21 days | Circular Velocity: 29.79 km/s | Periapsis: 0.9833 AU
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Understand the Math

Formula

T = 2 pi sqrt(a^3 / (G M))

Where T is the orbital period in seconds, a is the semi-major axis in meters, G is the gravitational constant (6.674 x 10^-11 m^3 kg^-1 s^-2), and M is the mass of the central body in kilograms. This is derived from Kepler's Third Law combined with Newton's law of gravitation.

Last reviewed: December 2025

Worked Examples

Example 1: Earth's Orbital Period

Calculate the orbital period of Earth orbiting the Sun at 1 AU (1.496 x 10^11 m) with the Sun's mass of 1.989 x 10^30 kg.
Solution:
T = 2 x pi x sqrt(a^3 / (G x M)) T = 2 x pi x sqrt((1.496e11)^3 / (6.674e-11 x 1.989e30)) T = 2 x pi x sqrt(3.348e33 / 1.327e20) T = 2 x pi x sqrt(2.524e13) T = 2 x pi x 5.024e6 T = 31,557,600 seconds = 365.25 days
Result: Orbital period: 365.25 days (1 year) confirming Kepler's Third Law

Example 2: ISS Orbital Period

The ISS orbits at 420 km altitude. With Earth's radius of 6,371 km and mass of 5.972 x 10^24 kg, calculate its orbital period.
Solution:
Semi-major axis = 6,371 + 420 = 6,791 km = 6,791,000 m T = 2 x pi x sqrt((6.791e6)^3 / (6.674e-11 x 5.972e24)) T = 2 x pi x sqrt(3.134e20 / 3.986e14) T = 2 x pi x sqrt(7.862e5) T = 2 x pi x 886.7 T = 5,571 seconds = 92.8 minutes
Result: ISS orbital period: 92.8 minutes | Velocity: 7.66 km/s | ~15.5 orbits per day
Expert Insights

Background & Theory

The Orbital Period Calculator applies the following established principles and formulas. Astronomy and space science rely on a set of precisely defined physical relationships that allow distances, sizes, motions, and energies of celestial objects to be calculated from observational data. Kepler's three laws of planetary motion, derived empirically in the early seventeenth century, describe elliptical orbits, equal areas swept in equal times, and the harmonic law Tยฒ = aยณ, where T is the orbital period in Earth years and a is the semi-major axis in astronomical units (AU). This relationship holds for any object orbiting the Sun and can be generalized using Newton's law of gravitation. Distances in astronomy are expressed in multiple units: one light-year equals approximately 9.461 ร— 10ยนโต meters, one parsec equals 3.086 ร— 10ยนโถ meters or about 3.26 light-years, defined as the distance at which one AU subtends one arcsecond of parallax. Angular size is calculated as ฮธ = 206,265 ร— (d / D) arcseconds, where d is the physical diameter and D is the distance. The stellar magnitude system uses Pogson's formula: m1 โˆ’ m2 = โˆ’2.5 ร— log10(F1 / F2), where F represents flux. Each magnitude step corresponds to a flux ratio of approximately 2.512, meaning a first-magnitude star is 100 times brighter than a sixth-magnitude star. Hubble's Law relates recessional velocity to distance: v = Hโ‚€d, where the Hubble constant Hโ‚€ is approximately 70 km/s/Mpc. Escape velocity from any body is given by v = โˆš(2GM/r), yielding 11.2 km/s for Earth. Orbital period for a circular orbit follows T = 2ฯ€โˆš(rยณ/GM). Luminosity and distance are linked by the inverse square law: F = L / (4ฯ€dยฒ). Stars are classified by spectral type using the mnemonic OBAFGKM, corresponding to surface temperatures from approximately 30,000 K (O-type) to under 3,500 K (M-type). Each type reflects characteristic absorption spectra tied to ionization states of elements in the stellar photosphere.

History

The history behind the Orbital Period Calculator traces back through the following developments. The history of astronomy is one of progressive scale โ€” each era expanding humanity's conception of the universe's size and structure. The Copernican revolution of 1543, when Nicolaus Copernicus published De revolutionibus orbium coelestium, displaced Earth from the center of the cosmos and placed the Sun at the center of the planetary system. Decades later, Galileo Galilei turned a Dutch-invented telescope toward the sky in 1609, discovering the moons of Jupiter, the phases of Venus, and the cratered surface of the Moon โ€” observations that provided compelling evidence for the heliocentric model and led to his conflict with the Catholic Church. Johannes Kepler, working from Tycho Brahe's meticulous naked-eye observations, derived his three laws of planetary motion between 1609 and 1619. Isaac Newton unified celestial and terrestrial mechanics with his law of universal gravitation in 1687, explaining the cause behind Kepler's empirical laws and enabling precise prediction of planetary positions. The eighteenth and nineteenth centuries brought systematic sky surveys, stellar parallax measurements, and the discovery that the Milky Way is itself a galaxy among many. Edwin Hubble's 1929 observations using the 100-inch Hooker Telescope at Mount Wilson demonstrated that galaxies are receding from us at velocities proportional to their distance โ€” the first direct evidence for an expanding universe and the empirical basis for Big Bang cosmology. NASA was founded in 1958 following the Sputnik shock, and the Apollo 11 mission landed humans on the Moon on July 20, 1969. The Hubble Space Telescope, launched in 1990, revolutionized observational astronomy by operating above Earth's atmosphere and producing imagery from ultraviolet to near-infrared wavelengths. The first confirmed exoplanet around a Sun-like star was detected in 1995 by Michel Mayor and Didier Queloz using the radial velocity method. The James Webb Space Telescope, launched in December 2021 and fully operational by 2022, extended infrared observations to probe the earliest galaxies formed after the Big Bang.

Key Features

  • Applies Kepler's third law to calculate the orbital period or semi-major axis of a body orbiting any central mass, supporting planets, moons, and artificial satellites.
  • Computes escape velocity for any celestial body given its mass and radius, allowing comparison across planets, moons, and hypothetical objects.
  • Converts distances between light-years, parsecs, and astronomical units, and calculates the travel time for light to cross those distances for quick cosmic scale comparisons.
  • Calculates apparent magnitude, absolute magnitude, and luminosity relationships using the distance modulus, enabling brightness comparisons between stars at different distances.
  • Uses Hubble's law to estimate the recession velocity of a galaxy from its distance or to back-calculate distance from observed redshift, with a configurable Hubble constant.
  • Computes the gravitational force between two celestial bodies using Newton's law of universal gravitation, with inputs for mass and separation distance.
  • Estimates the main-sequence lifetime of a star from its mass relative to the Sun, using the standard mass-luminosity scaling relation to indicate stellar longevity.
  • Calculates the minimum angular resolution of a telescope using the Rayleigh criterion and computes the angular diameter of an object given its physical size and distance.

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Frequently Asked Questions

Kepler's Third Law of Planetary Motion states that the square of a planet's orbital period is directly proportional to the cube of the semi-major axis of its orbit. Mathematically, T squared equals 4 pi squared times a cubed divided by G times M, where T is the orbital period, a is the semi-major axis (the average distance from the central body), G is the gravitational constant, and M is the mass of the central body. This elegant relationship means that if you know the distance of an orbiting body from its parent and the mass of the parent, you can calculate exactly how long one complete orbit takes. Johannes Kepler discovered this empirical relationship in 1619, and Isaac Newton later provided the theoretical foundation by deriving it from his law of universal gravitation, showing that it applies to any two gravitationally bound objects in the universe.
Orbital periods are fundamental to exoplanet detection through the transit method, where astronomers measure periodic dips in a star's brightness as a planet crosses in front of it. The time between transits directly gives the orbital period, and using Kepler's Third Law with the known stellar mass, scientists can calculate the planet's distance from its star. The Kepler Space Telescope discovered over 2,600 confirmed exoplanets using this technique. The radial velocity method also relies on orbital periods by detecting the periodic wobble of a star caused by an orbiting planet's gravitational pull. Shorter orbital periods are easier to detect because multiple transits can be observed in less time. This observational bias means that close-in hot Jupiters with periods of a few days were among the first exoplanets discovered, while detecting Earth-like planets with year-long periods requires years of continuous observation.
Satellite orbital periods around Earth depend entirely on their altitude above the surface, which determines the semi-major axis. Low Earth orbit satellites at 400 km altitude, like the International Space Station, complete one orbit in approximately 93 minutes traveling at 7.66 km/s. Medium Earth orbit GPS satellites at 20,200 km altitude have periods of about 12 hours. At exactly 35,786 km altitude, a satellite achieves geostationary orbit with a period matching Earth's 24-hour rotation, appearing stationary above a fixed point on the equator. This principle is used for communications and weather satellites. The Moon orbits at 384,400 km with a period of 27.3 days. For any circular orbit, doubling the altitude more than doubles the period because of the cube-root relationship in Kepler's law. No satellite can orbit below approximately 160 km altitude because atmospheric drag would quickly deorbit it.
Orbital velocity decreases with altitude: v = sqrt(GM/r), where G is the gravitational constant, M is Earth's mass, and r is orbital radius. Low Earth orbit (400 km) requires about 7.67 km/s. Geostationary orbit (35,786 km) requires only 3.07 km/s. Escape velocity from Earth's surface is 11.2 km/s.
You may use the results for reference and educational purposes. For professional reports, academic papers, or critical decisions, we recommend verifying outputs against peer-reviewed sources or consulting a qualified expert in the relevant field.
All calculations use established mathematical formulas and are performed with high-precision arithmetic. Results are accurate to the precision shown. For critical decisions in finance, medicine, or engineering, always verify results with a qualified professional.
Educational Note: This calculator is provided for educational and informational purposes. Results are based on the formulas and inputs provided. Always verify important calculations independently. NovaCalculator processes calculator inputs client-side; optional analytics follow visitor consent settings.Reviewed by: NovaCalculator Mathematics Team โ€” Verified against standard mathematical and scientific references. Last reviewed: December 2025. ยฉ 2024โ€“2026 NovaCalculator.

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Formula

T = 2 pi sqrt(a^3 / (G M))

Where T is the orbital period in seconds, a is the semi-major axis in meters, G is the gravitational constant (6.674 x 10^-11 m^3 kg^-1 s^-2), and M is the mass of the central body in kilograms. This is derived from Kepler's Third Law combined with Newton's law of gravitation.

Frequently Asked Questions

What is Kepler's Third Law and how does it calculate orbital period?

Kepler's Third Law of Planetary Motion states that the square of a planet's orbital period is directly proportional to the cube of the semi-major axis of its orbit. Mathematically, T squared equals 4 pi squared times a cubed divided by G times M, where T is the orbital period, a is the semi-major axis (the average distance from the central body), G is the gravitational constant, and M is the mass of the central body. This elegant relationship means that if you know the distance of an orbiting body from its parent and the mass of the parent, you can calculate exactly how long one complete orbit takes. Johannes Kepler discovered this empirical relationship in 1619, and Isaac Newton later provided the theoretical foundation by deriving it from his law of universal gravitation, showing that it applies to any two gravitationally bound objects in the universe.

How are orbital periods used to discover exoplanets?

Orbital periods are fundamental to exoplanet detection through the transit method, where astronomers measure periodic dips in a star's brightness as a planet crosses in front of it. The time between transits directly gives the orbital period, and using Kepler's Third Law with the known stellar mass, scientists can calculate the planet's distance from its star. The Kepler Space Telescope discovered over 2,600 confirmed exoplanets using this technique. The radial velocity method also relies on orbital periods by detecting the periodic wobble of a star caused by an orbiting planet's gravitational pull. Shorter orbital periods are easier to detect because multiple transits can be observed in less time. This observational bias means that close-in hot Jupiters with periods of a few days were among the first exoplanets discovered, while detecting Earth-like planets with year-long periods requires years of continuous observation.

What determines the orbital period of satellites around Earth?

Satellite orbital periods around Earth depend entirely on their altitude above the surface, which determines the semi-major axis. Low Earth orbit satellites at 400 km altitude, like the International Space Station, complete one orbit in approximately 93 minutes traveling at 7.66 km/s. Medium Earth orbit GPS satellites at 20,200 km altitude have periods of about 12 hours. At exactly 35,786 km altitude, a satellite achieves geostationary orbit with a period matching Earth's 24-hour rotation, appearing stationary above a fixed point on the equator. This principle is used for communications and weather satellites. The Moon orbits at 384,400 km with a period of 27.3 days. For any circular orbit, doubling the altitude more than doubles the period because of the cube-root relationship in Kepler's law. No satellite can orbit below approximately 160 km altitude because atmospheric drag would quickly deorbit it.

How do orbital velocities relate to altitude?

Orbital velocity decreases with altitude: v = sqrt(GM/r), where G is the gravitational constant, M is Earth's mass, and r is orbital radius. Low Earth orbit (400 km) requires about 7.67 km/s. Geostationary orbit (35,786 km) requires only 3.07 km/s. Escape velocity from Earth's surface is 11.2 km/s.

Is my data stored or sent to a server?

No. All calculations run entirely in your browser using JavaScript. No data you enter is ever transmitted to any server or stored anywhere. Your inputs remain completely private.

What inputs do I need to use Orbital Period Calculator accurately?

Each field is labelled with the required unit (metric or imperial). Gather your source values before starting โ€” for example, a weight measurement in kilograms, a distance in metres, or a dollar amount โ€” and enter them exactly as measured. The formula section on this page lists every variable and explains what each represents.

References

Reviewed by Daniel Agrici, Founder & Lead Developer ยท Editorial policy