Telescope Magnification by Eyepiece & Focal Length
Calculate telescope magnification from focal length and eyepiece focal length, plus the maximum useful magnification for your aperture.
Telescope Magnification by Eyepiece & Focal Length
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Formula: Magnification = Telescope Focal Length ÷ Eyepiece Focal Length
Worked example — 48× magnification, 4.17mm exit pupil — excellent for deep-sky observing
Formula
Magnification = Telescope Focal Length ÷ Eyepiece Focal Length
Divide the telescope's focal length (mm) by the eyepiece focal length (mm) to get magnification. Exit pupil = aperture ÷ magnification. Maximum useful magnification ≈ 2× aperture (mm). Limiting magnitude ≈ 2.7 + 5 × log₁₀(aperture mm).
Worked Examples
Example 1: 8-inch Dobsonian with 25mm Eyepiece
Problem:Calculate the magnification and exit pupil for a 200mm f/6 Dobsonian (1200mm FL) with a 25mm Plössl eyepiece.
Solution:Magnification = 1200 / 25 = 48× Exit pupil = 200 / 48 = 4.17mm True FOV ≈ 50° / 48 = 1.04° Max useful mag = 2 × 200 = 400×
Result:48× magnification, 4.17mm exit pupil — excellent for deep-sky observing
Example 2: Planetary Viewing at High Power
Problem:Same telescope with a 5mm eyepiece for planetary observation.
Solution:Magnification = 1200 / 5 = 240× Exit pupil = 200 / 240 = 0.83mm True FOV ≈ 50° / 240 = 0.21° Within max useful of 400×
Result:240× magnification, 0.83mm exit pupil — good for planets and Moon
Frequently Asked Questions
What is telescope magnification and how is it calculated?
Magnification (power) is the number of times larger an object appears through the telescope compared to the naked eye. It is calculated by dividing the telescope's focal length by the eyepiece's focal length: Magnification = Telescope FL ÷ Eyepiece FL. For example, a 1200mm telescope with a 25mm eyepiece gives 48× magnification. You can change magnification by swapping eyepieces.
What is the maximum useful magnification?
The maximum useful magnification is approximately 2× the aperture in millimeters (50× per inch). Beyond this, the image becomes dim and blurry due to diffraction limits. For a 200mm (8-inch) telescope, the max useful magnification is about 400×. Atmospheric seeing conditions often limit practical magnification to 200-300× regardless of telescope size.
What is exit pupil and why does it matter?
Exit pupil is the diameter of the light beam leaving the eyepiece, calculated as aperture ÷ magnification. It matters because the human pupil can only open to about 7mm in darkness (less with age). If the exit pupil exceeds your pupil size, light is wasted. An exit pupil of 2-4mm is ideal for most deep-sky viewing, while 0.5-1mm is better for planetary detail.
What is limiting magnitude?
Limiting magnitude is the faintest star magnitude visible through the telescope under ideal conditions. The naked eye can see to about magnitude 6. A 200mm telescope can theoretically reach magnitude 14.2, revealing objects about 1,900× fainter (8.2 magnitudes). The formula is: m = 2.7 + 5 × log₁₀(aperture in mm). Real-world limits are usually 1-2 magnitudes less due to light pollution and atmospheric conditions.
How do binocular numbers such as 10x50 relate to telescope magnification?
The first number is fixed magnification and the second is the aperture in millimetres, so 10x50 binoculars work at 10x with a 50mm objective. Every quantity on this page still applies: the exit pupil is 50 / 10 = 5mm, comfortably inside a dark-adapted pupil; light grasp is (50/7) squared, about 51 times the naked eye; the Dawes limit is 116 / 50 = 2.3 arcseconds; and the limiting magnitude is 2.7 + 5 log10(50), roughly 11.2. The maximum useful power for a 50mm objective is only about 100x, which is why 30x60 binoculars advertised at high power cannot deliver a usable image.
What is empty magnification and how do I recognize it?
Empty magnification is power that enlarges the image without revealing anything new. Past roughly 2× the aperture in millimeters, the Airy disk has already been blown up beyond what the eye can resolve, so extra power only spreads the same blur while the exit pupil shrinks and the view dims. The signs are clear: stars swell into soft discs, planetary detail turns mushy rather than sharper, floaters in your eye become visible, and every tremor of the mount is amplified. Drop back one eyepiece.
How do I work out which eyepiece focal length gives the power I want?
Rearrange the formula: eyepiece focal length = telescope focal length ÷ desired magnification. On a 1200mm telescope, 150× needs 1200 ÷ 150 = 8mm, while 60× needs 20mm. Then check the exit pupil, aperture ÷ magnification: at 150× on a 200mm aperture that is 1.33mm, comfortable for planetary work. Spacing neighboring eyepieces by roughly 1.4× to 1.5× in power avoids near-duplicate views, and a Barlow fills the gaps without buying more glass.
Why do two telescopes at the same magnification show different amounts of detail?
Because magnification only scales the image; aperture decides how much information is in it. A 60mm and a 200mm both working at 120× frame the same patch of sky, but the Dawes limit gives the small one 116 ÷ 60 = 1.93 arcseconds of resolution against 0.58 arcseconds for the large one. Light grasp scales with the square of diameter, so the 60mm collects about 74 times what the naked eye does and the 200mm about 816 times.
How does magnification affect image brightness?
Point sources and extended objects behave differently. A star remains essentially a point, so its brightness changes little as power rises. The Moon, planets and nebulae are extended, and their surface brightness falls with the square of magnification: double the power and each patch of the object is a quarter as bright, because the same light now covers four times the apparent area. That is why the sky background darkens usefully at high power for faint stars, while a nebula simply fades.
What is the minimum useful magnification and what happens below it?
Minimum useful power is about aperture ÷ 7, roughly 29× on a 200mm telescope, set by the 7mm limit of a fully dark-adapted pupil. Go lower and the exit pupil grows wider than your iris, so the outer part of the light cone never enters the eye and you are effectively observing with a smaller telescope. In a Newtonian or Schmidt-Cassegrain the shadow of the central obstruction can also appear as a dark blot in the middle of the field.
References
Background & Theory
History
Reviewed for accuracy by Daniel Agrici, Founder & Lead Developer · Editorial policy
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