Absolute Value Inequalities Calculator
Solve absolute value inequalities problems step-by-step with our free calculator. See formulas, worked examples, and clear explanations.
Formula
|ax + b| < c or |ax + b| > c
For less-than: convert to compound inequality -c < ax + b < c (bounded interval). For greater-than: split into ax + b > c OR ax + b < -c (two unbounded rays). The coefficient a, constant b, and right-hand side c determine the boundary points and interval width.
Worked Examples
Example 1: Solving |3x - 6| < 9
Problem: Find all values of x satisfying |3x - 6| < 9.
Solution: Convert to compound inequality: -9 < 3x - 6 < 9\nAdd 6 to all parts: -3 < 3x < 15\nDivide by 3: -1 < x < 5\nSolution in interval notation: (-1, 5)
Result: x is in the interval (-1, 5)
Example 2: Solving |2x + 1| >= 7
Problem: Find all values of x satisfying |2x + 1| >= 7.
Solution: Split into two cases:\nCase 1: 2x + 1 >= 7 => 2x >= 6 => x >= 3\nCase 2: 2x + 1 <= -7 => 2x <= -8 => x <= -4\nSolution: (-inf, -4] U [3, +inf)
Result: x <= -4 or x >= 3
Frequently Asked Questions
What is an absolute value inequality and how is it different from an equation?
An absolute value inequality involves an absolute value expression compared with a value using an inequality sign (such as less than or greater than), rather than an equals sign. While an absolute value equation like |ax + b| = c yields discrete point solutions, an inequality yields a continuous range or ranges of values. For less-than inequalities, the solution is a single bounded interval on the number line. For greater-than inequalities, the solution consists of two unbounded rays extending in opposite directions. Understanding this distinction is crucial for correctly interpreting and graphing solution sets in algebra.
How do you solve a less-than absolute value inequality?
To solve |ax + b| < c (where c is positive), you convert it into a compound inequality: -c < ax + b < c. This means the expression inside the absolute value must be between -c and c simultaneously. Then isolate x by subtracting b from all three parts and dividing by a (remembering to flip inequality signs if dividing by a negative number). The result is always a bounded interval. For example, |2x - 3| < 5 becomes -5 < 2x - 3 < 5, then -2 < 2x < 8, and finally -1 < x < 4, which is the open interval (-1, 4) on the number line.
What happens when an absolute value inequality has a negative right-hand side?
When the right-hand side is negative, the behavior depends on the inequality type. For |ax + b| < negative number, there is no solution because an absolute value is always non-negative, so it can never be less than a negative value. For |ax + b| > negative number, every real number is a solution because an absolute value is always greater than or equal to zero, which is always greater than any negative number. These special cases are important to recognize immediately because they require no algebraic manipulation and attempting to solve them normally can lead to incorrect or confusing results.
How do you express absolute value inequality solutions in interval notation?
Interval notation provides a compact way to describe solution sets. For bounded intervals from less-than inequalities, use parentheses for strict inequality and brackets for inclusive: (a, b) means a < x < b, while [a, b] means a <= x <= b. For unbounded intervals from greater-than inequalities, use the union symbol to join two rays: (-inf, a) union (b, +inf). Infinity always gets parentheses since it is not a number that can be reached or included. Mixed notation like (-inf, a] union [b, +inf) handles greater-than-or-equal-to cases. This notation is standard across mathematics and is essential for communicating solution sets precisely.
Can absolute value inequalities have no solution or all real numbers as solutions?
Yes, absolute value inequalities can produce these special solution sets beyond the standard interval results. The inequality |ax + b| < 0 has no solution since absolute values are always non-negative. Similarly, |ax + b| <= 0 has exactly one solution (when ax + b = 0). The inequality |ax + b| > 0 is satisfied by all real numbers except where ax + b = 0. The inequality |ax + b| >= 0 is satisfied by all real numbers without exception. Recognizing these cases quickly is a valuable algebra skill that saves significant time on homework, tests, and real-world applications.
How do you graph absolute value inequalities on a number line?
To graph absolute value inequality solutions on a number line, first solve the inequality to find the boundary points. For less-than inequalities yielding a bounded interval like -1 < x < 4, place open circles at -1 and 4 (or filled circles for less-than-or-equal) and shade the region between them. For greater-than inequalities yielding two rays like x < -1 or x > 4, place open circles at the boundary points and shade outward in both directions toward negative and positive infinity. The visual representation clearly shows whether the solution is a connected interval or two disconnected regions.